Let's say i acquire the name of a class that i made as a String
. How can i Instantiate the class with the name contained in that string? I I know it will be derived from a certain parent class, but the actual class will vary.
可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效,请关闭广告屏蔽插件后再试):
问题:
回答1:
var instance : MyClass = Type.createInstance(Type.resolveClass("path.to.MyClass"), []);
Few notes:
resolveClass()
takes the full path (packages included) of the classe you needcreateInstance()
takes as the second argument an array of values that are applied to the constructor. Those values must be in the exact number and must be passed even if they are optional (nulls are good in that case).