Why unhandled exception in a background thread doe

问题:

I am completely puzzled. I was so sure that .NET shuts the whole application domain if there is uncaught exception in a thread that I never tested this.

However I just tried the following code and it doesn't fail... Could anyone please explain why?

(Tried in .NET 4 and 3.5)

static void Main(string[] args)
{
    Console.WriteLine("Main thread {0}", Thread.CurrentThread.ManagedThreadId);

    Action a = new Action(() =>
    {
        Console.WriteLine("Background thread {0}", Thread.CurrentThread.ManagedThreadId);

        throw new ApplicationException("test exception");
    });

    a.BeginInvoke(null, null);

    Console.ReadLine();
}

回答1:

This is happening because the BeginInvoke uses ThreadPool internally and when ThreadPool any unhadled exceptions will be silence fail. However if you use a.EndInvoke then the unhadled exception will be throw at the EndInvoke method.

Note: as João Angelo stated that using ThreadPool methods directly "like ThreadPool.QueueUserWorkItems and UnsafeQueueUserWorkItem" will throw exceptions at 2.0 and above.

回答2:

From Exceptions in Managed Threads on MSDN:

In the .NET Framework version 2.0, the common language runtime allows most unhandled exceptions in threads to proceed naturally. In most cases this means that the unhandled exception causes the application to terminate.

This is a significant change from the .NET Framework versions 1.0 and 1.1, which provide a backstop for many unhandled exceptions — for example, unhandled exceptions in thread pool threads. See Change from Previous Versions later in this topic.

As a temporary compatibility measure, administrators can place a compatibility flag in the section of the application configuration file. This causes the common language runtime to revert to the behavior of versions 1.0 and 1.1.

<legacyUnhandledExceptionPolicy enabled="1"/>

回答3:

Normally with asynchronous delegates if the delegated method throws an exception the thread is terminated and the exception will be thrown again in the calling code only when you call EndInvoke.

This is why when using an asynchronous delegate (BeginInvoke) you should always call EndInvoke. Also, this should not be confused with Control.BeginInvoke which can be called in a fire and forget manner.

Earlier I said normally, because there is a possibility for you to state that the exception should be ignored if the delegate method returns void. To do this you need to mark the method with the OneWay attribute.

If you run the following example, you will only get an exception when calling willNotIgnoreThrow.EndInvoke.

static void Throws()
{
    Console.WriteLine("Thread: {0}", Thread.CurrentThread.ManagedThreadId);

    throw new ApplicationException("Test 1");
}

[OneWay]
static void ThrowsButIsIgnored()
{
    Console.WriteLine("Thread: {0}", Thread.CurrentThread.ManagedThreadId);

    throw new ApplicationException("Test 2");
}

static void Main(string[] args)
{
    Console.WriteLine("Main: {0}", Thread.CurrentThread.ManagedThreadId);

    var willIgnoreThrow = new Action(ThrowsButIsIgnored);
    var result1 = willIgnoreThrow.BeginInvoke(null, null);

    Console.ReadLine();
    willIgnoreThrow.EndInvoke(result1);

    Console.WriteLine("============================");

    var willNotIgnoreThrow = new Action(Throws);
    var result2 = willNotIgnoreThrow.BeginInvoke(null, null);

    Console.ReadLine();
    willNotIgnoreThrow.EndInvoke(result2);
}

回答4:

because exception throw on the given threads stays there unless it is channeled back to the main thread.

That's what backgroundWorker does it for you, if you have exception in the BackgroundWorker's thread, it gets rethrown on the main thread.

a.BeginInvoke(null, null);

this makes async call, which creates another thread to execute this