How to display multiple notifications in android

问题:

I am receiving only one notification and if there is another notification comes, it replaces the previous one and here is my code

private static void generateNotification(Context context, String message,
        String key) {
    int icon = R.drawable.ic_launcher;
    long when = System.currentTimeMillis();
    NotificationManager notificationManager = (NotificationManager) context
            .getSystemService(Context.NOTIFICATION_SERVICE);
    Notification notification = new Notification(icon, message, when);

    String title = context.getString(R.string.app_name);

    Intent notificationIntent = new Intent(context,
            FragmentOpenActivity.class);
    notificationIntent.putExtra(key, key);
    // set intent so it does not start a new activity
    notificationIntent.setFlags(Intent.FLAG_ACTIVITY_CLEAR_TOP
            | Intent.FLAG_ACTIVITY_SINGLE_TOP);
    PendingIntent intent = PendingIntent.getActivity(context, 0,
            notificationIntent, 0);
    notification.setLatestEventInfo(context, title, message, intent);
    notification.flags |= Notification.FLAG_AUTO_CANCEL;

    notification.defaults |= Notification.DEFAULT_SOUND;

    // notification.sound = Uri.parse("android.resource://" +
    // context.getPackageName() + "your_sound_file_name.mp3");
    notification.defaults |= Notification.DEFAULT_VIBRATE;
    notificationManager.notify(0, notification);

}

回答1:

just replace your line with this

 notificationManager.notify(Unique_Integer_Number, notification);

hope it will help you.

回答2:

Simple notification_id needs to be changable.

Just create random number for notification_id.

    Random random = new Random();
    int m = random.nextInt(9999 - 1000) + 1000;

or you can use this method for creating random number as told by tieorange (this will never get repeated):

    int m = (int) ((new Date().getTime() / 1000L) % Integer.MAX_VALUE);

and replace this line to add parameter for notification id as to generate random number

    notificationManager.notify(m, notification);

回答3:

Using Shared Preferences worked for me

SharedPreferences prefs = getSharedPreferences(Activity.class.getSimpleName(), Context.MODE_PRIVATE);
int notificationNumber = prefs.getInt("notificationNumber", 0);
...

notificationManager.notify(notificationNumber , notification);
SharedPreferences.Editor editor = prefs.edit();
notificationNumber++;
editor.putInt("notificationNumber", notificationNumber);
editor.commit();

回答4:

i guess this will help someone..
in below code "not_nu" is an random int.. PendingIntent and Notification have the same ID .. so that on each notification click the intent will direct to different activity..

private void sendNotification(String message,String title,JSONObject extras) throws JSONException {
   String id = extras.getString("actionParam");
    Log.e("gcm","id  = "+id);
    Intent intent = new Intent(this, OrderDetailActivty.class);
    intent.putExtra("id", id);
    intent.addFlags(Intent.FLAG_ACTIVITY_CLEAR_TOP);
    final int not_nu=generateRandom();
    PendingIntent pendingIntent = PendingIntent.getActivity(this, not_nu /* Request code */, intent,
            PendingIntent.FLAG_ONE_SHOT);

    Uri defaultSoundUri= RingtoneManager.getDefaultUri(RingtoneManager.TYPE_NOTIFICATION);
    NotificationCompat.Builder notificationBuilder = new NotificationCompat.Builder(this)
            .setSmallIcon(R.mipmap.ic_cart_red)
            .setContentTitle(title)
            .setContentText(message)
            .setAutoCancel(true)
            .setSound(defaultSoundUri)
            .setContentIntent(pendingIntent);

    NotificationManager notificationManager =
            (NotificationManager) getSystemService(Context.NOTIFICATION_SERVICE);

    notificationManager.notify(not_nu /* ID of notification */, notificationBuilder.build());
}
public int generateRandom(){
    Random random = new Random();
    return random.nextInt(9999 - 1000) + 1000;
}

回答5:

Replace your line with this.

notificationManager.notify((int) ((new Date().getTime() / 1000L) % Integer.MAX_VALUE), notification);

回答6:

At the place of uniqueIntNo put unique integer number like this:

mNotificationManager.notify(uniqueIntNo, builder.build());

回答7:

You need to add a unique ID to each of the notifications so that they do not combine with each other. You can use this link for your reference :

https://github.com/sanathe06/AndroidGuide/tree/master/ExampleCompatNotificationBuilder

回答8:

I solved my problem like this...

/**
     * Issues a notification to inform the user that server has sent a message.
     */
    private static void generateNotification(Context context, String message,
            String keys, String msgId, String branchId) {
        int icon = R.drawable.ic_launcher;
        long when = System.currentTimeMillis();
        NotificationCompat.Builder nBuilder;
        Uri alarmSound = RingtoneManager
                .getDefaultUri(RingtoneManager.TYPE_NOTIFICATION);
        nBuilder = new NotificationCompat.Builder(context)
                .setSmallIcon(R.drawable.ic_launcher)
                .setContentTitle("Smart Share - " + keys)
                .setLights(Color.BLUE, 500, 500).setContentText(message)
                .setAutoCancel(true).setTicker("Notification from smartshare")
                .setVibrate(new long[] { 100, 250, 100, 250, 100, 250 })
                .setSound(alarmSound);
        String consumerid = null;
        Integer position = null;
        Intent resultIntent = null;
        if (consumerid != null) {
            if (msgId != null && !msgId.equalsIgnoreCase("")) {
                if (key != null && key.equalsIgnoreCase("Yo! Matter")) {
                    ViewYoDataBase db_yo = new ViewYoDataBase(context);
                    position = db_yo.getPosition(msgId);
                    if (position != null) {
                        resultIntent = new Intent(context,
                                YoDetailActivity.class);
                        resultIntent.putExtra("id", Integer.parseInt(msgId));
                        resultIntent.putExtra("position", position);
                        resultIntent.putExtra("notRefresh", "notRefresh");
                    } else {
                        resultIntent = new Intent(context,
                                FragmentChangeActivity.class);
                        resultIntent.putExtra(key, key);
                    }
                } else if (key != null && key.equalsIgnoreCase("Message")) {
                    resultIntent = new Intent(context,
                            FragmentChangeActivity.class);
                    resultIntent.putExtra(key, key);
                }.
.
.
.
.
.
            } else {
                resultIntent = new Intent(context, FragmentChangeActivity.class);
                resultIntent.putExtra(key, key);
            }
        } else {
            resultIntent = new Intent(context, MainLoginSignUpActivity.class);
        }
        PendingIntent resultPendingIntent = PendingIntent.getActivity(context,
                notify_no, resultIntent, PendingIntent.FLAG_UPDATE_CURRENT);
        if (notify_no < 9) {
            notify_no = notify_no + 1;
        } else {
            notify_no = 0;
        }
        nBuilder.setContentIntent(resultPendingIntent);
        NotificationManager nNotifyMgr = (NotificationManager) context
                .getSystemService(context.NOTIFICATION_SERVICE);
        nNotifyMgr.notify(notify_no + 2, nBuilder.build());
    }

回答9:

Another way of doing it is take the current date convert it into long just take the last 4 digits. There is a high probability that the number will be unique.

    long time = new Date().getTime();
    String tmpStr = String.valueOf(time);
    String last4Str = tmpStr.substring(tmpStr.length() -5);
    int notificationId = Integer.valueOf(last4Str);

回答10:

Below is the code for pass unique notification id:

//"CommonUtilities.getValudeFromOreference" is the method created by me to get value from savedPreferences.
String notificationId = CommonUtilities.getValueFromPreference(context, Global.NOTIFICATION_ID, "0");
int notificationIdinInt = Integer.parseInt(notificationId);

notificationManager.notify(notificationIdinInt, notification);

// will increment notification id for uniqueness
notificationIdinInt = notificationIdinInt + 1;
CommonUtilities.saveValueToPreference(context, Global.NOTIFICATION_ID, notificationIdinInt + "");
//Above "CommonUtilities.saveValueToPreference" is the method created by me to save new value in savePreferences.

Reset notificationId in savedPreferences at specific range like i have did it at 1000. so it will not create any issues in future. Let me know if you need more detail information or any query. :)

回答11:

The problem is with your notificationId. Think it as an array index. Each time you update your notification, the notificationId is the place it takes to store value. As you are not incrementing your int value (in this case, your notificationId), this always replaces the previous one. The best solution I guess is to increment it just after you update a notification. And if you want to keep it persistent, then you can store the value of your notificationId in sharedPreferences. Whenever you come back, you can just grab the last integer value (notificationId stored in sharedPreferences) and use it.

回答12:

Use the following method in your code.

Method call :-

notificationManager.notify(getCurrentNotificationId(getApplicationContext()), notification);

Method:-

  *Returns a unique notification id.
         */

        public static int getCurrentNotificationId(Context iContext){

            NOTIFICATION_ID_UPPER_LIMIT = 30000; // Arbitrary number.

            NOTIFICATION_ID_LOWER_LIMIT = 0;
            SharedPreferences sharedPreferences       = PreferenceManager.getDefaultSharedPreferences(iContext);
        int previousTokenId                       = sharedPreferences.getInt("currentNotificationTokenId", 0);

        int currentTokenId                        = previousTokenId+1;

        SharedPreferences.Editor editor           = sharedPreferences.edit();

        if(currentTokenId<NOTIFICATION_ID_UPPER_LIMIT) {

            editor.putInt("currentNotificationTokenId", currentTokenId); // }
        }else{
            //If reaches the limit reset to lower limit..
            editor.putInt("currentNotificationTokenId", NOTIFICATION_ID_LOWER_LIMIT);
        }

        editor.commit();

        return currentTokenId;
    }

回答13:

A simple counter may solve your problem.

private Integer notificationId = 0;

private Integer incrementNotificationId() {
   return notificationId++;
}

NotificationManager.notify(incrementNotificationId, notification);

回答14:

declare class member
static int i = 0;

mNotificationManager.notify(++i, mBuilder.build());

回答15:

val notifyIdLong = ((Date().time / 1000L) % Integer.MAX_VALUE)
var notifyIdInteger = notifyIdLong.toInt()
if (notifyIdInteger < 0) notifyIdInteger = -1  * notifyIdInteger // if it's -ve change to positive
notificationManager.notify(notifyIdInteger, mBuilder.build())
log.d(TAG,"notifyId = $notifyIdInteger")