C++: splitting a string into an array

问题:

I am trying to insert a string separated by spaces into an array of strings without using vector in C++. For example:

using namespace std;
int main() {
    string line = "test one two three.";
    string arr[4];

    //codes here to put each word in string line into string array arr
    for(int i = 0; i < 4; i++) {
        cout << arr[i] << endl;
    }
}

I want the output to be:

test
one
two
three.

I know there are already a lot of questions asking string > array in C++. I realize this might be a duplicate question, but I could not find any answer satisfying my conditions (splitting a string into an array WITHOUT using vector). I apologize in advanced if this was a repeated question.

回答1:

It is possible to turn the string into a stream by using the std::stringstream class (its constructor takes a string as parameter). Once it's built, you can use the >> operator on it (like on regular file based streams), which will extract, or tokenize word from it:

#include <sstream>

using namespace std;

int main(){
    string line = "test one two three.";
    string arr[4];
    int i = 0;
    stringstream ssin(line);
    while (ssin.good() && i < 4){
        ssin >> arr[i];
        ++i;
    }
    for(i = 0; i < 4; i++){
        cout << arr[i] << endl;
    }
}

回答2:

#include <iostream>
#include <sstream>
#include <iterator>
#include <string>

using namespace std;

template <size_t N>
void splitString(string (&arr)[N], string str)
{
    int n = 0;
    istringstream iss(str);
    for (auto it = istream_iterator<string>(iss); it != istream_iterator<string>() && n < N; ++it, ++n)
        arr[n] = *it;
}

int main()
{
    string line = "test one two three.";
    string arr[4];

    splitString(arr, line);

    for (int i = 0; i < 4; i++)
       cout << arr[i] << endl;
}

回答3:

#define MAXSPACE 25

string line =  "test one two three.";
string arr[MAXSPACE];
string search = " ";
int spacePos;
int currPos = 0;
int k = 0;
int prevPos = 0;

do
{

    spacePos = line.find(search,currPos);

    if(spacePos >= 0)
    {

        currPos = spacePos;
        arr[k] = line.substr(prevPos, currPos - prevPos);
        currPos++;
        prevPos = currPos;
        k++;
    }


}while( spacePos >= 0);

arr[k] = line.substr(prevPos,line.length());

for(int i = 0; i < k; i++)
{
   cout << arr[i] << endl;
}

回答4:

Trivial:

const vector<string> explode(const string& s, const char& c)
{
    string buff{""};
    vector<string> v;

    for(auto n:s)
    {
        if(n != c) buff+=n; else
        if(n == c && buff != "") { v.push_back(buff); buff = ""; }
    }
    if(buff != "") v.push_back(buff);

    return v;
}

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回答5:

Here's a suggestion: use two indices into the string, say start and end. start points to the first character of the next string to extract, end points to the character after the last one belonging to the next string to extract. start starts at zero, end gets the position of the first char after start. Then you take the string between [start..end) and add that to your array. You keep going until you hit the end of the string.