Javafx 2 click and double click

问题:

I would like to know if it was possible to detect the double-click in JavaFX 2 ? and how ?

I would like to make different event between a click and a double click.

Thanks

回答1:

Yes you can detect single, double even multiple clicks:

myNode.setOnMouseClicked(new EventHandler<MouseEvent>() {
    @Override
    public void handle(MouseEvent mouseEvent) {
        if(mouseEvent.getButton().equals(MouseButton.PRIMARY)){
            if(mouseEvent.getClickCount() == 2){
                System.out.println("Double clicked");
            }
        }
    }
});

MouseButton.PRIMARY is used to determine if the left (commonly) mouse button is triggered the event. Read the api of getClickCount() to conclude that there maybe multiple click counts other than single or double. However I find it hard to distinguish between single and double click events. Because the first click count of the double click will rise a single event as well.

回答2:

Here is another piece of code which can be used if you have to distinguish between a single- and a double-click and have to take a specific action in either case.

import java.util.concurrent.ScheduledFuture;
import java.util.concurrent.ScheduledThreadPoolExecutor;
import java.util.concurrent.TimeUnit;

import javafx.application.Application;
import javafx.event.EventHandler;
import javafx.scene.Scene;
import javafx.scene.input.MouseButton;
import javafx.scene.input.MouseEvent;
import javafx.scene.layout.StackPane;
import javafx.stage.Stage;

public class DoubleClickDetectionTest extends Application {

    boolean dragFlag = false;

    int clickCounter = 0;

    ScheduledThreadPoolExecutor executor;

    ScheduledFuture<?> scheduledFuture;

    public DoubleClickDetectionTest() {
        executor = new ScheduledThreadPoolExecutor(1);
        executor.setRemoveOnCancelPolicy(true);
    }

    public static void main(String[] args) {
        launch(args);
    }

    @Override
    public void start(Stage primaryStage) throws Exception {
        StackPane root = new StackPane();

        primaryStage.setScene(new Scene(root, 400, 400));
        primaryStage.show();

        root.setOnMouseDragged(new EventHandler<MouseEvent>() {
            @Override
            public void handle(MouseEvent e) {
                if (e.getButton().equals(MouseButton.PRIMARY)) {
                    dragFlag = true;
                }
            }
        });

        root.setOnMouseClicked(new EventHandler<MouseEvent>() {
            @Override
            public void handle(MouseEvent e) {
                if (e.getButton().equals(MouseButton.PRIMARY)) {
                    if (!dragFlag) {
                        System.out.println(++clickCounter + " " + e.getClickCount());
                        if (e.getClickCount() == 1) {
                            scheduledFuture = executor.schedule(() -> singleClickAction(), 500, TimeUnit.MILLISECONDS);
                        } else if (e.getClickCount() > 1) {
                            if (scheduledFuture != null && !scheduledFuture.isCancelled() && !scheduledFuture.isDone()) {
                                scheduledFuture.cancel(false);
                                doubleClickAction();
                            }
                        }
                    }
                    dragFlag = false;
                }
            }
        });
    }

    @Override
    public void stop() {
        executor.shutdown();
    }

    private void singleClickAction() {
        System.out.println("Single-click action executed.");
    }

    private void doubleClickAction() {
        System.out.println("Double-click action executed.");
    }
}

回答3:

The response by P. Pandey is the simplest approach which actually distinguishes between single and double click, but it did not work for me. For one, the function "currentTimeMillis" already returns milliseconds, so dividing it by 1000 does not seem to be necessary. The version below worked for me in a more consistent fashion.

 @Override
 public void handle(MouseEvent t) {

        long diff = 0;

        currentTime=System.currentTimeMillis();

        if(lastTime!=0 && currentTime!=0){
            diff=currentTime-lastTime;

            if( diff<=215)
                isdblClicked=true;
            else
                isdblClicked=false;
        }

        lastTime=currentTime;

        System.out.println("IsDblClicked()"+isdblClicked); 

       //use the isdblClicked flag...   
}

回答4:

Here is how I have implemented double click

if (e.getEventType().equals(MouseEvent.MOUSE_CLICKED) && !drag_Flag) {
                long diff = 0;
            if(time1==0)
             time1=System.currentTimeMillis();
            else
            time2=System.currentTimeMillis();
            if(time1!=0 && time2!=0)
            diff=time2-time1;
            if((diff/1000)<=215 && diff>0)
            {
                isdblClicked=true;
            }
            else
            {
                isdblClicked=false;
            }

            System.out.println("IsDblClicked()"+isdblClicked); 

}

回答5:

Since it is not possible to distinguish between single-click and double-click by default, we use the following approach:

On single-click, we wrap the single-click operation in an abortable runnable. This runnable waits a certain amount of time (i.e., SINGLE_CLICK_DELAY) before being executed.

In the meantime, if a second click, i.e., a double-click, occurs, the single-click operation gets aborted and only the double-click operation is performed.

This way, either the single-click or the double-click operation is performed, but never both.

---

Following is the full code. To use it, only the three TODO lines have to be replaced by the wanted handlers.

private static final int SINGLE_CLICK_DELAY = 250;
private ClickRunner latestClickRunner = null;

private class ClickRunner implements Runnable {

    private final Runnable onSingleClick;
    private boolean aborted = false;

    public ClickRunner(Runnable onSingleClick) {
        this.onSingleClick = onSingleClick;
    }

    public void abort() {
        this.aborted = true;
    }

    @Override
    public void run() {
        try {
            Thread.sleep(SINGLE_CLICK_DELAY);
        } catch (InterruptedException e) {
            e.printStackTrace();
        }
        if (!aborted) {
            System.out.println("Execute Single Click");
            Platform.runLater(() -> onSingleClick.run());
        }
    }
}

private void init() {
    container.setOnMouseClicked(me -> {
        switch (me.getButton()) {
            case PRIMARY:
                if (me.getClickCount() == 1) {
                    System.out.println("Single Click");
                    latestClickRunner = new ClickRunner(() -> {
                      // TODO: Single-left-click operation
                    });
                    CompletableFuture.runAsync(latestClickRunner);
                }
                if (me.getClickCount() == 2) {
                    System.out.println("Double Click");
                    if (latestClickRunner != null) {
                        System.out.println("-> Abort Single Click");
                        latestClickRunner.abort();
                    }
                    // TODO: Double-left-click operation
                }
                break;
            case SECONDARY:
                // TODO: Right-click operation
                break;
            default:
                break;
        }
    });
}

回答6:

Adhering to Java SE 8 lambda expressions would look something like this:

node.setOnMouseClicked(event -> {
    if(event.getButton().equals(MouseButton.PRIMARY) && event.getClickCount() == 2) {
        handleSomeAction();
    }
});

Once you get used to lambda expressions - they end up being more understandable than the original class instantiation and overriding (x) method. -In my opinion-