How to create directory with right permissions usi

问题:

I am trying to write a simple C program that creates directories (a mkdir clone.). This is what I have so far:

#include <stdlib.h>
#include <sys/stat.h> // mkdir
#include <stdio.h> // perror

mode_t getumask()
{
    mode_t mask = umask(0);
    umask (mask);
    return mask;
}

int main(int argc, const char *argv[])
{
    mode_t mask = getumask();
    printf("%i",mask);

    if (mkdir("trial",mask) == -1) {
        perror(argv[0]);
        exit(EXIT_FAILURE);
    }
    return 0;
}

This code creates directory with d--------- but I want it to create it with drwxr-xr-x like mkdir do? What am I doing wrong here?

Edit: This is the working solution for me:

int main(int argc, const char *argv[])
{
    if (mkdir("trial",0777) == -1) {
        perror(argv[0]);
        exit(EXIT_FAILURE);
    }
    return 0;
}

Setting right permissions according to umask is automatically handled. So I only needed to call mkdir with full permissions, and that gets chopped according to current umask.

回答1:

As Eric says, umask is the complement of the actual permission mode you get. So instead of passing mask itself to mkdir(), you should pass 0777-mask to mkdir().

回答2:

You seem to be misunderstanding what umask is used for. It sets/retrieves the process's file mode creation mask, which in turn is used to turn off bits in the file mode you specify in calls like mkdir, like this (pseduo-code):

real_mode = requested_mode & ~umask

So in your code, since you pass in the value of the umask itself, you end up specifying permissions as zero, which is exactly what you see.

Instead, you should specify the permissions you want in the call to mkdir, like this:

mkdir("trial", 0755)