I need some help on declaring a regex. My inputs are like the following:
this is a paragraph with<[1> in between</[1> and then there are cases ... where the<[99> number ranges from 1-100</[99>.
and there are many other lines in the txt files
with<[3> such tags </[3>
The required output is:
this is a paragraph with in between and then there are cases ... where the number ranges from 1-100.
and there are many other lines in the txt files
with such tags
I\'ve tried this:
#!/usr/bin/python
import os, sys, re, glob
for infile in glob.glob(os.path.join(os.getcwd(), \'*.txt\')):
for line in reader:
line2 = line.replace(\'<[1> \', \'\')
line = line2.replace(\'</[1> \', \'\')
line2 = line.replace(\'<[1>\', \'\')
line = line2.replace(\'</[1>\', \'\')
print line
I\'ve also tried this (but it seems like I\'m using the wrong regex syntax):
line2 = line.replace(\'<[*> \', \'\')
line = line2.replace(\'</[*> \', \'\')
line2 = line.replace(\'<[*>\', \'\')
line = line2.replace(\'</[*>\', \'\')
I dont want to hard-code the replace
from 1 to 99 . . .
This tested snippet should do it:
import re
line = re.sub(r\"</?\\[\\d+>\", \"\", line)
Edit: Here\'s a commented version explaining how it works:
line = re.sub(r\"\"\"
(?x) # Use free-spacing mode.
< # Match a literal \'<\'
/? # Optionally match a \'/\'
\\[ # Match a literal \'[\'
\\d+ # Match one or more digits
> # Match a literal \'>\'
\"\"\", \"\", line)
Regexes are fun! But I would strongly recommend spending an hour or two studying the basics. For starters, you need to learn which characters are special: \"metacharacters\" which need to be escaped (i.e. with a backslash placed in front - and the rules are different inside and outside character classes.) There is an excellent online tutorial at: www.regular-expressions.info. The time you spend there will pay for itself many times over. Happy regexing!
str.replace()
does fixed replacements. Use re.sub()
instead.
I would go like this (regex explained in comments):
import re
# If you need to use the regex more than once it is suggested to compile it.
pattern = re.compile(r\"</{0,}\\[\\d+>\")
# <\\/{0,}\\[\\d+>
#
# Match the character “<” literally «<»
# Match the character “/” literally «\\/{0,}»
# Between zero and unlimited times, as many times as possible, giving back as needed (greedy) «{0,}»
# Match the character “[” literally «\\[»
# Match a single digit 0..9 «\\d+»
# Between one and unlimited times, as many times as possible, giving back as needed (greedy) «+»
# Match the character “>” literally «>»
subject = \"\"\"this is a paragraph with<[1> in between</[1> and then there are cases ... where the<[99> number ranges from 1-100</[99>.
and there are many other lines in the txt files
with<[3> such tags </[3>\"\"\"
result = pattern.sub(\"\", subject)
print(result)
If you want to learn more about regex I recomend to read Regular Expressions Cookbook by Jan Goyvaerts and Steven Levithan.
The easiest way
import re
txt=\'this is a paragraph with<[1> in between</[1> and then there are cases ... where the<[99> number ranges from 1-100</[99>. and there are many other lines in the txt files with<[3> such tags </[3>\'
out = re.sub(\"(<[^>]+>)\", \'\', txt)
print out
replace method of string objects does not accept regular expressions but only fixed strings (see documentation: http://docs.python.org/2/library/stdtypes.html#str.replace).
You have to use re
module:
import re
newline= re.sub(\"<\\/?\\[[0-9]+>\", \"\", line)
don\'t have to use regular expression (for your sample string)
>>> s
\'this is a paragraph with<[1> in between</[1> and then there are cases ... where the<[99> number ranges from 1-100</[99>. \\nand there are many other lines in the txt files\\nwith<[3> such tags </[3>\\n\'
>>> for w in s.split(\">\"):
... if \"<\" in w:
... print w.split(\"<\")[0]
...
this is a paragraph with
in between
and then there are cases ... where the
number ranges from 1-100
.
and there are many other lines in the txt files
with
such tags