What is logits, softmax and softmax_cross_entropy_

问题:

I was going through the tensorflow API docs here. In the tensorflow documentation, they used a keyword called logits. What is it? In a lot of methods in the API docs it is written like

tf.nn.softmax(logits, name=None)

If what is written is those logits are only Tensors, why keeping a different name like logits?

Another thing is that there are two methods I could not differentiate. They were

tf.nn.softmax(logits, name=None)
tf.nn.softmax_cross_entropy_with_logits(logits, labels, name=None)

What are the differences between them? The docs are not clear to me. I know what tf.nn.softmax does. But not the other. An example will be really helpful.

回答1:

Logits simply means that the function operates on the unscaled output of earlier layers and that the relative scale to understand the units is linear. It means, in particular, the sum of the inputs may not equal 1, that the values are not probabilities (you might have an input of 5).

tf.nn.softmax produces just the result of applying the softmax function to an input tensor. The softmax \"squishes\" the inputs so that sum(input) = 1: it\'s a way of normalizing. The shape of output of a softmax is the same as the input: it just normalizes the values. The outputs of softmax can be interpreted as probabilities.

a = tf.constant(np.array([[.1, .3, .5, .9]]))
print s.run(tf.nn.softmax(a))
[[ 0.16838508  0.205666    0.25120102  0.37474789]]

In contrast, tf.nn.softmax_cross_entropy_with_logits computes the cross entropy of the result after applying the softmax function (but it does it all together in a more mathematically careful way). It\'s similar to the result of:

sm = tf.nn.softmax(x)
ce = cross_entropy(sm)

The cross entropy is a summary metric: it sums across the elements. The output of tf.nn.softmax_cross_entropy_with_logits on a shape [2,5] tensor is of shape [2,1] (the first dimension is treated as the batch).

If you want to do optimization to minimize the cross entropy AND you\'re softmaxing after your last layer, you should use tf.nn.softmax_cross_entropy_with_logits instead of doing it yourself, because it covers numerically unstable corner cases in the mathematically right way. Otherwise, you\'ll end up hacking it by adding little epsilons here and there.

Edited 2016-02-07: If you have single-class labels, where an object can only belong to one class, you might now consider using tf.nn.sparse_softmax_cross_entropy_with_logits so that you don\'t have to convert your labels to a dense one-hot array. This function was added after release 0.6.0.

回答2:

Short version:

Suppose you have two tensors, where y_hat contains computed scores for each class (for example, from y = W*x +b) and y_true contains one-hot encoded true labels.

y_hat  = ... # Predicted label, e.g. y = tf.matmul(X, W) + b
y_true = ... # True label, one-hot encoded

If you interpret the scores in y_hat as unnormalized log probabilities, then they are logits.

Additionally, the total cross-entropy loss computed in this manner:

y_hat_softmax = tf.nn.softmax(y_hat)
total_loss = tf.reduce_mean(-tf.reduce_sum(y_true * tf.log(y_hat_softmax), [1]))

is essentially equivalent to the total cross-entropy loss computed with the function softmax_cross_entropy_with_logits():

total_loss = tf.reduce_mean(tf.nn.softmax_cross_entropy_with_logits(y_hat, y_true))

Long version:

In the output layer of your neural network, you will probably compute an array that contains the class scores for each of your training instances, such as from a computation y_hat = W*x + b. To serve as an example, below I\'ve created a y_hat as a 2 x 3 array, where the rows correspond to the training instances and the columns correspond to classes. So here there are 2 training instances and 3 classes.

import tensorflow as tf
import numpy as np

sess = tf.Session()

# Create example y_hat.
y_hat = tf.convert_to_tensor(np.array([[0.5, 1.5, 0.1],[2.2, 1.3, 1.7]]))
sess.run(y_hat)
# array([[ 0.5,  1.5,  0.1],
#        [ 2.2,  1.3,  1.7]])

Note that the values are not normalized (i.e. the rows don\'t add up to 1). In order to normalize them, we can apply the softmax function, which interprets the input as unnormalized log probabilities (aka logits) and outputs normalized linear probabilities.

y_hat_softmax = tf.nn.softmax(y_hat)
sess.run(y_hat_softmax)
# array([[ 0.227863  ,  0.61939586,  0.15274114],
#        [ 0.49674623,  0.20196195,  0.30129182]])

It\'s important to fully understand what the softmax output is saying. Below I\'ve shown a table that more clearly represents the output above. It can be seen that, for example, the probability of training instance 1 being \"Class 2\" is 0.619. The class probabilities for each training instance are normalized, so the sum of each row is 1.0.

                      Pr(Class 1)  Pr(Class 2)  Pr(Class 3)
                    ,--------------------------------------
Training instance 1 | 0.227863   | 0.61939586 | 0.15274114
Training instance 2 | 0.49674623 | 0.20196195 | 0.30129182

So now we have class probabilities for each training instance, where we can take the argmax() of each row to generate a final classification. From above, we may generate that training instance 1 belongs to \"Class 2\" and training instance 2 belongs to \"Class 1\".

Are these classifications correct? We need to measure against the true labels from the training set. You will need a one-hot encoded y_true array, where again the rows are training instances and columns are classes. Below I\'ve created an example y_true one-hot array where the true label for training instance 1 is \"Class 2\" and the true label for training instance 2 is \"Class 3\".

y_true = tf.convert_to_tensor(np.array([[0.0, 1.0, 0.0],[0.0, 0.0, 1.0]]))
sess.run(y_true)
# array([[ 0.,  1.,  0.],
#        [ 0.,  0.,  1.]])

Is the probability distribution in y_hat_softmax close to the probability distribution in y_true? We can use cross-entropy loss to measure the error.

We can compute the cross-entropy loss on a row-wise basis and see the results. Below we can see that training instance 1 has a loss of 0.479, while training instance 2 has a higher loss of 1.200. This result makes sense because in our example above, y_hat_softmax showed that training instance 1\'s highest probability was for \"Class 2\", which matches training instance 1 in y_true; however, the prediction for training instance 2 showed a highest probability for \"Class 1\", which does not match the true class \"Class 3\".

loss_per_instance_1 = -tf.reduce_sum(y_true * tf.log(y_hat_softmax), reduction_indices=[1])
sess.run(loss_per_instance_1)
# array([ 0.4790107 ,  1.19967598])

What we really want is the total loss over all the training instances. So we can compute:

total_loss_1 = tf.reduce_mean(-tf.reduce_sum(y_true * tf.log(y_hat_softmax), reduction_indices=[1]))
sess.run(total_loss_1)
# 0.83934333897877944

Using softmax_cross_entropy_with_logits()

We can instead compute the total cross entropy loss using the tf.nn.softmax_cross_entropy_with_logits() function, as shown below.

loss_per_instance_2 = tf.nn.softmax_cross_entropy_with_logits(y_hat, y_true)
sess.run(loss_per_instance_2)
# array([ 0.4790107 ,  1.19967598])

total_loss_2 = tf.reduce_mean(tf.nn.softmax_cross_entropy_with_logits(y_hat, y_true))
sess.run(total_loss_2)
# 0.83934333897877922

Note that total_loss_1 and total_loss_2 produce essentially equivalent results with some small differences in the very final digits. However, you might as well use the second approach: it takes one less line of code and accumulates less numerical error because the softmax is done for you inside of softmax_cross_entropy_with_logits().

回答3:

tf.nn.softmax computes the forward propagation through a softmax layer. You use it during evaluation of the model when you compute the probabilities that the model outputs.

tf.nn.softmax_cross_entropy_with_logits computes the cost for a softmax layer. It is only used during training.

The logits are the unnormalized log probabilities output the model (the values output before the softmax normalization is applied to them).

回答4:

Above answers have enough description for the asked question.

Adding to that, Tensorflow has optimised the operation of applying the activation function then calculating cost using its own activation followed by cost functions. Hence it is a good practice to use: tf.nn.softmax_cross_entropy() over tf.nn.softmax(); tf.nn.cross_entropy()

You can find prominent difference between them in a resource intensive model.