I have the following two lines in a header in order to declare a vector containing a template:
template <class t>
std::vector <t> vec;
However I get the following error:
data member 'vec' cannot be a member template
What did I do wrong?
Edit:
I don't know that I was understood correctly, I am trying to declare a vector which contains a template, I know that this can be done as one can have the following:
template <class T>
void funct(vector <T> v){
}
this function takes a vector of a template as it's parameter, I wish to do the same thing except with declaring the vector in a header in order to allow the vector to contain anything.
The template <>
statement is only used when declaring a function template or a class template. For example you can use it when you declare (and define) a class:
template <typename T>
class TemplateClass {
/* definition */
};
Or a function:
template <typename T>
void templateFunc(T value) {
/* definition */
}
When creating an instance of the class, you can't use the template <>
statement. Instead you specify a template parameter like this:
TemplateClass<int> tc;
And when calling a template function:
int i = 1;
templateFunc(i); // <-- Automatic template deduction to int.
Such vector can't contain anything. Let's suppose that a compiler let you declare such a vector, and you write a code like
//...
A Aobj;
vec.push_back(Aobj);
//...
Then size of one element in the vec will be the sizeof(A)
. But next you writes
//...
B Bobj;
vec.push_back(Bobj);
//...
What the size of one element here should be?
Anyway, as a workaround you may declare vector<void*> vec
this going to contain a pointers to anything you wanted.
Vector always need a class T as template. But the template should be put ahead of class declaration.
You probably mean
template<class T>
class A {
private:
std::vector<T> vec;
};
This answer applies to C++11 and earlier
There is no such thing as templated data members. The only sorts of templates are class template and function template. Your other example is a function template.
Try and think about how someone would instantiate your class. Suppose it was legal to do:
struct S
{
template<typename T>
T x;
};
int main()
{
S s;
s.x = ????
}
The type of S
must be known in order to do S s;
, it can't magically change to accommodate whatever type you decide to give to x
. In fact you couldn't even evaluate s.x
.
To solve your problem you have to make the template parameter be a template parameter of the class containing the data member, e.g.:
template<typename T>
struct S
{
vector<T> vec;
};
int main()
{
S<int> s;
s.vec = vector<int>(5);
}