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问题:
Suppose there are objects making subscriptions to a socket server like so:
socket.on('news', obj.socketEvent)
These objects have a short life span and are frequently created, generating many subscriptions. This seems like a memory leak and an error prone situation which would intuitively be prevented this way:
socket.off('news', obj.socketEvent)
before the object is deleted, but alas, there isn't an off
method in the socket. Is there another method meant for this?
Edit: having found no answer I'm assigning a blank method to overwrite the wrapper method for the original event handler, an example follows.
var _blank = function(){};
var cbProxy = function(){
obj.socketEvent.apply(obj, arguments)
};
var cbProxyProxy = function(){
cbProxy.apply ({}, arguments)
}
socket.on('news', cbProxyProxy);
// ...and to unsubscribe
cbProxy = _blank;
回答1:
From looking at the source of socket.io.js (couldn't find it in documentation anywhere), I found these two functions:
removeListener = function(name, fn)
removeAllListeners = function(name)
I used removeAllListeners
successfully in my app; you should be able to choose from these:
socket.removeListener("news", cbProxy);
socket.removeAllListeners("news");
Also, I don't think your solution of cbProxy = _blank
would actually work; that would only affect the cbProxy
variable, not any actual socket.io event.
回答2:
If you want to create listeners that "listens" only once use socket.once('news',func)
. Socket.io automatically will distroy the listener after the event happened - it's called "volatile listener".
回答3:
Looking at the code of current version of Socket.io Client (1.4.8) it seems that off, removeAllListeners, removeEventListener are all pointing to the same function.
Calling any of those, providing event name and/or callback, gives the desired result. Not providing anything at all seems to reset everything.
Please do be cautious about the fn/callback argument. It has to be the same instance used in the code.
Example:
var eventCallback = function(data) {
// do something nice
};
socket.off('eventName', eventCallback);
Would work as expected.
Example (will also work):
function eventCallback(data) {
// do something nice
}
socket.off('eventName', eventCallback);
Please be cautious that the callback you are trying to remove is the one that you passed in (this one can bring a lot of confusion and frustration).
This example implements a wrapper around initial callback, trying to remove that would not work as the real callback being added is an undisclosed closure instance: http://www.html5rocks.com/en/tutorials/frameworks/angular-websockets/
Here is the link to that specific line in the codebase: https://github.com/socketio/socket.io-client/blob/master/socket.io.js#L1597
回答4:
Socket.io version 0.9.16 implements removeListener
but not off
.
You can use removeListener
instead of off
when unsubscribing, or simply implement off
as follows:
var socket = io.connect(url);
socket.off = socket.removeListener;
If you are using the Backbone listenTo
event subscription approach, you'll need to implement the above as Backbone calls off
when unsubscribing events.
回答5:
I found that in socket.io 0.9.11 and Chrome24 socket.io removeListener doesn't work.
this modified version works for me:
EventEmitter.prototype.removeListener = function (name, fn) {
if (this.$events && this.$events[name]) {
var list = this.$events[name];
if (io.util.isArray(list)) {
var pos = -1;
for (var i = 0, l = list.length; i < l; i++) {
if (list[i].toString() === fn.toString() || (list[i].listener && list[i].listener === fn)) {
pos = i;
break;
}
}
if (pos < 0) {
return this;
}
list.splice(pos, 1);
if (!list.length) {
delete this.$events[name];
}
} else {
if (list.toString() === fn.toString() || (list.listener && list.listener === fn)) {
delete this.$events[name];
}
}
}
return this;
};
回答6:
Removing an event listener on the client
var Socket = io.connect();
Socket.removeListener('test', test);
回答7:
Since I had a spot of troubles making this work figured I'd chime in here as well, along with a nice updated answer for 2017. Thanks to @Pjotr for pointing out that it has to be the same callback instance.
Example with Angular2 TypeScript in a socket-io.subscriber service. Note the "newCallback" wrapper
private subscriptions: Array<{
key: string,
callback: Function
}>;
constructor() {
this.subscriptions = [];
}
subscribe(key: string, callback: Function) {
let newCallback = (response) => callback(response);
this.socket.on(key, newCallback);
return this.subscriptions.push({key: key, callback: newCallback}) - 1;
}
unsubscribe(i: number) {
this.socket.removeListener(this.subscriptions[i].key, this.subscriptions[i].callback);
}
回答8:
To add to @Andrew Magee, here is an example of unsubscribing socket.io events in Angular JS, and of course works with Vanilla JS:
function handleCarStarted ( data ) { // Do stuff }
function handleCarStopped ( data ) { // Do stuff }
Listen for events:
var io = $window.io(); // Probably put this in a factory, not controller instantiation
io.on('car.started', handleCarStarted);
io.on('car.stopped', handleCarStopped);
$scope.$on('$destroy', function () {
io.removeListener('car.started', handleCarStarted);
io.removeListener('car.stopped', handleCarStopped);
});
回答9:
Also on java
client, it can be done the same way with the Javascript client. I've pasted from socket.io.
// remove all listeners of the connect event
socket.off(Socket.EVENT_CONNECT);
listener = new Emitter.Listener() { ... };
socket.on(Socket.EVENT_CONNECT, listener);
// remove the specified listener
socket.off(Socket.EVENT_CONNECT, listener);