如何在Python验证IP地址？ [重复] 如何在Python验证IP地址？ [重复](How

这个问题已经在这里有一个答案：

• 检查字符串在python的IP地址模式匹配？ 18个回答

什么是验证用户输入的IP是否有效的最好方法？ 它有一个字符串。

Answer 1:

不要解析它。 只要问。

import socket

try:
    socket.inet_aton(addr)
    # legal
except socket.error:
    # Not legal

Answer 2:

import socket

def is_valid_ipv4_address(address):
    try:
        socket.inet_pton(socket.AF_INET, address)
    except AttributeError:  # no inet_pton here, sorry
        try:
            socket.inet_aton(address)
        except socket.error:
            return False
        return address.count('.') == 3
    except socket.error:  # not a valid address
        return False

    return True

def is_valid_ipv6_address(address):
    try:
        socket.inet_pton(socket.AF_INET6, address)
    except socket.error:  # not a valid address
        return False
    return True

Answer 3:

该IPY模块 （专为处理IP地址的模块）将抛出无效地址的ValueError异常。

>>> from IPy import IP
>>> IP('127.0.0.1')
IP('127.0.0.1')
>>> IP('277.0.0.1')
Traceback (most recent call last):
 ...
ValueError: '277.0.0.1': single byte must be 0 <= byte < 256
>>> IP('foobar')
Traceback (most recent call last):
 ...
ValueError: invalid literal for long() with base 10: 'foobar'

然而，像达斯汀的回答，它会接受像“4”和“192.168”因为，如前所述，这些都是IP地址的有效表示。

如果你正在使用Python 3.3或更高版本，现在包括ip地址模块 ：

>>> import ipaddress
>>> ipaddress.ip_address('127.0.0.1')
IPv4Address('127.0.0.1')
>>> ipaddress.ip_address('277.0.0.1')
Traceback (most recent call last):
  File "<stdin>", line 1, in <module>
  File "/usr/lib/python3.3/ipaddress.py", line 54, in ip_address
    address)
ValueError: '277.0.0.1' does not appear to be an IPv4 or IPv6 address
>>> ipaddress.ip_address('foobar')
Traceback (most recent call last):
  File "<stdin>", line 1, in <module>
  File "/usr/lib/python3.3/ipaddress.py", line 54, in ip_address
    address)
ValueError: 'foobar' does not appear to be an IPv4 or IPv6 address

对于Python 2，你可以使用ip地址，如果你安装python-ip地址获取相同的功能：

pip install ipaddress

该模块是与Python 2兼容，并提供了非常类似的API到因为Python 3.3包括Python标准库在IPADDRESS模块。 更多细节在这里 。 在Python 2，你需要将IP地址字符串显式转换为Unicode： ipaddress.ip_address(u'127.0.0.1') 。

Answer 4:

def is_valid_ip(ip):
    """Validates IP addresses.
    """
    return is_valid_ipv4(ip) or is_valid_ipv6(ip)

IPv4的：

def is_valid_ipv4(ip):
    """Validates IPv4 addresses.
    """
    pattern = re.compile(r"""
        ^
        (?:
          # Dotted variants:
          (?:
            # Decimal 1-255 (no leading 0's)
            [3-9]\d?|2(?:5[0-5]|[0-4]?\d)?|1\d{0,2}
          |
            0x0*[0-9a-f]{1,2}  # Hexadecimal 0x0 - 0xFF (possible leading 0's)
          |
            0+[1-3]?[0-7]{0,2} # Octal 0 - 0377 (possible leading 0's)
          )
          (?:                  # Repeat 0-3 times, separated by a dot
            \.
            (?:
              [3-9]\d?|2(?:5[0-5]|[0-4]?\d)?|1\d{0,2}
            |
              0x0*[0-9a-f]{1,2}
            |
              0+[1-3]?[0-7]{0,2}
            )
          ){0,3}
        |
          0x0*[0-9a-f]{1,8}    # Hexadecimal notation, 0x0 - 0xffffffff
        |
          0+[0-3]?[0-7]{0,10}  # Octal notation, 0 - 037777777777
        |
          # Decimal notation, 1-4294967295:
          429496729[0-5]|42949672[0-8]\d|4294967[01]\d\d|429496[0-6]\d{3}|
          42949[0-5]\d{4}|4294[0-8]\d{5}|429[0-3]\d{6}|42[0-8]\d{7}|
          4[01]\d{8}|[1-3]\d{0,9}|[4-9]\d{0,8}
        )
        $
    """, re.VERBOSE | re.IGNORECASE)
    return pattern.match(ip) is not None

IPv6的：

def is_valid_ipv6(ip):
    """Validates IPv6 addresses.
    """
    pattern = re.compile(r"""
        ^
        \s*                         # Leading whitespace
        (?!.*::.*::)                # Only a single whildcard allowed
        (?:(?!:)|:(?=:))            # Colon iff it would be part of a wildcard
        (?:                         # Repeat 6 times:
            [0-9a-f]{0,4}           #   A group of at most four hexadecimal digits
            (?:(?<=::)|(?<!::):)    #   Colon unless preceeded by wildcard
        ){6}                        #
        (?:                         # Either
            [0-9a-f]{0,4}           #   Another group
            (?:(?<=::)|(?<!::):)    #   Colon unless preceeded by wildcard
            [0-9a-f]{0,4}           #   Last group
            (?: (?<=::)             #   Colon iff preceeded by exacly one colon
             |  (?<!:)              #
             |  (?<=:) (?<!::) :    #
             )                      # OR
         |                          #   A v4 address with NO leading zeros 
            (?:25[0-4]|2[0-4]\d|1\d\d|[1-9]?\d)
            (?: \.
                (?:25[0-4]|2[0-4]\d|1\d\d|[1-9]?\d)
            ){3}
        )
        \s*                         # Trailing whitespace
        $
    """, re.VERBOSE | re.IGNORECASE | re.DOTALL)
    return pattern.match(ip) is not None

IPv6的版本使用“ (?:(?<=::)|(?<!::):) ” “它可以替换为(?(?<!::):) ”对正则表达式引擎支持条件语句与查找变通。 （即PCRE，.NET）

编辑：

• 放弃了原生的变体。
• 扩展的正则表达式符合RFC。
• 添加了另一个正则表达式的IPv6地址。

EDIT2：

我发现了一些链接讨论如何使用正则表达式解析IPv6地址：

• 地址IPv6的正则表达式 - InterMapper论坛
• 工作IPv6的正则表达式 -帕特里克游乐场博客
• test-ipv6-regex.pl - Perl脚本与吨的测试案例。 这似乎对其中的几个测试我正则表达式失败。

EDIT3：

终于写出通过了所有测试的模式，而且我也很高兴。

Answer 5:

在Python 3.4，检查的最佳方式，如果一个IPv6还是IPv4地址是正确的，是用Python标准库模块ipaddress - IPv4 / IPv6双操作库SA https://docs.python.org/3/library/ipaddress .HTML为完整的文档。

例如：

#!/usr/bin/env python

import ipaddress
import sys

try:
    ip = ipaddress.ip_address(sys.argv[1])
    print('%s is a correct IP%s address.' % (ip, ip.version))
except ValueError:
    print('address/netmask is invalid: %s' % sys.argv[1])
except:
    print('Usage : %s  ip' % sys.argv[0])

对于其他版本：Github上，phihag /菲利普Hagemeister， “巨蟒3.3的ip地址为老的Python版本”， https://github.com/phihag/ipaddress

从phihag的反向移植可如在蟒蛇的Python 2.7包含在安装程序。 SA https://docs.continuum.io/anaconda/pkg-docs

要使用PIP安装：

pip install ipaddress

SA：IPADDRESS 1.0.17 “的IPv4 / IPv6处理库”， “在3.3+ ip地址模块的端口”， https://pypi.python.org/pypi/ipaddress/1.0.17

Answer 6:

我希望它是简单和Python的不足：

def is_valid_ip(ip):
    m = re.match(r"^(\d{1,3})\.(\d{1,3})\.(\d{1,3})\.(\d{1,3})$", ip)
    return bool(m) and all(map(lambda n: 0 <= int(n) <= 255, m.groups()))

Answer 7:

我认为这会做...

def validIP(address):
    parts = address.split(".")
    if len(parts) != 4:
        return False
    for item in parts:
        if not 0 <= int(item) <= 255:
            return False
    return True

Answer 8:

我得给信贷的大量工作马库斯Jarderot为他的岗位 - 我的大部分职位的是从他的启发。

我发现，马库斯的回答仍然未能一些在他的回答中引用的Perl脚本IPv6的例子。

这里是我的正则表达式通过所有的在Perl脚本的例子：

r"""^
     \s* # Leading whitespace
     # Zero-width lookaheads to reject too many quartets
     (?:
        # 6 quartets, ending IPv4 address; no wildcards
        (?:[0-9a-f]{1,4}(?::(?!:))){6}
             (?:25[0-4]|2[0-4]\d|1\d\d|[1-9]\d|\d)
        (?:\.(?:25[0-4]|2[0-4]\d|1\d\d|[1-9]\d|\d)){3}
      |
        # 0-5 quartets, wildcard, ending IPv4 address
        (?:(?:[0-9a-f]{1,4}(?::(?!:))){0,4}[0-9a-f]{1,4})?
        (?:::(?!:))
             (?:25[0-4]|2[0-4]\d|1\d\d|[1-9]\d|\d)
        (?:\.(?:25[0-4]|2[0-4]\d|1\d\d|[1-9]\d|\d)){3}
      |
        # 0-4 quartets, wildcard, 0-1 quartets, ending IPv4 address
        (?:(?:[0-9a-f]{1,4}(?::(?!:))){0,3}[0-9a-f]{1,4})?
        (?:::(?!:))
        (?:[0-9a-f]{1,4}(?::(?!:)))?
             (?:25[0-4]|2[0-4]\d|1\d\d|[1-9]\d|\d)
        (?:\.(?:25[0-4]|2[0-4]\d|1\d\d|[1-9]\d|\d)){3}
      |
        # 0-3 quartets, wildcard, 0-2 quartets, ending IPv4 address
        (?:(?:[0-9a-f]{1,4}(?::(?!:))){0,2}[0-9a-f]{1,4})?
        (?:::(?!:))
        (?:[0-9a-f]{1,4}(?::(?!:))){0,2}
             (?:25[0-4]|2[0-4]\d|1\d\d|[1-9]\d|\d)
        (?:\.(?:25[0-4]|2[0-4]\d|1\d\d|[1-9]\d|\d)){3}
      |
        # 0-2 quartets, wildcard, 0-3 quartets, ending IPv4 address
        (?:(?:[0-9a-f]{1,4}(?::(?!:))){0,1}[0-9a-f]{1,4})?
        (?:::(?!:))
        (?:[0-9a-f]{1,4}(?::(?!:))){0,3}
             (?:25[0-4]|2[0-4]\d|1\d\d|[1-9]\d|\d)
        (?:\.(?:25[0-4]|2[0-4]\d|1\d\d|[1-9]\d|\d)){3}
      |
        # 0-1 quartets, wildcard, 0-4 quartets, ending IPv4 address
        (?:[0-9a-f]{1,4}){0,1}
        (?:::(?!:))
        (?:[0-9a-f]{1,4}(?::(?!:))){0,4}
             (?:25[0-4]|2[0-4]\d|1\d\d|[1-9]\d|\d)
        (?:\.(?:25[0-4]|2[0-4]\d|1\d\d|[1-9]\d|\d)){3}
      |
        # wildcard, 0-5 quartets, ending IPv4 address
        (?:::(?!:))
        (?:[0-9a-f]{1,4}(?::(?!:))){0,5}
             (?:25[0-4]|2[0-4]\d|1\d\d|[1-9]\d|\d)
        (?:\.(?:25[0-4]|2[0-4]\d|1\d\d|[1-9]\d|\d)){3}
      |
        # 8 quartets; no wildcards
        (?:[0-9a-f]{1,4}(?::(?!:))){7}[0-9a-f]{1,4}
      |
        # 0-7 quartets, wildcard
        (?:(?:[0-9a-f]{1,4}(?::(?!:))){0,6}[0-9a-f]{1,4})?
        (?:::(?!:))
      |
        # 0-6 quartets, wildcard, 0-1 quartets
        (?:(?:[0-9a-f]{1,4}(?::(?!:))){0,5}[0-9a-f]{1,4})?
        (?:::(?!:))
        (?:[0-9a-f]{1,4})?
      |
        # 0-5 quartets, wildcard, 0-2 quartets
        (?:(?:[0-9a-f]{1,4}(?::(?!:))){0,4}[0-9a-f]{1,4})?
        (?:::(?!:))
        (?:(?:[0-9a-f]{1,4}(?::(?!:))){0,1}[0-9a-f]{1,4})?
      |
        # 0-4 quartets, wildcard, 0-3 quartets
        (?:(?:[0-9a-f]{1,4}(?::(?!:))){0,3}[0-9a-f]{1,4})?
        (?:::(?!:))
        (?:(?:[0-9a-f]{1,4}(?::(?!:))){0,2}[0-9a-f]{1,4})?
      |
        # 0-3 quartets, wildcard, 0-4 quartets
        (?:(?:[0-9a-f]{1,4}(?::(?!:))){0,2}[0-9a-f]{1,4})?
        (?:::(?!:))
        (?:(?:[0-9a-f]{1,4}(?::(?!:))){0,3}[0-9a-f]{1,4})?
      |
        # 0-2 quartets, wildcard, 0-5 quartets
        (?:(?:[0-9a-f]{1,4}(?::(?!:))){0,1}[0-9a-f]{1,4})?
        (?:::(?!:))
        (?:(?:[0-9a-f]{1,4}(?::(?!:))){0,4}[0-9a-f]{1,4})?
      |
        # 0-1 quartets, wildcard, 0-6 quartets
        (?:[0-9a-f]{1,4})?
        (?:::(?!:))
        (?:(?:[0-9a-f]{1,4}(?::(?!:))){0,5}[0-9a-f]{1,4})?
      |
        # wildcard, 0-7 quartets
        (?:::(?!:))
        (?:(?:[0-9a-f]{1,4}(?::(?!:))){0,6}[0-9a-f]{1,4})?
     )
     (?:/(?:1(?:2[0-7]|[01]\d)|\d\d?))? # With an optional CIDR routing prefix (0-128)
     \s* # Trailing whitespace
    $"""

我也把一个Python脚本测试所有的IPv6的例子; 它是在这里引擎收录 ，因为它太大了，张贴在这里。

可以在形式“[结果] = [示例]”运行带的测试结果和实施例参数的脚本，所以这样的：

python script.py Fail=::1.2.3.4: pass=::127.0.0.1 false=::: True=::1

或者你可以简单地通过指定任何参数，所以像运行所有测试：

python script.py

无论如何，我希望这可以帮助别人！

Answer 9:

我想出了这个小白简单的版本

def ip_checkv4(ip):
        parts=ip.split(".")
        if len(parts)<4 or len(parts)>4:
            return "invalid IP length should be 4 not greater or less than 4"
        else:
            while len(parts)== 4:
                a=int(parts[0])
                b=int(parts[1])
                c=int(parts[2])
                d=int(parts[3])
                if a<= 0 or a == 127 :
                    return "invalid IP address"
                elif d == 0:
                    return "host id  should not be 0 or less than zero " 
                elif a>=255:
                    return "should not be 255 or greater than 255 or less than 0 A"
                elif b>=255 or b<0: 
                    return "should not be 255 or greater than 255 or less than 0 B"
                elif c>=255 or c<0:
                    return "should not be 255 or greater than 255 or less than 0 C"
                elif d>=255 or c<0:
                    return "should not be 255 or greater than 255 or less than 0 D"
                else:
                    return "Valid IP address ", ip

    p=raw_input("Enter IP address")
    print ip_checkv4(p)

Answer 10:

考虑IPv4地址为“IP”。

if re.match(r'^((\d{1,2}|1\d{2}|2[0-4]\d|25[0-5])\.){3}(\d{1,2}|1\d{2}|2[0-4]\d|25[0-5])$', ip):  
    print "Valid IP"  
else:
    print "Invalid IP"

Answer 11:

我只需要解析IP V4地址。 基于寒战战略我的解决方案如下：

def getIP():

    valid = False

    while not valid :

        octets = raw_input( "Remote Machine IP Address:" ).strip().split(".")

        try: valid=len( filter( lambda(item):0<=int(item)<256, octets) ) == 4

        except: valid = False

    return ".".join( octets )

文章来源: How to validate IP address in Python? [duplicate]