I work with ASP.NET MVC With Durandal/Breeze templates.
Let's say I have the following class:
public class Person
{
public int Id { get; set; }
public string Firstname { get; set; }
public string Lastname { get; set; }
public virtual List<Person> Friends { get; set; }
}
With the following EF Fluent API:
modelBuilder.Entity<Person>()
.HasMany(m => m.Friends)
.WithMany()
.Map(m => m.ToTable("Friends"));
The database is generated successfully.
The problem is when I perform a que
ry with Breeze (client side) I have no data for the Friends
property.
var query = entityQuery.from('Person')
.where('id', '==', 123)
.expand("Friends");
When the query is executed I get as result the requested People entity with all the data except the Friends property is always an empty array. When I check the Json answer I see that also the data are transmitted. Even data for the Friends property. However they are not linked to the Friends property itself.
My question: what do I have to do to have my Friends property filled with values?
Thanks.
You must declare a foreign key in Person. Breeze requires the FK to correctly resolve associations.
Edit:
I just realized you are asking about a many-to-many relationship. (yeah, I should have read the post title...)
Breeze does not support many-to-many associations.
However, you could have two one-to-many relationships to work as a many-to-many. (i.e. many-to-one-to-many) In this case, you will need to define the linking table/entity and the foreign key as mentioned earlier. (see http://www.breezejs.com/documentation/navigation-properties)
Try this answer: *Note that this is incomplete because i do not see the other table that you are trying to m-2-m with Persons. ( You will only want to use Persons Table and the 2nd Table , NOT table=Friends.
db.Person
.Include(c => c.Friends)
.Where(c => c.Friends.Any(up => up.FriendVlaue == c.FirstName)) //c.from Persons
.Select(c => new
{
PersonID = c.ID,
PersonName = c.FirstName,
PersonCount = c.Person.Count()
})
{
From This answer
You should include Friends in the results. You can do this by adding Include("Friends")
at Server Side API.
[HttpGet]
public IQueryable<Person> Persons()
{
return _contextProvider.Persons.Include("Friends");
}
If you don't want to return always the Friends
reference, you can create another method in the API such as PersonsWithFriends
as suggested in here (Specialized query actions).