与Apache抢占基本身份验证的HttpClient 4与Apache抢占基本身份验证的HttpCl

是否有设置一个更简单的方法比什么描述先发制人基本验证HTTP客户端在这里 ？
在以前的版本（3.X），它使用的是一个简单的方法调用（例如， httpClient.getParams().setAuthenticationPreemptive(true) ）。
我想避免的主要问题是添加BasicHttpContext给我执行每个方法。

Answer 1:

这是很难做到这一点没有通过上下文通过每一次，但你也许可以通过使用请求拦截做到这一点。 下面是一些代码，我们使用（从他们的JIRA发现，IIRC）：

// Pre-emptive authentication to speed things up
BasicHttpContext localContext = new BasicHttpContext();

BasicScheme basicAuth = new BasicScheme();
localContext.setAttribute("preemptive-auth", basicAuth);

httpClient.addRequestInterceptor(new PreemptiveAuthInterceptor(), 0);

(...)

static class PreemptiveAuthInterceptor implements HttpRequestInterceptor {

    public void process(final HttpRequest request, final HttpContext context) throws HttpException, IOException {
        AuthState authState = (AuthState) context.getAttribute(ClientContext.TARGET_AUTH_STATE);

        // If no auth scheme avaialble yet, try to initialize it
        // preemptively
        if (authState.getAuthScheme() == null) {
            AuthScheme authScheme = (AuthScheme) context.getAttribute("preemptive-auth");
            CredentialsProvider credsProvider = (CredentialsProvider) context.getAttribute(ClientContext.CREDS_PROVIDER);
            HttpHost targetHost = (HttpHost) context.getAttribute(ExecutionContext.HTTP_TARGET_HOST);
            if (authScheme != null) {
                Credentials creds = credsProvider.getCredentials(new AuthScope(targetHost.getHostName(), targetHost.getPort()));
                if (creds == null) {
                    throw new HttpException("No credentials for preemptive authentication");
                }
                authState.setAuthScheme(authScheme);
                authState.setCredentials(creds);
            }
        }

    }

}

Answer 2:

如果您正在寻找强制HttpClient的4单个请求进行身份验证，下面的工作：

String username = ...
String password = ...
UsernamePasswordCredentials creds = new UsernamePasswordCredentials(username, password);

HttpRequest request = ...
request.addHeader(new BasicScheme().authenticate(creds, request));

Answer 3:

这是相同的解决方案垫的曼尼恩的，但你不必把localContext每个请求。 所以，很简单，但它增加了认证的所有要求。 有用的，如果你使用Apache Solr实现，它使用HttpClient的内部时，并没有对个人要求的控制，在我的情况。

import org.apache.http.HttpException;
import org.apache.http.HttpHost;
import org.apache.http.HttpRequest;
import org.apache.http.HttpRequestInterceptor;
import org.apache.http.auth.AuthScope;
import org.apache.http.auth.AuthState;
import org.apache.http.auth.Credentials;
import org.apache.http.client.CredentialsProvider;
import org.apache.http.client.protocol.ClientContext;
import org.apache.http.impl.auth.BasicScheme;
import org.apache.http.protocol.ExecutionContext;
import org.apache.http.protocol.HttpContext;

httpClient.addRequestInterceptor(new PreemptiveAuthInterceptor(), 0);

(...)

static class PreemptiveAuthInterceptor implements HttpRequestInterceptor {

    public void process(final HttpRequest request, final HttpContext context) throws HttpException, IOException {
        AuthState authState = (AuthState) context.getAttribute(ClientContext.TARGET_AUTH_STATE);

        // If no auth scheme available yet, try to initialize it
        // preemptively
        if (authState.getAuthScheme() == null) {
            CredentialsProvider credsProvider = (CredentialsProvider) context.getAttribute(ClientContext.CREDS_PROVIDER);
            HttpHost targetHost = (HttpHost) context.getAttribute(ExecutionContext.HTTP_TARGET_HOST);
            Credentials creds = credsProvider.getCredentials(new AuthScope(targetHost.getHostName(), targetHost.getPort()));
            if (creds == null) {
                throw new HttpException("No credentials for preemptive authentication");
            }
            authState.setAuthScheme(new BasicScheme());
            authState.setCredentials(creds);
        }

    }

}

当然，你必须设置凭据提供：

httpClient.getCredentialsProvider().setCredentials(
                new AuthScope(url.getHost(), url.getPort()),
                new UsernamePasswordCredentials(username, password))

该AuthScope不能包含的境界，因为它是事先不知道。

Answer 4:

很多上面使用的答案过时代码。 我使用Apache SOLRJ版本5.0.0。 我的代码由

private HttpSolrClient solrClient; 

private void initialiseSOLRClient() {
            URL solrURL = null;
            try {
                solrURL = new URL(urlString);
            } catch (MalformedURLException e) {
                LOG.error("Cannot parse the SOLR URL!!" + urlString);
                throw new SystemException("Cannot parse the SOLR URL!! " + urlString, e);
            }
            String host = solrURL.getHost();
            int port = solrURL.getPort();
            AuthScope authScope = new AuthScope(host, port);

    BasicTextEncryptor textEncryptor = new BasicTextEncryptor();
    textEncryptor.setPassword("red bananas in the spring");
    String decryptPass = textEncryptor.decrypt(pass);
    UsernamePasswordCredentials creds = new UsernamePasswordCredentials(userName, decryptPass);

    CredentialsProvider credsProvider = new BasicCredentialsProvider();
    credsProvider.setCredentials(
            authScope,
            creds);

    HttpClientBuilder builder = HttpClientBuilder.create();
    builder.addInterceptorFirst(new PreemptiveAuthInterceptor());
    builder.setDefaultCredentialsProvider(credsProvider);
    CloseableHttpClient httpClient = builder.build();

    solrClient = new HttpSolrClient(urlString, httpClient);
}

该PreemptiveAuthInterceptor现在是如下： -

static class PreemptiveAuthInterceptor implements HttpRequestInterceptor {

    public void process(final HttpRequest request, final HttpContext context) throws HttpException, IOException {
        AuthState authState = (AuthState) context.getAttribute(HttpClientContext.TARGET_AUTH_STATE);
        // If no auth scheme available yet, try to initialize it
        // preemptively
        if (authState.getAuthScheme() == null) {
            CredentialsProvider credsProvider = (CredentialsProvider) 
                        context.getAttribute(HttpClientContext.CREDS_PROVIDER);
            HttpHost targetHost = (HttpHost) context.getAttribute(HttpCoreContext.HTTP_TARGET_HOST);
            AuthScope authScope = new AuthScope(targetHost.getHostName(), targetHost.getPort());
            Credentials creds = credsProvider.getCredentials(authScope);
            if(creds == null){

            }
            authState.update(new BasicScheme(), creds);
        }

    }
}

Answer 5:

有点晚了党，但我来到翻过线程试图解决这个问题的一个POST请求的代理预授权。 要添加到亚当的回应，我发现我下面的工作：

HttpPost httppost = new HttpPost(url);
UsernamePasswordCredentials creds = new UsernamePasswordCredentials(username, password);
Header bs = new BasicScheme().authenticate(creds, httppost);
httppost.addHeader("Proxy-Authorization", bs.getValue());

原以为可能是其他人谁运行到这很有帮助。

Answer 6:

我认为最好的办法可能只是做手工。 我增加了以下功能

经典的Java：

import javax.xml.bind.DatatypeConverter;

...

private static void addAuthHeader(HttpRequestBase http, String username, String password) throws UnsupportedEncodingException {
        String encoded = DatatypeConverter.printBase64Binary((username + ":" + password).getBytes("UTF-8"));
        http.addHeader("AUTHORIZATION", "Basic " + encoded);
    }

HTTPRequestBase可以是一个实例HttpGet或HttpPost

安卓：

import android.util.Base64;

...

private static void addAuthHeader(HttpRequestBase http, String username, String password) throws UnsupportedEncodingException {
    String encoded = Base64.encodeToString((username + ":" + password).getBytes("UTF-8"), Base64.NO_WRAP);
    http.addHeader("AUTHORIZATION", "Basic " + encoded);
}

Answer 7:

我使用此代码，根据我的阅读HttpClient的4.5文档 ：

HttpClientContext ctx = HttpClientContext.create()
ctx.setCredentialsProvider(new BasicCredentialsProvider())
ctx.setAuthCache(new BasicAuthCache())
UsernamePasswordCredentials creds = new UsernamePasswordCredentials(user, pass)
AuthScope authScope = new AuthScope(host, port)
ctx.getCredentialsProvider.setCredentials(authScope, credentials)

// This part makes authentication preemptive:
HttpHost targetHost = new HttpHost(host, port, scheme)
ctx.getAuthCache.put(targetHost, new BasicScheme())

...，并确保你总是传递上下文HTTPClient.execute()

Answer 8:

我不知道你这个结尾的注释。 它具有所有的机器做先发制人权威性的HttpClient和你只需要做，一旦（在构造和配置的HttpClient）。 一旦你这样做，你建立你的方法实例同样的方式一如既往。 你不“加BasicHttpContext”的方法。

你最好的选择，我倒是觉得，是有自己的对象，设置所有先发制人身份验证所需的垃圾，并具有给定的列举HTTPMethod对象执行请求的简单方法或方法。

Answer 9:

在Android中，垫曼尼恩的回答无法解决HTTPS，仍然发送两个请求，你能做到像下面，关键是与用户代理追加authHeader：

    public static DefaultHttpClient createProxyHttpClient() {
        try {
            final DefaultHttpClient client = createPlaintHttpClient();
            client.setRoutePlanner(new HttpRoutePlanner() {
                @Override
                public HttpRoute determineRoute(HttpHost target, HttpRequest request, HttpContext context) throws HttpException {
                    boolean isSecure = "https".equalsIgnoreCase(target.getSchemeName());
                    if (needProxy) {
                        Header header = isSecure ? ProxyUtils.createHttpsAuthHeader() : ProxyUtils.createAuthHeader();
                        if (isSecure) {
                            client.getParams().setParameter(CoreProtocolPNames.USER_AGENT, com.netease.cloudmusic.utils.HttpRequest.USER_AGENT + "\r\n" + header.getName() + ":" + header.getValue());
                        } else {
                            client.getParams().setParameter(CoreProtocolPNames.USER_AGENT, com.netease.cloudmusic.utils.HttpRequest.USER_AGENT);
                            if (request instanceof RequestWrapper) {
                                request = ((RequestWrapper) request).getOriginal();
                            }
                            request.setHeader(header);
                        }
                        String host = isSecure ? ProxyUtils.SECURE_HOST : ProxyUtils.HOST;
                        int port = isSecure ? ProxyUtils.SECURE_PORT : ProxyUtils.PORT;
                        return new HttpRoute(target, null,  new HttpHost(host, port), isSecure);
                    } else {
                        client.getParams().setParameter(CoreProtocolPNames.USER_AGENT, com.netease.cloudmusic.utils.HttpRequest.USER_AGENT);
                        return new HttpRoute(target, null, isSecure);
                    }
                }
            });
            return client;
        } catch (Exception e) {
            e.printStackTrace();
            return new DefaultHttpClient();
        }
    }

public static DefaultHttpClient createPlaintHttpClient() {
       try {
            KeyStore trustStore = KeyStore.getInstance(KeyStore.getDefaultType());
            trustStore.load(null, null);
            PlainSSLSocketFactory socketFactory = new PlainSSLSocketFactory(trustStore);
            socketFactory.setHostnameVerifier(SSLSocketFactory.ALLOW_ALL_HOSTNAME_VERIFIER);
            BasicHttpParams params = new BasicHttpParams();
            HttpConnectionParams.setConnectionTimeout(params, 30000);
            HttpConnectionParams.setSoTimeout(params, 30000);
            HttpProtocolParams.setVersion(params, HttpVersion.HTTP_1_1);
            HttpProtocolParams.setContentCharset(params, HTTP.UTF_8);
            SchemeRegistry registry = new SchemeRegistry();
            registry.register(new Scheme("http", PlainSocketFactory.getSocketFactory(), 80));
            registry.register(new Scheme("https", socketFactory, 443));
            ThreadSafeClientConnManager ccm = new ThreadSafeClientConnManager(params, registry);
            HttpClientParams.setCookiePolicy(params, CookiePolicy.BROWSER_COMPATIBILITY);
            final DefaultHttpClient client = new DefaultHttpClient(ccm, params);
            client.setRoutePlanner(new HttpRoutePlanner() {
        @Override
        public HttpRoute determineRoute(HttpHost target, HttpRequest arg1, HttpContext arg2) throws HttpException {
               client.getParams().setParameter(CoreProtocolPNames.USER_AGENT, com.netease.cloudmusic.utils.HttpRequest.USER_AGENT);
            return new HttpRoute(target, null, "https".equalsIgnoreCase(target.getSchemeName()));
        }
        });
            return client;
        } catch (Exception e) {
            e.printStackTrace();
            return new DefaultHttpClient();
        }
}

文章来源: Preemptive Basic authentication with Apache HttpClient 4