Enable/Disable a dropdownbox in jquery

2019-01-08 16:49发布

问题:

I am new to jQuery and I want to enable and disable a dropdown list using a checkbox. This is my html:

<select id="dropdown" style="width:200px">
    <option value="feedback" name="aft_qst">After Quest</option>
    <option value="feedback" name="aft_exm">After Exam</option>
</select>
<input type="checkbox" id="chkdwn2" value="feedback" />

What jQuery code do I need to do this? Also searching for a good jQuery documentation/study material.

回答1:

Here is one way that I hope is easy to understand:

http://jsfiddle.net/tft4t/

$(document).ready(function() {
 $("#chkdwn2").click(function() {
   if ($(this).is(":checked")) {
      $("#dropdown").prop("disabled", true);
   } else {
      $("#dropdown").prop("disabled", false);  
   }
 });
});


回答2:

Try -

$('#chkdwn2').change(function(){
    if($(this).is(':checked'))
        $('#dropdown').removeAttr('disabled');
    else
        $('#dropdown').attr("disabled","disabled");
})


回答3:

I am using JQuery > 1.8 and this works for me...

$('#dropDownId').attr('disabled', true);


回答4:

$("#chkdwn2").change(function(){
       $("#dropdown").slideToggle();
});

JsFiddle



回答5:

try this

 <script type="text/javascript">
        $(document).ready(function () {
            $("#chkdwn2").click(function () {
                if (this.checked)
                    $('#dropdown').attr('disabled', 'disabled');
                else
                    $('#dropdown').removeAttr('disabled');
            });
        });
    </script>


回答6:

To enable/disable -

$("#chkdwn2").change(function() { 
    if (this.checked) $("#dropdown").prop("disabled",true);
    else $("#dropdown").prop("disabled",false);
}) 

Demo - http://jsfiddle.net/tTX6E/



回答7:

$("#chkdwn2").change(function() { 
    if (this.checked) $("#dropdown").prop("disabled",'disabled');
}) 


回答8:

$(document).ready(function() {
 $('#chkdwn2').click(function() {
   if ($('#chkdwn2').prop('checked')) {
      $('#dropdown').prop('disabled', true);
   } else {
      $('#dropdown').prop('disabled', false);  
   }
 });
});

making use of .prop in the if statement.



回答9:

A better solution without if-else:

$(document).ready(function() {
    $("#chkdwn2").click(function() {
        $("#dropdown").prop("disabled", this.checked);  
    });
});