I'm running this code, compiled on 64 bits vc++ 2005, on Windows Server 2008 R2 with 32GB. There is an access violation inside the for loop.
#include <iostream>
using namespace std;
int main(int argc, char* argv[])
{
double *x = new double[536870912];
cout << "memory allocated" << endl;
for(long int i = 0; i < 536870912; i++)
{
cout << i << endl;
x[i] = 0;
}
delete [] x;
return 0;
}
So if there is no exception in new double[536870912], why am I getting an access violation when doing an assignment over a particular array position?
Another point worth mentioning is that this program was succesfully tested on another computer.
It is probably one of the following problem:
- long int is 32-bits: that mean your maximum value is 2147483647, and sizeof(double)*536870912 >= 2147483647. (I don't really know if that has sense. It probably depend on how the compiller work)
- Your allocation is failing.
I suggest you to test the following code:
#include<conio.h>
#include <iostream>
using namespace std;
#define MYTYPE unsigned long long
int main(int argc, char* argv[])
{
// Test compiling mode
if (sizeof(void*) == 8) cout << "Compiling 64-bits" << endl;
else cout << "Compiling 32-bits" << endl;
// Test the size of mytype
cout << "Sizeof:" << sizeof(MYTYPE) << endl;
MYTYPE len;
// Get the number of <<doubles>> to allocate
cout << "How many doubles do you want?" << endl;
cin >> len;
double *x = new (std::nothrow) double[len];
// Test allocation
if (NULL==x)
{
cout << "unable to allocate" << endl;
return 0;
}
cout << "memory allocated" << endl;
// Set all values to 0
for(MYTYPE i = 0; i < len; i++)
{
if (i%100000==0) cout << i << endl;
x[i] = 0;
}
// Wait before release, to test memory usage
cout << "Press <Enter> key to continue...";
getch();
// Free memory.
delete [] x;
}
Editing: Using this code, i just achieved allocate a single block of 9GB.