FluentAssertions: equivalence of sorted lists

问题:

I'm trying to establish equivalence of two lists using FluentAssertions in C#, where two things are of importance:

1. the elements are compared by the values they hold, not by reference (i.e. they are equivalent, not equal)
2. the order of the elements in the lists is important

Is there no function in FluentAssertions (or even NUnit) that does this?

Cheers!

回答1:

By default, ShouldBeEquivalentTo() will ignore the order in the collections because in most cases two collections are equivalent if they contain the same items in any order. If you do care about the order, just use one of the overloads of WithStrictOrdering() on the options => parameter.

Example:

var myList = Enumerable.Range(1, 5);
var expected = new[]
{
    1, 2, 3, 4, 5
};

//succeeds
myList.ShouldBeEquivalentTo(expected, options => options.WithStrictOrdering());

//fails
myList.Reverse().ShouldBeEquivalentTo(expected, options => options.WithStrictOrdering());

Read more about these options in the documentation.

回答2:

Late to the game here but I use the Fluent Assertions version of this here:

actualRows.ShouldBeEquivalentTo(expectedRows,options => options.WithStrictOrdering());

It will check all the values of all the properties for equivalence, and with this option set order counts. If order does not matter in which case omit the options param and it will make sure the item from one colection will exist somewhere in the other. Hope this helps someone

回答3:

I think you can just do:

myObject.List.SequenceEqual(myOtherObject.ListToCompare).Should().BeTrue();

This will only work if the elements in the list are equal when using Object.Equal(element1, element2)

if this is not the case then you need to implement your own EqualityComparer for the objedts in the lists then use:

myObject.List.SequenceEqual(myOtherObject.ListToCompare, myEqualityComparer)
             .Should().BeTrue();

回答4:

During my struggle with similar task found out about next method:

IEnumerable collection = new[] { 1, 2, 5, 8 };

collection
    .Should()
    .ContainInOrder(new[] { 1, 5, 8 });

Collection Assertions Docs

回答5:

You want the ShouldAllBeEquivalentTo method, that should compare the values of the properties of the two object graphs in a list.

*Edit: I'd probably use the Linq Sequence equal with a custom equality comparer that uses ShouldBeEquivalentTo to care about the order of the elements.

回答6:

I believe no. But you can always write an extension methon for that purpose. I.e.

    public static void AreEqual<T>(this IList<T> left, IList<T> right)
    {
        Assert.AreEqual(left.Count, right.Count);

        for (int i = 0; i < left.Count - 1; i++)
        {
            Assert.IsTrue(left[i].Equals(right[i]));
        }
    }

回答7:

The Microsoft.VisualStudio.TestTools.UnitTesting.CollectionAssert class may have a method responding to your needs.

CollectionAssert.AreEqual Method (ICollection, ICollection, IComparer) should do the trick.

Two collections are equal if they have the same elements in the same order and quantity. Elements are equal if their values are equal, not if they refer to the same object.