How to send input to the console as if the user is

问题:

This is my problem. I have a program that has to run in a TTY, cygwin provides this TTY. When I redirect stdIn the program fails because it does not have a TTY. I cannot modify this program, and need some way of automating it.

How can I grab the cmd.exe window and send it data and make it think the user is typing it?

I'm using C#, I believe there is a way to do it with java.awt.Robot but I have to use C# for other reasons.

回答1:

This sounds like a task for SendKeys(). It's not C#, but VBScript, but nontheless - you asked for some way of automating it:

Set Shell = CreateObject("WScript.Shell")

Shell.Run "cmd.exe /k title RemoteControlShell"
WScript.Sleep 250

Shell.AppActivate "RemoteControlShell"
WScript.Sleep 250

Shell.SendKeys "dir{ENTER}"

回答2:

I have figured out how to send the input to the console. I used what Jon Skeet said. I am not 100% sure this is the correct way to implement this.

If there are any comments on to make this better I would love to here. I did this just to see if I could figure it out.

Here is the program I stared that waited for input form the user

class Program
{
    static void Main(string[] args)
    {
        // This is needed to wait for the other process to wire up.
        System.Threading.Thread.Sleep(2000);

        Console.WriteLine("Enter Pharse: ");

        string pharse = Console.ReadLine();

        Console.WriteLine("The password is '{0}'", pharse);


        Console.WriteLine("Press any key to exit. . .");
        string lastLine = Console.ReadLine();

        Console.WriteLine("Last Line is: '{0}'", lastLine);
    }
}

This is the console app writing to the other one

class Program
{
    static void Main(string[] args)
    {
        // Find the path of the Console to start
        string readFilePath = System.IO.Path.GetFullPath(@"..\..\..\ReadingConsole\bin\Debug\ReadingConsole.exe");

        ProcessStartInfo startInfo = new ProcessStartInfo(readFilePath);

        startInfo.RedirectStandardOutput = true;
        startInfo.RedirectStandardInput = true;
        startInfo.WindowStyle = ProcessWindowStyle.Hidden;
        startInfo.CreateNoWindow = true;
        startInfo.UseShellExecute = false;

        Process readProcess = new Process();
        readProcess.StartInfo = startInfo;

        // This is the key to send data to the server that I found
        readProcess.OutputDataReceived += new DataReceivedEventHandler(readProcess_OutputDataReceived);

        // Start the process
        readProcess.Start();

        readProcess.BeginOutputReadLine();

        // Wait for other process to spin up
        System.Threading.Thread.Sleep(5000);

        // Send Hello World
        readProcess.StandardInput.WriteLine("Hello World");

        readProcess.StandardInput.WriteLine("Exit");

        readProcess.WaitForExit();
    }

    static void readProcess_OutputDataReceived(object sender, DataReceivedEventArgs e)
    {
        // Write what was sent in the event
        Console.WriteLine("Data Recieved at {1}: {0}", e.Data, DateTime.UtcNow.Ticks);
    }
}

回答3:

Can you start the program (or cygwin) within your code, using ProcessStartInfo.RedirectStandardInput (and output/error) to control the data flow?

回答4:

I had similar problem some time ago, cygwin should write some useful information (exact cygwin function, error text and WINAPI error code) to error stream, you should redirect it somewhere and read what it writes.