Using OR & AND in COUNTIFS

问题:

I would like to include an "AND" condition for one of the conditions I have in my COUNTIFS clause.

Something like this:

=COUNTIFS(A1:A196;{"Yes"or "NO"};J1:J196;"Agree")

So, it should return the number of rows where:

 (A1:A196 is either "yes" or "no") AND (J1:j196 is "agree")

回答1:

You could just add a few COUNTIF statements together:

=COUNTIF(A1:A196,"yes")+COUNTIF(A1:A196,"no")+COUNTIF(J1:J196,"agree")

This will give you the result you need.

EDIT

Sorry, misread the question. Nicholas is right that the above will double count. I wasn't thinking of the AND condition the right way. Here's an alternative that should give you the correct results, which you were pretty close to in the first place:

=SUM(COUNTIFS(A1:A196,{"yes","no"},J1:J196,"agree"))

回答2:

There is probably a more efficient solution to your question, but following formula should do the trick:

=SUM(COUNTIFS(J1:J196,"agree",A1:A196,"yes"),COUNTIFS(J1:J196,"agree",A1:A196,"no"))

回答3:

In a more general case:

N( A union B) = N(A) + N(B) - N(A intersect B) 
= COUNTIFS(A1:A196,"Yes",J1:J196,"Agree")+COUNTIFS(A1:A196,"No",J1:J196,"Agree")-A1:A196,"Yes",A1:A196,"No")

回答4:

One solution is doing the sum:

=SUM(COUNTIFS(A1:A196,{"yes","no"},B1:B196,"agree"))

or know its not the countifs but the sumproduct will do it in one line:

=SUMPRODUCT(((A1:A196={"yes","no"})*(j1:j196="agree")))

回答5:

i found i had to do something akin to

=(countifs (A1:A196,"yes", j1:j196, "agree") + (countifs (A1:A196,"no", j1:j196, "agree"))

回答6:

Using array formula.

=SUM(COUNT(IF(D1:D5="Yes",COUNT(D1:D5),"")),COUNT(IF(D1:D5="No",COUNT(D1:D5),"")),COUNT(IF(D1:D5="Agree",COUNT(D1:D5),"")))

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