I'm trying to cycle through some table rows. The simplified rows are as follows:
<table>
<tr id="ucf48">
<td class="ucf_text">
<input name="ucf_t48" value="Ann becomes very involved in the text she is reading." type="text">
</td>
</tr>
<tr id="ucf351">
<td class="ucf_text">
<input name="ucf_t351" value="Ann is a fast and confident reader." type="text">
</td>
</tr>
</table>
I'm using this code to cycle:
$('#ucf tr').each(function(i,obj){
var cn=$(this).attr('id').substr(3);
var t=$(this +'.ucf_text input').val();
console.log("Row "+i);
console.log("Cnum: "+cn);
console.log(t);
});
The console output is:
Row 0
Cnum: 48
Ann becomes very involved in the text she is reading.
Row 1
Cnum: 351
Ann becomes very involved in the text she is reading.
Now before someone flames me, I know I can do this another way by referring to the data I want using 'name'. Why, however, does my cnum variable follow 'this' but the t variable does not?
Thanks.
When you do:
var t=$(this +'.ucf_text input').val();
this
isn't converting correctly to a string.
Try:
var t=$(this).find('.ucf_text input').val();
var t=$(this +'.ucf_text input').val();
You're trying to concatenate a string with a DOM node.
I assume you want the children of each row? Which would be:
var t=$(this).find('.ucf_text input').val();
You cannot concatenate DOM objects and strings.
You can easily fix this by specifying this
as the context of the selector:
var t = $('.ucf_text input', this).val();
By doing so the selector only matches elements inside the given context, i.e. the table row in your case.
You've already got 2 correct answers, but just for the sake of diversity, here's another way to do it:
var t = $('.ucf_text input', this).val();
Actually, this is because $(this)
[tr] doesn't have the class .ucf_text
I think you meant the td beneath it
Add a space to signify you mean the child. :)
var t=$(this +' .ucf_text input').val();
^ Space!
EDIT:
Or not!
var t=$(this).children('.ucf_text').children('input').val();
Find is way cooler, but I'm editing for the sake of not leaving a wrong answer up and wanted to be somewhat original, and besides... Maybe you need a distinct path to the input?