我想替换子icashier.alipay.com
列在df
url
icashier.alipay.com/catalog/2758186/detail.aspx
icashier.alipay.com/catalog/2758186/detail.aspx
icashier.alipay.com/catalog/2758186/detail.aspx
vk.com
到aliexpress.com
。
欲望输出
aliexpress.com/catalog/2758186/detail.aspx
aliexpress.com/catalog/2758186/detail.aspx
aliexpress.com/catalog/2758186/detail.aspx
vk.com
我尝试df['url'].replace('icashier.alipay.com', 'aliexpress.com', 'inplace=True')
但它返回empty dataframe
。
使用replace
用dict
更换和参数inplace=True
和regex=True
:
df['url'].replace({'icashier.alipay.com': 'aliexpress.com'}, inplace=True, regex=True)
print (df)
url
0 aliexpress.com/catalog/2758186/detail.aspx
1 aliexpress.com/catalog/2758186/detail.aspx
2 aliexpress.com/catalog/2758186/detail.aspx
3 vk.com
使用str.replace
更换子, replace
外观的完全匹配,除非你传递一个正则表达式模式和param regex=True
:
In [25]:
df['url'] = df['url'].str.replace('icashier.alipay.com', 'aliexpress.com')
df['url']
Out[25]:
0 aliexpress.com/catalog/2758186/detail.aspx
1 aliexpress.com/catalog/2758186/detail.aspx
2 aliexpress.com/catalog/2758186/detail.aspx
3 vk.com
Name: url, dtype: object