可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效,请关闭广告屏蔽插件后再试):
问题:
What is it and how to use?
I need that as I have a timer that inserts into DB every second, and I have a shared resource between timer handler and the main thread.
I want to gurantee that if the timer handler takes more than one second in the insertion the waited threads should be executed in order.
This is a sample code for my timer handler
private void InsertBasicVaraibles(object param)
{
try
{
DataTablesMutex.WaitOne();//mutex for my shared resources
//insert into DB
}
catch (Exception ex)
{
//Handle
}
finally
{
DataTablesMutex.ReleaseMutex();
}
}
But currently the mutex does not guarantee any order.
There is not answer after I put the detailed question!!!
回答1:
You'll need to write your own class to do this, I found this example (pasted because it looks as though the site's domain has lapsed):
using System.Threading;
public sealed class QueuedLock
{
private object innerLock;
private volatile int ticketsCount = 0;
private volatile int ticketToRide = 1;
public QueuedLock()
{
innerLock = new Object();
}
public void Enter()
{
int myTicket = Interlocked.Increment(ref ticketsCount);
Monitor.Enter(innerLock);
while (true)
{
if (myTicket == ticketToRide)
{
return;
}
else
{
Monitor.Wait(innerLock);
}
}
}
public void Exit()
{
Interlocked.Increment(ref ticketToRide);
Monitor.PulseAll(innerLock);
Monitor.Exit(innerLock);
}
}
Example of usage:
QueuedLock queuedLock = new QueuedLock();
try
{
queuedLock.Enter();
// here code which needs to be synchronized
// in correct order
}
finally
{
queuedLock.Exit();
}
Source via Google cache
回答2:
Just reading Joe Duffy's "Concurrent Programming on Windows" it sounds like you'll usually get FIFO behaviour from .NET monitors, but there are some situations where that won't occur.
Page 273 of the book says: "Because monitors use kernel objects internally, they exhibit the same roughly-FIFO behavior that the OS synchronization mechanisms also exhibit (described in the previous chapter). Monitors are unfair, so if another thread sneaks in and acquires the lock before an awakened waiting thread tries to acquire the lock, the sneaky thread is permitted to acquire the lock."
I can't immediately find the section referenced "in the previous chapter" but it does note that locks have been made deliberately unfair in recent editions of Windows to improve scalability and reduce lock convoys.
Do you definitely need your lock to be FIFO? Maybe there's a different way to approach the problem. I don't know of any locks in .NET which are guaranteed to be FIFO.
回答3:
You should re-design your system to not rely on the execution order of the threads. For example, rather than have your threads make a DB call that might take more than one second, have your threads place the command they would execute into a data structure like a queue (or a heap if there is something that says "this one should be before another one"). Then, in spare time, drain the queue and do your db inserts one at a time in the proper order.
回答4:
There is no guaranteed order on any built-in synchronisation objects: http://msdn.microsoft.com/en-us/library/ms684266(VS.85).aspx
If you want a guaranteed order you'll have to try and build something yourself, note though that it's not as easy as it might sound, especially when multiple threads reach the synchronisation point at (close to) the same time. To some extent the order they will be released will always be 'random' since you cannot predict in which order the point is reached, so does it really matter?
回答5:
Actually the answers are good, but I solved the problem by removing the timer and run the method (timer-handler previously) into background thread as follows
private void InsertBasicVaraibles()
{
int functionStopwatch = 0;
while(true)
{
try
{
functionStopwatch = Environment.TickCount;
DataTablesMutex.WaitOne();//mutex for my shared resources
//insert into DB
}
catch (Exception ex)
{
//Handle
}
finally
{
DataTablesMutex.ReleaseMutex();
}
//simulate the timer tick value
functionStopwatch = Environment.TickCount - functionStopwatch;
int diff = INSERTION_PERIOD - functionStopwatch;
int sleep = diff >= 0 ? diff:0;
Thread.Sleep(sleep);
}
}
回答6:
Follow up on Matthew Brindley's answer.
If converting code from
lock (LocalConnection.locker) {...}
then you could either do a IDisposable or do what I did:
public static void Locking(Action action) {
Lock();
try {
action();
} finally {
Unlock();
}
}
LocalConnection.Locking( () => {...});
I decided against IDisposable because it would creates a new invisible object on every call.
As to reentrancy issue I modified the code to this:
public sealed class QueuedLock {
private object innerLock = new object();
private volatile int ticketsCount = 0;
private volatile int ticketToRide = 1;
ThreadLocal<int> reenter = new ThreadLocal<int>();
public void Enter() {
reenter.Value++;
if ( reenter.Value > 1 )
return;
int myTicket = Interlocked.Increment( ref ticketsCount );
Monitor.Enter( innerLock );
while ( true ) {
if ( myTicket == ticketToRide ) {
return;
} else {
Monitor.Wait( innerLock );
}
}
}
public void Exit() {
if ( reenter.Value > 0 )
reenter.Value--;
if ( reenter.Value > 0 )
return;
Interlocked.Increment( ref ticketToRide );
Monitor.PulseAll( innerLock );
Monitor.Exit( innerLock );
}
}