In an answer there was the following code:
if (std::ifstream input("input_file.txt"))
;
Which seems convenient, limiting the scope of the 'input' variable to where it's confirmed to be valid, however neither VS2015 nor g++ seems to compile it. Is it some compiler specific thing or does it require some extra flags?
In VS2015 the IDE highlights "std::ifstream" and the "input_file.txt" as well as the last parentheses. "std::ifstream" is flagged with "Error: a function type is not allowed here".
VS2015 C++ compiler gives following errors:
- C4430 missing type specifier - int assumed. Note: C++ does not support default-int
- C2059 syntax error: '('
The code you have is not legal.. yet. Prior to C++11 a if statement could be
if(condition)
if(type name = initializer)
and name
would be evaluated as a bool
to determine the condition. In C++11/14 the rules expended to allow
if(condition)
if(type name = initializer)
if(type name{initializer})
Where, again, name
is evaluted as a bool
after it is initialized to determine the condition.
Starting in C++17 though you will be able to declare a variable in a if statement as a compound statement like a for loop which allows you to initialize the variable with parentheses.
if (std::ifstream input("input_file.txt"); input.is_open())
{
// do stuff with input
}
else
{
// do other stuff with input
}
It should be noted though that this is just syntactic sugar and the above code is actually translated to
{
std::ifstream input("input_file.txt")
if (input.is_open())
{
// do stuff with input
}
else
{
// do other stuff with input
}
}
According to http://en.cppreference.com/w/cpp/language/if that code is not legal (This site is pretty reputable but I can hunt for the standard reference if desired). You can declare variables in an if condition but they must be initialized by =
or {}
. So assuming you have at least C++11 you can do:
if (std::ifstream input{"input_file.txt"})
;