我试图做使用改造2.0 HTTP POST到服务器
MediaType MEDIA_TYPE_TEXT = MediaType.parse("text/plain");
MediaType MEDIA_TYPE_IMAGE = MediaType.parse("image/*");
ByteArrayOutputStream byteArrayOutputStream = new ByteArrayOutputStream();
imageBitmap.compress(Bitmap.CompressFormat.JPEG, 90, byteArrayOutputStream);
profilePictureByte = byteArrayOutputStream.toByteArray();
Call<APIResults> call = ServiceAPI.updateProfile(
RequestBody.create(MEDIA_TYPE_TEXT, emailString),
RequestBody.create(MEDIA_TYPE_IMAGE, profilePictureByte));
call.enqueue();
服务器返回一个错误,说文件是无效的。
这是奇怪,因为我曾尝试上传在iOS(使用其他库)相同的格式相同的文件,但它成功上传。
我想知道什么是上传使用改造2.0图像的正确方法?
我应该首先保存到硬盘上传之前?
谢谢!
PS:我已经使用改装为其他多部分请求不包括图像和他们成功完成。 问题是,当我试图包括在主体上的字节。
Answer 1:
我强调两个1.9和2.0的解决方案,因为它是一些有用的
在1.9
,我认为更好的解决办法是将文件保存到磁盘,并把它作为像键入的文件:
改造1.9
(我不知道你的服务器端实现)有类似这样的API接口方法
@POST("/en/Api/Results/UploadFile")
void UploadFile(@Part("file")TypedFile file,@Part("folder")String folder,Callback<Response> callback);
并使用它像
TypedFile file = new TypedFile("multipart/form-data", new File(path));
对于改造2使用以下方法
改造2.0(这是一个解决方法问题,在改造2现在是固定的,正确的方法是指jimmy0251的答案 )
API接口:
public interface ApiInterface {
@Multipart
@POST("/api/Accounts/editaccount")
Call<User> editUser (@Header("Authorization") String authorization, @Part("file\"; filename=\"pp.png\" ") RequestBody file , @Part("FirstName") RequestBody fname, @Part("Id") RequestBody id);
}
使用它,如:
File file = new File(imageUri.getPath());
RequestBody fbody = RequestBody.create(MediaType.parse("image/*"), file);
RequestBody name = RequestBody.create(MediaType.parse("text/plain"), firstNameField.getText().toString());
RequestBody id = RequestBody.create(MediaType.parse("text/plain"), AZUtils.getUserId(this));
Call<User> call = client.editUser(AZUtils.getToken(this), fbody, name, id);
call.enqueue(new Callback<User>() {
@Override
public void onResponse(retrofit.Response<User> response, Retrofit retrofit) {
AZUtils.printObject(response.body());
}
@Override
public void onFailure(Throwable t) {
t.printStackTrace();
}
});
Answer 2:
有上传与它的名字与改造2文件,无需任何破解的正确方法:
定义API接口:
@Multipart
@POST("uploadAttachment")
Call<MyResponse> uploadAttachment(@Part MultipartBody.Part filePart);
// You can add other parameters too
上传这样的文件:
File file = // initialize file here
MultipartBody.Part filePart = MultipartBody.Part.createFormData("file", file.getName(), RequestBody.create(MediaType.parse("image/*"), file));
Call<MyResponse> call = api.uploadAttachment(filePart);
这说明只有文件上传,您还可以在用同样的方法添加其他参数@Part
注解。
Answer 3:
我用改造2.0我的注册用户,发送的multipart /表单文件图片和文字从注册的账号
在我RegisterActivity,使用的AsyncTask
//AsyncTask
private class Register extends AsyncTask<String, Void, String> {
@Override
protected void onPreExecute() {..}
@Override
protected String doInBackground(String... params) {
new com.tequilasoft.mesasderegalos.dbo.Register().register(txtNombres, selectedImagePath, txtEmail, txtPassword);
responseMensaje = StaticValues.mensaje ;
mensajeCodigo = StaticValues.mensajeCodigo;
return String.valueOf(StaticValues.code);
}
@Override
protected void onPostExecute(String codeResult) {..}
在我Register.java类就是利用与改造同步调用
import android.util.Log;
import com.tequilasoft.mesasderegalos.interfaces.RegisterService;
import com.tequilasoft.mesasderegalos.utils.StaticValues;
import com.tequilasoft.mesasderegalos.utils.Utilities;
import java.io.File;
import okhttp3.MediaType;
import okhttp3.MultipartBody;
import okhttp3.RequestBody;
import okhttp3.ResponseBody;
import retrofit2.Call;
import retrofit2.Response;
/**Created by sam on 2/09/16.*/
public class Register {
public void register(String nombres, String selectedImagePath, String email, String password){
try {
// create upload service client
RegisterService service = ServiceGenerator.createUser(RegisterService.class);
// add another part within the multipart request
RequestBody requestEmail =
RequestBody.create(
MediaType.parse("multipart/form-data"), email);
// add another part within the multipart request
RequestBody requestPassword =
RequestBody.create(
MediaType.parse("multipart/form-data"), password);
// add another part within the multipart request
RequestBody requestNombres =
RequestBody.create(
MediaType.parse("multipart/form-data"), nombres);
MultipartBody.Part imagenPerfil = null;
if(selectedImagePath!=null){
File file = new File(selectedImagePath);
Log.i("Register","Nombre del archivo "+file.getName());
// create RequestBody instance from file
RequestBody requestFile =
RequestBody.create(MediaType.parse("multipart/form-data"), file);
// MultipartBody.Part is used to send also the actual file name
imagenPerfil = MultipartBody.Part.createFormData("imagenPerfil", file.getName(), requestFile);
}
// finally, execute the request
Call<ResponseBody> call = service.registerUser(imagenPerfil, requestEmail,requestPassword,requestNombres);
Response<ResponseBody> bodyResponse = call.execute();
StaticValues.code = bodyResponse.code();
StaticValues.mensaje = bodyResponse.message();
ResponseBody errorBody = bodyResponse.errorBody();
StaticValues.mensajeCodigo = errorBody==null
?null
:Utilities.mensajeCodigoDeLaRespuestaJSON(bodyResponse.errorBody().byteStream());
Log.i("Register","Code "+StaticValues.code);
Log.i("Register","mensaje "+StaticValues.mensaje);
Log.i("Register","mensajeCodigo "+StaticValues.mensaje);
}
catch (Exception e){
e.printStackTrace();
}
}
}
在RegisterService的接口
public interface RegisterService {
@Multipart
@POST(StaticValues.REGISTER)
Call<ResponseBody> registerUser(@Part MultipartBody.Part image,
@Part("email") RequestBody email,
@Part("password") RequestBody password,
@Part("nombre") RequestBody nombre
);
}
对于公用事业解析OFR响应的InputStream
public class Utilities {
public static String mensajeCodigoDeLaRespuestaJSON(InputStream inputStream){
String mensajeCodigo = null;
try {
BufferedReader reader = new BufferedReader(
new InputStreamReader(
inputStream, "iso-8859-1"), 8);
StringBuilder sb = new StringBuilder();
String line;
while ((line = reader.readLine()) != null) {
sb.append(line).append("\n");
}
inputStream.close();
mensajeCodigo = sb.toString();
} catch (Exception e) {
Log.e("Buffer Error", "Error converting result " + e.toString());
}
return mensajeCodigo;
}
}
Answer 4:
更新代码为Retrofit2.0图像文件上传
public interface ApiInterface {
@Multipart
@POST("user/signup")
Call<UserModelResponse> updateProfilePhotoProcess(@Part("email") RequestBody email, @Part("password") RequestBody password, @Part("profile_pic\"; filename=\"pp.png\" ") RequestBody file);
}
改变MediaType.parse("image/*")
到MediaType.parse("image/jpeg")
RequestBody reqFile = RequestBody.create(MediaType.parse("image/jpeg"), file);
RequestBody email = RequestBody.create(MediaType.parse("text/plain"), "upload_test4@gmail.com");
RequestBody password = RequestBody.create(MediaType.parse("text/plain"), "123456789");
Call<UserModelResponse> call = apiService.updateProfilePhotoProcess(email,password,reqFile);
call.enqueue(new Callback<UserModelResponse>() {
@Override
public void onResponse(Call<UserModelResponse> call, Response<UserModelResponse> response) {
String TAG = response.body().toString();
UserModelResponse userModelResponse = response.body();
UserModel userModel = userModelResponse.getUserModel();
Log.d("MainActivity","user image = "+userModel.getProfilePic());
}
@Override
public void onFailure(Call<UserModelResponse> call, Throwable t) {
Toast.makeText(MainActivity.this,""+TAG,Toast.LENGTH_LONG).show();
}
});
Answer 5:
添加到由@insomniac给出了答案 。 您可以创建一个Map
把参数RequestBody
包括图像。
代码接口
public interface ApiInterface {
@Multipart
@POST("/api/Accounts/editaccount")
Call<User> editUser (@Header("Authorization") String authorization, @PartMap Map<String, RequestBody> map);
}
代码的Java类
File file = new File(imageUri.getPath());
RequestBody fbody = RequestBody.create(MediaType.parse("image/*"), file);
RequestBody name = RequestBody.create(MediaType.parse("text/plain"), firstNameField.getText().toString());
RequestBody id = RequestBody.create(MediaType.parse("text/plain"), AZUtils.getUserId(this));
Map<String, RequestBody> map = new HashMap<>();
map.put("file\"; filename=\"pp.png\" ", fbody);
map.put("FirstName", name);
map.put("Id", id);
Call<User> call = client.editUser(AZUtils.getToken(this), map);
call.enqueue(new Callback<User>() {
@Override
public void onResponse(retrofit.Response<User> response, Retrofit retrofit)
{
AZUtils.printObject(response.body());
}
@Override
public void onFailure(Throwable t) {
t.printStackTrace();
}
});
Answer 6:
因此,它非常简单的方式来实现你的任务。 您需要按照下面的步骤: -
1.第一步骤
public interface APIService {
@Multipart
@POST("upload")
Call<ResponseBody> upload(
@Part("item") RequestBody description,
@Part("imageNumber") RequestBody description,
@Part MultipartBody.Part imageFile
);
}
你需要让整个呼叫为@Multipart request
。 item
和image number
只是串体,其被包裹在RequestBody
。 我们使用MultipartBody.Part class
,使我们能够发送实际的文件名,除了与请求的二进制文件数据
2.第二步骤
File file = (File) params[0];
RequestBody requestFile = RequestBody.create(MediaType.parse("multipart/form-data"), file);
MultipartBody.Part body =MultipartBody.Part.createFormData("Image", file.getName(), requestBody);
RequestBody ItemId = RequestBody.create(okhttp3.MultipartBody.FORM, "22");
RequestBody ImageNumber = RequestBody.create(okhttp3.MultipartBody.FORM,"1");
final Call<UploadImageResponse> request = apiService.uploadItemImage(body, ItemId,ImageNumber);
现在你有image path
,你需要转换成file
。现在转换file
到RequestBody
使用方法RequestBody.create(MediaType.parse("multipart/form-data"), file)
。 现在,你需要你的转换RequestBody requestFile
成MultipartBody.Part
使用方法MultipartBody.Part.createFormData("Image", file.getName(), requestBody);
。
ImageNumber
和ItemId
是我的另一个数据,我需要发送到服务器,所以我也使这两个东西放进RequestBody
。
欲了解更多信息
Answer 7:
上传文件使用改装很简单,需要构建你的API接口
public interface Api {
String BASE_URL = "http://192.168.43.124/ImageUploadApi/";
@Multipart
@POST("yourapipath")
Call<MyResponse> uploadImage(@Part("image\"; filename=\"myfile.jpg\" ") RequestBody file, @Part("desc") RequestBody desc);
}
在上面的代码图像是按键的名称,所以如果你正在使用PHP,你会写$ _FILES [“形象”] [“tmp_name的值”]得到这个。 和文件名=“myfile.jpg”是正在与请求发送的文件的名称。
现在要上传的文件,你需要,这将使你从开放的绝对路径的方法。
private String getRealPathFromURI(Uri contentUri) {
String[] proj = {MediaStore.Images.Media.DATA};
CursorLoader loader = new CursorLoader(this, contentUri, proj, null, null, null);
Cursor cursor = loader.loadInBackground();
int column_index = cursor.getColumnIndexOrThrow(MediaStore.Images.Media.DATA);
cursor.moveToFirst();
String result = cursor.getString(column_index);
cursor.close();
return result;
}
现在你可以使用下面的代码,上传您的文件。
private void uploadFile(Uri fileUri, String desc) {
//creating a file
File file = new File(getRealPathFromURI(fileUri));
//creating request body for file
RequestBody requestFile = RequestBody.create(MediaType.parse(getContentResolver().getType(fileUri)), file);
RequestBody descBody = RequestBody.create(MediaType.parse("text/plain"), desc);
//The gson builder
Gson gson = new GsonBuilder()
.setLenient()
.create();
//creating retrofit object
Retrofit retrofit = new Retrofit.Builder()
.baseUrl(Api.BASE_URL)
.addConverterFactory(GsonConverterFactory.create(gson))
.build();
//creating our api
Api api = retrofit.create(Api.class);
//creating a call and calling the upload image method
Call<MyResponse> call = api.uploadImage(requestFile, descBody);
//finally performing the call
call.enqueue(new Callback<MyResponse>() {
@Override
public void onResponse(Call<MyResponse> call, Response<MyResponse> response) {
if (!response.body().error) {
Toast.makeText(getApplicationContext(), "File Uploaded Successfully...", Toast.LENGTH_LONG).show();
} else {
Toast.makeText(getApplicationContext(), "Some error occurred...", Toast.LENGTH_LONG).show();
}
}
@Override
public void onFailure(Call<MyResponse> call, Throwable t) {
Toast.makeText(getApplicationContext(), t.getMessage(), Toast.LENGTH_LONG).show();
}
});
}
对于更详细的解释,你可以访问这个改造上传文件教程 。
文章来源: POST Multipart Form Data using Retrofit 2.0 including image