Check if input is number or letter javascript

问题:

I'm using forms in HTML and javascript. I would like an alert to pop up only if the user inputs a LETTER and clicks submit.

So I have the HTML code:

<form name="myForm" action="" onsubmit="return checkInp()" method="post">
    First name: <input type="text" name="age">
<input type="submit" value="Submit">   

And the javascript code:

function checkInp()
{
var x=document.forms["myForm"]["age"].value;
if (x consists of any letters) // this is the code I need to change
{
alert("Must input numbers");
return false;
}
}

回答1:

You can use the isNaN function to determine if a value does not convert to a number. Example as below:

function checkInp()
{
  var x=document.forms["myForm"]["age"].value;
  if (isNaN(x)) 
  {
    alert("Must input numbers");
    return false;
  }
}

回答2:

Use Regular Expression to match for only letters. It's also good to have knowledge about, if you ever need to do something more complicated, like make sure it's a certain count of numbers.

function checkInp()
{
    var x=document.forms["myForm"]["age"].value;
    var regex=/^[a-zA-Z]+$/;
    if (!x.match(regex))
    {
        alert("Must input string");
        return false;
    }
}

Even better would be to deny anything but numbers:

function checkInp()
{
    var x=document.forms["myForm"]["age"].value;
    var regex=/^[0-9]+$/;
    if (x.match(regex))
    {
        alert("Must input numbers");
        return false;
    }
}

回答3:

You could use the isNaN Function. It returns true if the data is not a number. That would be something like that:

function checkInp()
{
    var x=document.forms["myForm"]["age"].value;
    if (isNaN(x)) // this is the code I need to change
    {
        alert("Must input numbers");
        return false;
    }
}

Note: isNan considers 10.2 as a valid number.

回答4:

you can use isNaN(). it returns true when data is not number.

var data = 'hello there';
if(isNaN(data)){
  alert("it is not number");
}else {
  alert("its a valid number");
}

回答5:

Try this:

if(parseInt("0"+x, 10) > 0){/* x is integer */}

回答6:

Just find the remainder by dividing by 1, that is x%1. If the remainder is 0, it means that x is a whole number. Otherwise, you have to display the message "Must input numbers". This will work even in the case of strings, decimal numbers etc.

function checkInp()
{
    var x = document.forms["myForm"]["age"].value;
    if ((x%1) != 0) 
    {
        alert("Must input numbers");
        return false;
    }
}

回答7:

A better(error-free) code would be like:

function isReallyNumber(data) {
    return typeof data === 'number' && !isNaN(data);
}

This will handle empty strings as well. Another reason, isNaN("12") equals to false but "12" is a string and not a number, so it should result to true. Lastly, a bonus link which might interest you.

回答8:

function isNumber(data){
    data = data +"e1";                      // Disallow eng. notation "10e2"+"e1" is NaN
    var clean = parseFloat(data,10) / data ; // 1 if parsed cleanly
    return (clean && (data/data) === 1.0);  // Checks for NaN
}

function isInteger(data){
    data = data +"e1";                      // Disallow eng. notation "10e2"+"e1" is NaN
    var clean = parseInt(data,10) / data ; // 1 if parsed cleanly
    return (clean && (data%1) === 0);          // Checks For integer and NaN
}

回答9:

I know this post is old but it was the first one that popped up when I did a search. I tried @Kim Kling RegExp but it failed miserably. Also prior to finding this forum I had tried almost all the other variations listed here. In the end, none of them worked except this one I created; it works fine, plus it is es6:

    let regex = new RegExp(/[^0-9]/, 'g');
    let x = document.forms["myForm"]["age"].value;

    if (x.match(regex)) {
       alert("Must be a valid number");
            return
    }

回答10:

I think the easiest would be to create a Number object with the string and check if with the help of isInteger function provided by Number class itself.

Number.isInteger(Number('1')) //true
Number.isInteger(Number('1 mango')) //false
Number.isInteger(Number(1)) //true
Number.isInteger(Number(1.9)) //false

回答11:

The best and modern way is typeof (variable) if you care about real number not number from string. For example:

var a = 1;
var b = '1';

typeof a: // Output: "number"
typeof b: // Output: "string