I have a collection which elements can be simplified to this:
{tags : [1, 5, 8]}
where there would be at least one element in array and all of them should be different. I want to substitute one tag for another and I thought that there would not be a problem. So I came up with the following query:
db.colll.update({
tags : 1
},{
$pull: { tags: 1 },
$addToSet: { tags: 2 }
}, {
multi: true
})
Cool, so it will find all elements which has a tag that I do not need (1), remove it and add another (2) if it is not there already. The problem is that I get an error:
"Cannot update 'tags' and 'tags' at the same time"
Which basically means that I can not do pull and addtoset at the same time. Is there any other way I can do this?
Of course I can memorize all the IDs of the elements and then remove tag and add in separate queries, but this does not sound nice.
The error is pretty much what it means as you cannot act on two things of the same "path" in the same update operation. The two operators you are using do not process sequentially as you might think they do.
You can do this with as "sequential" as you can possibly get with the "bulk" operations API or other form of "bulk" update though. Within reason of course, and also in reverse:
var bulk = db.coll.initializeOrderedBulkOp();
bulk.find({ "tags": 1 }).updateOne({ "$addToSet": { "tags": 2 } });
bulk.find({ "tags": 1 }).updateOne({ "$pull": { "tags": 1 } });
bulk.execute();
Not a guarantee that nothing else will try to modify,but it is as close as you will currently get.
Also see the raw "update" command with multiple documents.
If you're removing and adding at the same time, you may be modeling a 'map', instead of a 'set'. If so, an object may be less work than an array.
Instead of data as an array:
{ _id: 'myobjectwithdata',
data: [{ id: 'data1', important: 'stuff'},
{ id: 'data2', important: 'more'}]
}
Use data as an object:
{ _id: 'myobjectwithdata',
data: { data1: { important: 'stuff'},
data2: { important: 'more'} }
}
The one-command update is then:
db.coll.update(
'myobjectwithdata',
{ $set: { 'data.data1': { important: 'treasure' } }
);
Hard brain working for this answer done here and here.