Java HashSet equivalent in c++

问题:

I was curious if there was something akin the the Java hashset in c++. I.e a data structure with fast look, as I will only be running .contains(e) on it. Likewise, if you could enlighten me on how to do a .contains() on whatever data structure you propose, I would be very appreciative. O, please do not post just look at the c++ docs as I have already done so and find them burdensome.

回答1:

You can use std::unordered_set<> (standard § 23.5.6), its find method (to do a lookup) as an average complexity of O(1) :

#include <iostream>
#include <unordered_set>

int main()
{  
    std::unordered_set<int> example = {1, 2, 3, 4};

    auto search = example.find(2);
    if(search != example.end()) {
        std::cout << "Found " << (*search) << '\n';
    }
    else {
        std::cout << "Not found\n";
    }
}

EDIT:

As suggested by @Drew Dormann, you can alternatively use count, which also has a average complexity of O(1):

#include <iostream>
#include <unordered_set>

int main()
{  
    std::unordered_set<int> example = {1, 2, 3, 4};

    if(example.count(2)) {
        std::cout << "Found\n";
    }
    else {
        std::cout << "Not found\n";
    }
}