In C++/CLI , you can use native types in a managed class by it is not allowed to hold a member of a native class in a managed class : you need to use pointers in that case.
Here is an example :
class NativeClass
{
....
};
public ref class ManagedClass
{
private:
NativeClass mNativeClass; // Not allowed !
NativeClass * mNativeClass; // OK
auto_ptr<NativeClass> mNativeClass; //Not allowed !
boost::shared_ptr<NativeClass> mNativeClass; //Not allowed !
};
Does anyone know of an equivalent of shared_ptr in the C++/CLI world?
Edit:
Thanks for your suggestion, "1800-Information". Following your suggestion, I checked about STL.Net but it is only available with Visual Studio 2008, and it provides containers + algorithms, but no smart pointers.
I found the answer on codeproject :
Nishant Sivakumar posted an article about this at http://www.codeproject.com/KB/mcpp/CAutoNativePtr.aspx
On this page, also look for the comment by Denis N. Shevchenko : he provides a stl-like implementation that works quite well.
I haven't thoroughly tested this but how about something like the following:
#pragma once
#include <memory>
template <class T>
public ref class m_shared_ptr sealed
{
std::shared_ptr<T>* pPtr;
public:
m_shared_ptr()
: pPtr(nullptr)
{}
m_shared_ptr(T* t) {
pPtr = new std::shared_ptr<T>(t);
}
m_shared_ptr(std::shared_ptr<T> t) {
pPtr = new std::shared_ptr<T>(t);
}
m_shared_ptr(const m_shared_ptr<T>% t) {
pPtr = new std::shared_ptr<T>(*t.pPtr);
}
!m_shared_ptr() {
delete pPtr;
}
~m_shared_ptr() {
delete pPtr;
}
operator std::shared_ptr<T>() {
return *pPtr;
}
m_shared_ptr<T>% operator=(T* ptr) {
pPtr = new std::shared_ptr<T>(ptr);
return *this;
}
T* operator->() {
return (*pPtr).get();
}
};
This should let you use C++11/Boost's shared_ptrs interchangebly in ref classes.
STL.Net is documented here. I don't know what state it is in or what use it might be for you.