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问题:
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Random number generator only generating one random number
9 answers
I have the following code inside a static method in a static class:
Random r = new Random();
int randomNumber = r.Next(1,100);
I have this inside a loop and I keep getting the same randomNumber
!
Any suggestions here?
回答1:
You should not create a new Random
instance in a loop. Try something like:
var rnd = new Random();
for(int i = 0; i < 100; ++i)
Console.WriteLine(rnd.Next(1, 100));
The sequence of random numbers generated by a single Random
instance is supposed to be uniformly distributed. By creating a new Random
instance for every random number in quick successions, you are likely to seed them with identical values and have them generate identical random numbers. Of course, in this case, the generated sequence will be far from uniform distribution.
For the sake of completeness, if you really need to reseed a Random
, you\'ll create a new instance of Random
with the new seed:
rnd = new Random(newSeed);
回答2:
A good seed generation for me is:
Random rand = new Random(Guid.NewGuid().GetHashCode());
It is very random. The seed is always different because the seed is also random generated.
回答3:
In case you can\'t for some reason use the same Random
again and again, try initializing it with something that changes all the time, like the time itself.
new Random(new System.DateTime().Millisecond).Next();
Remember this is bad practice though.
EDIT: The default constructor already takes its seed from the clock, and probably better than we would. Quoting from MSDN:
Random() : Initializes a new instance of the Random class, using a time-dependent default seed value.
The code below is probably your best option:
new Random().Next();
回答4:
Bit late, but the implementation used by System.Random is Environment.TickCount
:
public Random()
: this(Environment.TickCount) {
}
This avoids having to cast DateTime.UtcNow.Ticks
from a long, which is risky anyway as it doesn\'t represent ticks since system start, but \"the number of 100-nanosecond intervals that have elapsed since 12:00:00 midnight, January 1, 0001 (0:00:00 UTC on January 1, 0001, in the Gregorian calendar)\".
Was looking for a good integer seed for the TestApi\'s StringFactory.GenerateRandomString
回答5:
public static Random rand = new Random(); // this happens once, and will be great at preventing duplicates
Note, this is not to be used for cryptographic purposes.
回答6:
this workes for me:
private int GetaRandom()
{
Thread.Sleep(1);
return new Random(DateTime.Now.Millisecond).Next();
}
回答7:
A good seed initialisation can be done like this
Random rnd = new Random((int)DateTime.Now.Ticks);
The ticks will be unique and the cast into a int with probably a loose of value will be OK.
回答8:
I use this for most situations, keep the seed if there is a need to repeat the sequence
var seed = (int) DateTime.Now.Ticks;
var random = new Random(seed);
or
var random = new Random((int)DateTime.Now.Ticks);