Parsing Domainname From URL In PHP

问题:

How I can parse a domain from URL in PHP? It seems that I need a country domain database.

Examples:

http://mail.google.com/hfjdhfjd/jhfjd.html -> google.com
http://www.google.bg/jhdjhf/djfhj.html -> google.bg
http://www.google.co.uk/djhdjhf.php -> google.co.uk
http://www.tsk.tr/jhjgc.aspx -> tsk.tr
http://subsub.sub.nic.tr/ -> nic.tr
http://subsub.sub.google.com.tr -> google.com.tr
http://subsub.sub.itoy.info.tr -> itoy.info.tr

Can it be done with whois request?

Edit: There are few domain names with .tr (www.nic.tr, www.tsk.tr) the others are as you know: www.something.com.tr, www.something.org.tr

Also there is no www.something.com.bg, www.something.org.bg. They are www.something.bg like the Germans' .de

But there are www.something.a.bg, www.something.b.bg thus a.bg, b.bg, c.bg and so on. (a.bg is like co.uk)

There on the net must be list of these top domain names.

Check how is coloured the url http://www.agrotehnika97.a.bg/ in Internet Explorer. Check also

www.google.co.uk<br>
www.google.com.tr<br>
www.nic.tr<br>
www.tsk.tr

回答1:

The domain is stored in $_SERVER['HTTP_HOST'].

EDIT: I believe this returns the whole domain. To just get the top-level domain, you could do this:

// Add all your wanted subdomains that act as top-level domains, here (e.g. 'co.cc' or 'co.uk')
// As array key, use the last part ('cc' and 'uk' in the above examples) and the first part as sub-array elements for that key
$allowed_subdomains = array(
    'cc'    => array(
        'co'
    ),
    'uk'    => array(
        'co'
    )
);

$domain = $_SERVER['HTTP_HOST'];
$parts = explode('.', $domain);
$top_level = array_pop($parts);

// Take care of allowed subdomains
if (isset($allowed_subdomains[$top_level]))
{
    if (in_array(end($parts), $allowed_subdomains[$top_level]))
        $top_level = array_pop($parts).'.'.$top_level;
}

$top_level = array_pop($parts).'.'.$top_level;

回答2:

You can use parse_url() to split it up and get what you want. Here's an example...

    $url = 'http://www.google.com/search?hl=en&source=hp&q=google&btnG=Google+Search&meta=lr%3D&aq=&oq=dasd';
    print_r(parse_url($url));

Will echo...

Array
(
    [scheme] => http
    [host] => www.google.com
    [path] => /search
    [query] => hl=en&source=hp&q=google&btnG=Google+Search&meta=lr%3D&aq=&oq=dasd
)

回答3:

I reckon you'll need a list of all suffixes used after a domain name. http://publicsuffix.org/list/ provides an up-to-date (or so they claim) of all suffixes in use currently. The list is actually here Now the idea would be for you to parse up that list into a structure, with different levels split by the dot, starting by the end levels:

so for instance for the domains: com.la com.tr com.lc

you'd end up with:

[la]=>[com]
[lc]=>[com]

etc...

Then you'd get the host from base_url (by using parse_url), and you'd explode it by dots. and you start matching up the values against your structure, starting with the last one:

so for google.com.tr you'd start by matching tr, then com, then you won't find a match once you get to google, which is what you want...

回答4:

Regex and parse_url() aren't solution for you.

You need package that uses Public Suffix List, only in this way you can correctly extract domains with two-, third-level TLDs (co.uk, a.bg, b.bg, etc.). I recomend use TLD Extract.

Here example of code:

$extract = new LayerShifter\TLDExtract\Extract();

$result = $extract->parse('http://subsub.sub.google.com.tr');
$result->getRegistrableDomain(); // will return (string) 'google.com.tr'