Probably a confusing title, but not sure how else to put it. Example should make it clearer. I have many different models that share many of the same attributes. So in each model I have to specify those same attributes and THEN the attributes that are specific to that particular model.
Is there any way I can create some class that lists these basic attributes and then inherit from that class without using Single-Table Inheritance? Because if I put all the shared attributes and Mongoid includes into a single model and inherit from that base model in the other models, then STI is enforced and all my models are stored in a single mongodb collection, differentiated by a "_type" field.
This is what I have:
class Model_1
include Mongoid::Document
field :uuid, :type => String
field :process_date, :type => String
...
end
class Model_2
include Mongoid::Document
field :uuid, :type => String
field :process_date, :type => String
...
end
But this is the functionality I'm after:
class Base_model
field :uuid, :type => String
field :process_date, :type => String
end
class Model_1 < Base_model
# To ensure STI is not enforced
include Mongoid::Document
# Attribute list inherited from Base_model
end
The issue is that if you don't have the "include Mongoid::Document" in the Base_model, then that base model doesn't know about the "field ..." functionality. But if you do put the mongoid include in the base model and inherit from it, STI is enforced.
I can't do STI for this particular situation but it's a coding nightmare to have multiple models, all with the same attributes list specified over and over (there are a growing number of models and each share about 15-20 attributes, so anytime I have to change a model name it's a lot of effort to change it everywhere...).