What regular expression will match valid internati

问题:

I need to determine whether a phone number is valid before attempting to dial it. The phone call can go anywhere in the world.

What regular expression will match valid international phone numbers?

回答1:

\\+(9[976]\\d|8[987530]\\d|6[987]\\d|5[90]\\d|42\\d|3[875]\\d|
2[98654321]\\d|9[8543210]|8[6421]|6[6543210]|5[87654321]|
4[987654310]|3[9643210]|2[70]|7|1)\\d{1,14}$

Is the correct format for matching a generic international phone number. I replaced the US land line centric international access code 011 with the standard international access code identifier of \'+\', making it mandatory. I also changed the minimum for the national number to at least one digit.

Note that if you enter numbers in this format into your mobile phone address book, you may successfully call any number in your address book no matter where you travel. For land lines, replace the plus with the international access code for the country you are dialing from.

Note that this DOES NOT take into account national number plan rules - specifically, it allows zeros and ones in locations that national number plans may not allow and also allows number lengths greater than the national number plan for some countries (e.g., the US).

回答2:

All country codes are defined by the ITU. The following regex is based on ITU-T E.164 and Annex to ITU Operational Bulletin No. 930 – 15.IV.2009. It contains all current country codes and codes reserved for future use. While it could be shortened a bit, I decided to include each code independently.

This is for calls originating from the USA. For other countries, replace the international access code (the 011 at the beginning of the regex) with whatever is appropriate for that country\'s dialing plan.

Also, note that ITU E.164 defines the maximum length of a full international telephone number to 15 digits. This means a three digit country code results in up to 12 additional digits, and a 1 digit country code could contain up to 14 additional digits. Hence the

[0-9]{0,14}$

a the end of the regex.

Most importantly, this regex does not mean the number is valid - each country defines its own internal numbering plan. This only ensures that the country code is valid.

^011(999|998|997|996|995|994|993|992|991| 990|979|978|977|976|975|974|973|972|971|970| 969|968|967|966|965|964|963|962|961|960|899| 898|897|896|895|894|893|892|891|890|889|888| 887|886|885|884|883|882|881|880|879|878|877| 876|875|874|873|872|871|870|859|858|857|856| 855|854|853|852|851|850|839|838|837|836|835| 834|833|832|831|830|809|808|807|806|805|804| 803|802|801|800|699|698|697|696|695|694|693| 692|691|690|689|688|687|686|685|684|683|682| 681|680|679|678|677|676|675|674|673|672|671| 670|599|598|597|596|595|594|593|592|591|590| 509|508|507|506|505|504|503|502|501|500|429| 428|427|426|425|424|423|422|421|420|389|388| 387|386|385|384|383|382|381|380|379|378|377| 376|375|374|373|372|371|370|359|358|357|356| 355|354|353|352|351|350|299|298|297|296|295| 294|293|292|291|290|289|288|287|286|285|284| 283|282|281|280|269|268|267|266|265|264|263| 262|261|260|259|258|257|256|255|254|253|252| 251|250|249|248|247|246|245|244|243|242|241| 240|239|238|237|236|235|234|233|232|231|230| 229|228|227|226|225|224|223|222|221|220|219| 218|217|216|215|214|213|212|211|210|98|95|94| 93|92|91|90|86|84|82|81|66|65|64|63|62|61|60| 58|57|56|55|54|53|52|51|49|48|47|46|45|44|43| 41|40|39|36|34|33|32|31|30|27|20|7|1)[0-9]{0, 14}$

回答3:

This is a further optimisation.

\\+(9[976]\\d|8[987530]\\d|6[987]\\d|5[90]\\d|42\\d|3[875]\\d|
2[98654321]\\d|9[8543210]|8[6421]|6[6543210]|5[87654321]|
4[987654310]|3[9643210]|2[70]|7|1)
\\W*\\d\\W*\\d\\W*\\d\\W*\\d\\W*\\d\\W*\\d\\W*\\d\\W*\\d\\W*(\\d{1,2})$

(i) allows for valid international prefixes
(ii) followed by 9 or 10 digits, with any type or placing of delimeters (except between the last two digits)

This will match:
[phone]
[phone]
[phone]
[phone]
[phone]
+46.234.567.8901
+1/234/567/8901

回答4:

You can use the library libphonenumber from Google.

PhoneNumberUtil phoneNumberUtil = PhoneNumberUtil.getInstance();
String decodedNumber = null;
PhoneNumber number;
    try {
        number = phoneNumberUtil.parse(encodedHeader, null);
        decodedNumber = phoneNumberUtil.format(number, PhoneNumberFormat.E164);
    } catch (NumberParseException e) {
        e.printStackTrace();
    }

回答5:

Here\'s an \"optimized\" version of your regex:

^011(9[976]\\d|8[987530]\\d|6[987]\\d|5[90]\\d|42\\d|3[875]\\d|
2[98654321]\\d|9[8543210]|8[6421]|6[6543210]|5[87654321]|
4[987654310]|3[9643210]|2[70]|7|1)\\d{0,14}$

You can replace the \\ds with [0-9] if your regex syntax doesn\'t support \\d.

回答6:

I use this one:

/([0-9\\s\\-]{7,})(?:\\s*(?:#|x\\.?|ext\\.?|extension)\\s*(\\d+))?$/

Advantages: recognizes + or 011 beginnings, lets it be as long as needed, and handles many extension conventions. (#,x,ext,extension)

回答7:

This will work for international numbers;

C#:

@\"^((\\+\\d{1,3}(-| )?\\(?\\d\\)?(-| )?\\d{1,5})|(\\(?\\d{2,6}\\)?))(-| )?(\\d{3,4})(-| )?(\\d{4})(( x| ext)\\d{1,5}){0,1}$\"

JS:

/^((\\+\\d{1,3}(-| )?\\(?\\d\\)?(-| )?\\d{1,5})|(\\(?\\d{2,6}\\)?))(-| )?(\\d{3,4})(-| )?(\\d{4})(( x| ext)\\d{1,5}){0,1}$/

回答8:

For iOS SWIFT I found this helpful,

let phoneRegEx = \"^((\\\\+)|(00)|(\\\\*)|())[0-9]{3,14}((\\\\#)|())$\"

回答9:

Modified @Eric\'s regular expression - added a list of all country codes (got them from xxxdepy @ Github. I hope you will find it helpful:

/(\\+|00)(297|93|244|1264|358|355|376|971|54|374|1684|1268|61|43|994|257|32|229|226|880|359|973|1242|387|590|375|501|1441|591|55|1246|673|975|267|236|1|61|41|56|86|225|237|243|242|682|57|269|238|506|53|5999|61|1345|357|420|49|253|1767|45|1809|1829|1849|213|593|20|291|212|34|372|251|358|679|500|33|298|691|241|44|995|44|233|350|224|590|220|245|240|30|1473|299|502|594|1671|592|852|504|385|509|36|62|44|91|246|353|98|964|354|972|39|1876|44|962|81|76|77|254|996|855|686|1869|82|383|965|856|961|231|218|1758|423|94|266|370|352|371|853|590|212|377|373|261|960|52|692|389|223|356|95|382|976|1670|258|222|1664|596|230|265|60|262|264|687|227|672|234|505|683|31|47|977|674|64|968|92|507|64|51|63|680|675|48|1787|1939|850|351|595|970|689|974|262|40|7|250|966|249|221|65|500|4779|677|232|503|378|252|508|381|211|239|597|421|386|46|268|1721|248|963|1649|235|228|66|992|690|993|670|676|1868|216|90|688|886|255|256|380|598|1|998|3906698|379|1784|58|1284|1340|84|678|681|685|967|27|260|263)(9[976]\\d|8[987530]\\d|6[987]\\d|5[90]\\d|42\\d|3[875]\\d|2[98654321]\\d|9[8543210]|8[6421]|6[6543210]|5[87654321]|4[987654310]|3[9643210]|2[70]|7|1)\\d{4,20}$/

回答10:

There\'s obviously a multitude of ways to do this, as evidenced by all of the different answers given thus far, but I\'ll throw my $0.02 worth in here and provide the regex below, which is a bit more terse than nearly all of the above, but more thorough than most as well. It also has the nice side-effect of leaving the country code in $1 and the local number in $2.

^\\+(?=\\d{5,15}$)(1|2[078]|3[0-469]|4[013-9]|5[1-8]|6[0-6]|7|8[1-469]|9[0-58]|[2-9]..)(\\d+)$

回答11:

A simple version for european numbers, that matches numbers like 0034617393211 but also long ones as 004401484172842.

^0{2}[0-9]{11,}

Hope it helps :·)

回答12:

public static boolean validateInternationalPhoneNumberFormat(String phone) {
    StringBuilder sb = new StringBuilder(200);

    // Country code
    sb.append(\"^(\\\\+{1}[\\\\d]{1,3})?\");

    // Area code, with or without parentheses
    sb.append(\"([\\\\s])?(([\\\\(]{1}[\\\\d]{2,3}[\\\\)]{1}[\\\\s]?)|([\\\\d]{2,3}[\\\\s]?))?\");

    // Phone number separator can be \"-\", \".\" or \" \"

    // Minimum of 5 digits (for fixed line phones in Solomon Islands)
    sb.append(\"\\\\d[\\\\-\\\\.\\\\s]?\\\\d[\\\\-\\\\.\\\\s]?\\\\d[\\\\-\\\\.\\\\s]?\\\\d[\\\\-\\\\.\\\\s]?\\\\d[\\\\-\\\\.\\\\s]?\");

    // 4 more optional digits
    sb.append(\"\\\\d?[\\\\-\\\\.\\\\s]?\\\\d?[\\\\-\\\\.\\\\s]?\\\\d?[\\\\-\\\\.\\\\s]?\\\\d?$\");

    return Pattern.compile(sb.toString()).matcher(phone).find();
}

回答13:

Here is a regex for the following most common phone number scenarios. Although this is tailored from a US perspective for area codes it works for international scenarios.

1. The actual number should be 10 digits only.
2. For US numbers area code may be surrounded with parentheses ().
3. The country code can be 1 to 3 digits long. Optionally may be preceded by a + sign.
4. There may be dashes, spaces, dots or no spaces between country code, area code and the rest of the number.

5. A valid phone number cannot be all zeros.

   ^(?!\\b(0)\\1+\\b)(\\+?\\d{1,3}[. -]?)?\\(?\\d{3}\\)?([. -]?)\\d{3}\\3\\d{4}$
   

Explanation:

    ^ - start of expression  
    (?!\\b(0)\\1+\\b) - (?!)Negative Look ahead. \\b - word boundary around a \'0\' character. \\1 backtrack to previous capturing group (zero). Basically don\'t match all zeros.  
    (\\+?\\d{1,3}[. -]?)? - \'\\+?\' plus sign before country code is optional.\\d{1,3} - country code can be 1 to 3 digits long. \'[. -]?\' - spaces,dots and dashes are optional. The last question mark is to make country code optional.  
    \\(?\\d{3}\\)? - \'\\)?\' is to make parentheses optional. \\d{3} - match 3 digit area code.  
    ([. -]?) - optional space, dash or dot
    $ - end of expression

More examples and explanation - https://regex101.com/r/hTH8Ct/2/

回答14:

The international numbering plan is based on the ITU E.164 numbering plan. I guess that\'s the starting point to your regular expression.

I\'ll update this if I get around to create a regular expression based on the ITU E.164 numbering.

回答15:

This Regex Expression works for India, Canada, Europe, New Zealand, Australia, United States phone numbers, along with their country codes:

\"^(\\+(([0-9]){1,2})[-.])?((((([0-9]){2,3})[-.]){1,2}([0-9]{4,10}))|([0-9]{10}))$\"

回答16:

This works for me, without 00, 001, 0011 etc prefix though:

/^\\+*(\\d{3})*[0-9,\\-]{8,}/

回答17:

Even though this is not really using RegExp to get the job done - or maybe because of that - this looks like a nice solution to me: https://intl-tel-input.com/node_modules/intl-tel-input/examples/gen/is-valid-number.html

回答18:

Try the following API for phone number validation. Also this will return the Country, Area and Provider

demo https://libphonenumber.appspot.com/

git https://github.com/googlei18n/libphonenumber/releases/tag/v8.9.0

回答19:

Try this, it works for me.

^(00|\\+)[1-9]{1}([0-9][\\s]*){9,16}$

回答20:

I have used this below:

^(\\+|00)[0-9]{1,3}[0-9]{4,14}(?:x.+)?$

The format +CCC.NNNNNNNNNNxEEEE or 00CCC.NNNNNNNNNNxEEEE

Phone number must start with \'+\' or \'00\' for an international call. where C is the 1–3 digit country code,

N is up to 14 digits,

and E is the (optional) extension.

The leading plus sign and the dot following the country code are required. The literal “x” character is required only if an extension is provided.

回答21:

Try this, I do not know if there is any phone number longer than 12:

^(00|\\+){1}\\d{12}$