In some code I saw recently there was a structure defined like this:
typedef struct tagMyStruct {
int numberOne;
int numberTwo;
} MYSTRUCT;
The way I understand this, tagMyStruct
is the new data type and MYSTRUCT
is a variable that is created right there.
At another place, this was used like this:
MYSTRUCT *pStruct = new MYSTRUCT;
and it compiled fine with Visual Studio 2010. How is that valid C++? I thought MYSTRUCT
was a variable and not a type?
No. tagMyStruct
is the name of the struct. In C, unlike C++, you must explicitly use the struct keyword every time you use the struct type. For example
tagMyStruct x; //error
struct tagMyStruct x; //OK
To avoid writing struct all the time, struct tagMyStruct
is typedef
'd to MYSTRUCT
. Now you can write
MYSTRUCT x; //ok, same as struct tagMyStruct x;
What you thought this was (a variable definition) would be without the typedef keyword, like this
struct tagMyStruct {
int numberOne;
int numberTwo;
} MYSTRUCT;
BTW
MYSTRUCT pStruct = new MYSTRUCT; //error cannot convert MYSTRUCT* to MYSTRUCT
is not valid C or C++ anyway. Maybe you mean
MYSTRUCT* pStruct = new MYSTRUCT; //valid C++ (invalid C - use malloc instead of new in C)
hth
struct tagMyStruct { ... };
defines a new C++ type (class) called tagMyStruct
.
struct { ... } MYSTRUCT;
defines a variable called MYSTRUCT
with the given structure.
typedef struct { ... } MYSTRUCT;
defines a typedef called MYSTRUCT
which is equivalent to the given anonymous struct.
typedef tagMyStruct struct { ... } MYSTRUCT;
defines a typedef called MYSTRUCT
and a type called tagMyStruct
. So MYSTRUCT is just a typedef for tagMyStruct. Therefore, MYSTRUCT pStruct
defines a tagMyStruct
called pStruct
.
The assignment you gave is invalid, since new MYSTRUCT
returns a pointer to MYSTRUCT
.
You are wrong, you are using typedef
, i.e. MYSTRUCT
is an alias for tagMyStruct
. This explains how it's correct c++.
In order to create a variable, drop the typedef:
struct tagMyStruct {
int numberOne;
int numberTwo;
} MYSTRUCT;