I'm trying to instantiate some modules in Verilog using a generate
block since I'm going to be instantiating a variable amount of them.
genvar i;
generate
for (i=1; i<=10; i=i+1) begin
status whatever_status (
.clk(clk),
.reset_n(reset_n),
.a(a[i]),
.b(b[i]),
.out(out[i])
);
end
endgenerate
a
& b
are declared as input arrays to the parent module and out
is declared as a array of wires.
What am I doing wrong here? Is this not allowed in Verilog? Quartus is telling me:
Error (10644): Verilog HDL error at driver.v(63): this block requires a name
Line 63 is the for loop above. Any help is appreciated!
You can apply label identifier to begin
-end
block with a colon after the begin (example: begin : label
- end
. This has always been an optional feature for generate blocks, though it is highly recommended. Quartus should not be giving an error.
It is an easy fix to satisfy Quartus-- add a label of any name you want:
genvar i;
generate
for (i=1; i<=10; i=i+1) begin : generate_block_identifier // <-- example block name
status whatever_status (
.clk(clk),
.reset_n(reset_n),
.a(a[i]),
.b(b[i]),
.out(out[i])
);
end
endgenerate
I know this doesn't directly answer the question, but you can also declare several modules in this formation without using a generate
block like so:
status whatever_status[10:0] (
.clk(clk),
.reset_n(reset_n),
.a(a),
.b(b),
.out(out)
);
This is equivalent to the generate
block above assuming that a
, b
, and out
being passed are declared as [10:0]
. This syntax will work as long as they're integer multiples of how they're declared in the module; they'll be spread evenly among each instance, otherwise synthesis will throw an error.
For example if a
, b
, and out
are declared [21:0]
, then every 2 bits will be passed to each instance, and it is assumed they are declared as [1:0]
within the module status
.
Give your block a name:
for (i=1; i<=10; i=i+1) begin: my_status