In the c++ standard, in [basic.lval]/11.6 says:
If a program attempts to access the stored value of an object through a glvalue of other than one of the following types the behavior is undefined:[...]
- an aggregate or union type that includes one of the aforementioned types among its elements or non-static data members (including, recursively, an element or non-static data member of a subaggregate or contained union),[...]
This sentence is part of the strict-aliasing rule.
Can it allow us to access the inactive member of a non existing union? As in:
struct A{
int id :1;
int value :32;
};
struct Id{
int id :1;
};
union X{
A a;
Id id_;
};
void test(){
A a;
auto id = reinterpret_cast<X&>(a).id_; //UB or not?
}
Note: Bellow an explanation of what I do not grasp in the standard, and why the example above could be useful.
I wonder in what could [basic.lval]/11.6 be usefull.
[class.mfct.non-static]/2 does forbid us to call a member function of the "casted to" union or aggregate:
If a non-static member function of a class X is called for an object that is not of type X, or of a type derived from X, the behavior is undefined.
Considering that static data member access, or static member function can directly be performed using a qualified-name (a_class::a_static_member
),
the only usefull uses case of the [basic.lval]/11.6, may be to access member of the "casted to" union. I thought about using this last standard rule to implement an "optimized variant". This variant could hold either a class A object or a class B object, the two starting with a bitfield of size 1, denoting the type:
class A{
unsigned type_id_ :1;
int value :31;
public:
A():type_id_{0}{}
void bar{};
void baz{};
};
class B{
unsigned type_id_ :1;
int value :31;
public:
B():type_id_{1}{}
int value() const;
void value(int);
void bar{};
void baz{};
};
struct type_id_t{
unsigned type_id_ :1;
};
struct AB_variant{
union {
A a;
B b;
type_id_t id;};
//[...]
static void foo(AB_variant& x){
if (x.id.type_id_==0){
reinterpret_cast<A&>(x).bar();
reinterpret_cast<A&>(x).baz();
}
else if (x.id.type_id_==1){
reinterpret_cast<B&>(x).bar();
reinterpret_cast<B&>(x).baz();
}
}
};
The call to AB_variant::foo
does not invoke undefined behavior as long as its argument refers to an object of type AB_variant
thanks to the rule of pointer-interconvertibility [basic.compound]/4. The access to the inactive union member type_id_
is allowed because id
belongs to the common initial sequence of A
, B
and type_id_t
[class.mem]/25:
But what happens if I try to call it with a complete object of type A
?
A a{};
AB_variant::foo(reinterpret_cast<AB_variant&>(a));
The problem here is that I try to access an inactive member of a union that does not exist.
The two pertinent standard paragraphs are [class.mem]/25:
In a standard-layout union with an active member of struct type T1, it is permitted to read a non-static data member m of another union member of struct type T2 provided m is part of the common initial sequence of T1 and T2; the behavior is as if the corresponding member of T1 were nominated.
And [class.union]/1:
In a union, a non-static data member is active if its name refers to an object whose lifetime has begun and has not ended.
Q3: Does the expression "its name refers" signify that "an object" is actually an object built within a living union? Or could it refers to object a
because of [basic.lval]/11.6.