MongoDB: Updating documents using data from the sa

问题:

This question already has an answer here:

• Update MongoDB field using value of another field 6 answers

I have a list of documents, each with lat and lon properties (among others).

{ \'lat\': 1, \'lon\': 2, someotherdata [...] } 
{ \'lat\': 4, \'lon\': 1, someotherdata [...] }
[...]

I want to modify it so that it looks like this:

{ \'coords\': {\'lat\': 1, \'lon\': 2}, someotherdata [...]} 
{ \'coords\': {\'lat\': 4, \'lon\': 1}, someotherdata [...]}
[...]

So far I\'ve got this:

db.events.update({}, {$set : {\'coords\': {\'lat\': db.events.lat, \'lon\': db.events.lon}}}, false, true)

But it treats the db.events.lat and db.events.lon as strings. How can I reference the document\'s properties?

Cheers.

回答1:

The $rename operator (introduced a month after this question was posted) makes it really easy to do these kinds of things where you don\'t need to modify the values.

Insert some test documents

db.events.insert({ \'lat\': 1, \'lon\': 2, someotherdata: [] })
db.events.insert({ \'lat\': 4, \'lon\': 1, someotherdata: [] })

use the $rename operator

db.events.update({}, {$rename: {\'lat\': \'coords.lat\', \'lon\': \'coords.lon\'}}, false, true)

Results

db.events.find()
{
    \"_id\" : ObjectId(\"5113c82dd28c4e8b79971add\"),
    \"coords\" : {
        \"lat\" : 1,
        \"lon\" : 2
    },
    \"someotherdata\" : [ ]
}
{
    \"_id\" : ObjectId(\"5113c82ed28c4e8b79971ade\"),
    \"coords\" : {
        \"lat\" : 4,
        \"lon\" : 1
    },
    \"someotherdata\" : [ ]
}

回答2:

Update: If all you have to do is change the structure of a document without changing the values, see gipset\'s answer for a nice solution.

---

According to a (now unavailable) comment on the Update documentation page, you cannot reference the current document\'s properties from within an update().

You\'ll have to iterate through all the documents and update them like this:

db.events.find().snapshot().forEach(
  function (e) {
    // update document, using its own properties
    e.coords = { lat: e.lat, lon: e.lon };

    // remove old properties
    delete e.lat;
    delete e.lon;

    // save the updated document
    db.events.save(e);
  }
)

Such a function can also be used in a map-reduce job or a server-side db.eval() job, depending on your needs.

回答3:

We can use Mongo script to manipulate data on the fly. It works for me!

I use this script to correct my address data.

Example of current address: \"No.12, FIFTH AVENUE,\".

I want to remove the last redundant comma, the expected new address \"\"No.12, FIFTH AVENUE\".

var cursor = db.myCollection.find().limit(100);

while (cursor.hasNext()) {
  var currentDocument = cursor.next();

  var address = currentDocument[\'address\'];
  var lastPosition = address.length - 1;

  var lastChar = address.charAt(lastPosition);

  if (lastChar == \",\") {

    var newAddress = address.slice(0, lastPosition);


    currentDocument[\'address\'] = newAddress;

    db.localbizs.update({_id: currentDocument._id}, currentDocument);

  }
}

Hope this helps!

回答4:

As long as you are OK with creating a copy of the data, the aggregation framework can be used as an alternative here. You also have the option to do more to the data if you wish using other operators, but the only one you need is $project. It\'s somewhat wasteful in terms of space, but may be faster and more appropriate for some uses. To illustrate, I\'ll first insert some sample data into the foo collection:

db.foo.insert({ \'lat\': 1, \'lon\': 2, someotherdata : [1, 2, 3] })
db.foo.insert({ \'lat\': 4, \'lon\': 1, someotherdata : [4, 5, 6] })

Now, we just use $project to rework the lat and lon fields, then send them to the newfoo collection:

db.foo.aggregate([
    {$project : {_id : \"$_id\", \"coords.lat\" : \"$lat\", \"coords.lon\" : \"$lon\", \"someotherdata\" : \"$someotherdata\" }},
    { $out : \"newfoo\" }
])

Then check newfoo for our altered data:

db.newfoo.find()
{ \"_id\" : ObjectId(\"544548a71b5cf91c4893eb9a\"), \"someotherdata\" : [ 1, 2, 3 ], \"coords\" : { \"lat\" : 1, \"lon\" : 2 } }
{ \"_id\" : ObjectId(\"544548a81b5cf91c4893eb9b\"), \"someotherdata\" : [ 4, 5, 6 ], \"coords\" : { \"lat\" : 4, \"lon\" : 1 } }

Once you are happy with the new data, you can then use the renameCollection() command to drop the old data and use the new data under the old name:

> db.newfoo.renameCollection(\"foo\", true)
{ \"ok\" : 1 }
> db.foo.find()
{ \"_id\" : ObjectId(\"544548a71b5cf91c4893eb9a\"), \"someotherdata\" : [ 1, 2, 3 ], \"coords\" : { \"lat\" : 1, \"lon\" : 2 } }
{ \"_id\" : ObjectId(\"544548a81b5cf91c4893eb9b\"), \"someotherdata\" : [ 4, 5, 6 ], \"coords\" : { \"lat\" : 4, \"lon\" : 1 } }

One last note - until SERVER-7944 is completed you can\'t do the equivalent of a snapshot by hinting the _id index as suggested in this answer and so you can end up hitting a document more than once if activity elsewhere causes it to move. Since you are inserting the _id field in this example, any such occurrence would cause a unique key violation, so you will not end up with dupes, but you might have an \"old\" version of a document. As always, check your data thoroughly before dropping it, and preferably take a backup.

回答5:

Neils answer. Just to let people know you cannot run this on a large database if you are lets say doing it remote shell like Robomongo. You will need to ssh into your actual server\'s mongo shell. Also you could also do this if you would rather do an Update.

db.Collection.find({***/ possible query /***}).toArray().forEach(
  function(obj){
    obj.item = obj.copiedItem;
    obj.otherItem = obj.copiedItem;
    obj.thirdItem = true;
    obj.fourthItem = \"string\";
    db.Collection.update({_id: obj._id}, obj);
  }
);

回答6:

From the CLI? I think you have to pull the values out first and assign the value into a variable. Then run your update command.

Or (I haven\'t tried) remove \'db\' from the string. events.lat and events.lon If it works, you will still have multiple values, the old values for \"lat\" and \"lon\" and the new array you created.