Submit form input array with jquery ajax post

问题:

Alright I want to submit a form thru jquery ajax. All the inputs are in an array and it is multidimensional.

Its a dynamic form that uses the array key as the question id. The subkey is used for grouping the questions at a question set.

<form name="testing" id="testing" method="post">
    <label>Question 1?</label> 
    <input type="text" name="data[14][1]" id="" class="" value=""><br>
    <label>Question 2?</label> 
    <input type="text" name="data[16][1]" id="" class="" value=""><br>
    <label>Question 1?</label> 
    <input type="text" name="data[14][2]" id="" class="" value=""><br>
    <label>Question 2?</label> 
    <input type="text" name="data[16][2]" id="" class="" value=""><br>
    <label>Question 3?</label> 
    <select name="data[19]" id="" class="">
        <option value="1">1</option>
        <option value="2">2</option>
        <option value="3">3</option>
        <option value="4">4</option>
    </select><br>
    <input type="submit" value="Submit">
</form>

So that is my example html. Here is my example jquery:

$("#testing").submit(function() { 
           var data = $('input[name^="data\\["]').serializeArray();
                $.ajax({ 
                 type: "POST",
                 url:  "upload.php",
                 data: {internalform: "submit", data: data},
                 dataType : "text",

           success: function(returndata){
            if(returndata == "no") 
             { return false;
             } else {
               alert("clicked 1 " + returndata);
                }
                 } 
                 });    
            return false;
            }); 

Problem is I get this as a return array:

Array
(
    [0] => Array
        (
            [name] => data[14]
            [value] => sd
        )

    [1] => Array
        (
            [name] => data[16]
            [value] => s
        )

)

But I want an array like this:

Array ( [14] => ddd [16] => ddd [19] => 4 ) 

Im sure its simple but I'm missing something. I know why its doing it but I can't get it the way I want it/need it. Can someone help?

回答1:

Try below snippet,I have not tested this but probably it should work.

Replace var data = $('input[name^="data\\["]').serializeArray(); part with below snippet

var data = {};
$.each($('input[name^="data\\["]')​.serializeArray()​, function() {
    data[this.name] = this.value;
})​;

Try this it will solve the data coming in front issues

i have worked out this one

var data = {};
$.each($('select[name^="data\\["] , input[name^="data\\["]').serializeArray(), function() {
   var vv = this.name.replace(/data/, '' ).replace(/(\[[0-9]\])$/,'');
   data[vv] = this.value;           
});

回答2:

I don't know how to do this in jquery but you can transform that array in php

$result = array();
foreach($array as $item) {
   $index = intval(preg_replace("/data\[([0-9]*)\]/", '\1' $item['name']));
   $result[$index] = $item['value'];
}

回答3:

Try this

var data = {}; 
$('input[name^="data\\["]').serializeArray().map(function(n){
    var name = n['name'].replace(/data\[([0-9]*)\]\[(.*)\]/, '$1');
    data[name] = n['value'];
});

回答4:

var data = {};
$.each($('input[name^="data\\["]')​.serializeArray()​, function() {
    data[this.name] = this.value;
})​;

gives console error >>

Uncaught SyntaxError: missing ) after argument list