I have a file that looks as below:
{
"repositories": [
{
"id": "156c48fc-f208-43e8-a631-4d12deb89fa4",
"namespace": "rhel12",
"namespaceType": "organization",
"name": "rhel6.6",
"shortDescription": "",
"visibility": "public"
},
{
"id": "f359b5d2-cb3a-4bb3-8aff-d879d51f1a04",
"namespace": "rhel12",
"namespaceType": "organization",
"name": "rhel7",
"shortDescription": "",
"visibility": "public"
}
]
}
I want to get only name values with each of them in a new line so that I can use while read -r line
.
I need only
rhel6.6
rhel7
I am using jq as follows which doesn't seem to work:
jq -r '.[].name'
Please suggest correct use of jq here
You need to combine filters by means of |
operator:
$ jq -r '.[] | .[] | .name' test.json
rhel6.6
rhel7
The first .[]
fetches repositories
array. The next .[]
fetches all the items of the repositories
array. Finally, .name
extracts properties from the array items(objects).
Note, the first .[]
works on object because it is a documented feature:
.[]
If you use the .[index] syntax, but omit the index entirely, it
will return all of the elements of an array...
You can also use this on an object, and it will return all the
values of the object.
You want to look at the repositories array instead of treating the input as an array:
$ jq -r '.repositories[].name' file
rhel6.6
rhel7
Here is another solution. Assuming the requirements
I want to get only name values with each of them in a new line so that I can use while read -r line.
Can you please how can i get output in format rhel12/rhel6.6 In other words, I need o/p in format namespace/name
if the data is in data.json
then the command
jq -M -r '.repositories[] | "\(.namespace)/\(.name)"' data.json
should produce
rhel12/rhel6.6
rhel12/rhel7