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Django: get URL of current page, including parameters, in a template
6 answers
Firstly, I want to say that I'm a beginner in Django.
I'm looking for a simple way to retrieve the domain name of my Django website.
I want to do this in my settings.py. I've already tried with the socket something like this:
socket.gethostname()
but this doesn't work correctly.
If you have a request object,do
request.META['HTTP_HOST']
This would return the hostname
If you're using django.contrib.sites
framework:
from django.contrib.sites.models import Site
your_domain = Site.objects.get_current().domain
Reference: https://docs.djangoproject.com/en/1.8/ref/contrib/sites/
import platform
platform.node()
from the docs:
"Returns the computer’s network name (may not be fully qualified!). An
empty string is returned if the value cannot be determined."