I open a web page with QWebView.load(QUrl(myurl)) , the webpage gets some input and returns a new php generated page.
If executed in Firefox the browser automatically opens a new tab/window to show the returned page.
How to tell QWebView to open a new instance of QWebview with the returned data loaded?
I was looking at at the QwebView documentation at
www.riverbankcomputing.co.uk/static/Docs/PyQt4/html/qwebview.html ... but no joy.
Example of such a page :
http://www.iqfront.com/index.php?option=com_content&view=article&id=5&Itemid=4
Thanks for any ideas.
from my understanding this is developer's job to create and open new tabs for urls clicked.You would need to define a custom slot for QWebView::linkClicked signal. This signal is emitted whenever the user clicks on a link and the page's linkDelegationPolicy property is set to delegate the link handling for the specified url. There you can create a new instance of QWebView add it a tab and open new url there. Below is an example:
import sys
from PyQt4 import QtGui, QtCore, QtWebKit
class MainForm(QtGui.QMainWindow):
def __init__(self, parent=None):
super(MainForm, self).__init__(parent)
self.tabWidget = QtGui.QTabWidget(self)
self.setCentralWidget(self.tabWidget)
self.loadUrl(QtCore.QUrl('http://qt.nokia.com/'))
def loadUrl(self, url):
view = QtWebKit.QWebView()
view.connect(view, QtCore.SIGNAL('loadFinished(bool)'), self.loadFinished)
view.connect(view, QtCore.SIGNAL('linkClicked(const QUrl&)'), self.linkClicked)
view.page().setLinkDelegationPolicy(QtWebKit.QWebPage.DelegateAllLinks)
self.tabWidget.setCurrentIndex(self.tabWidget.addTab(view, 'loading...'))
view.load(url)
def loadFinished(self, ok):
index = self.tabWidget.indexOf(self.sender())
self.tabWidget.setTabText(index, self.sender().url().host())
def linkClicked(self, url):
self.loadUrl(url)
def main():
app = QtGui.QApplication(sys.argv)
form = MainForm()
form.show()
app.exec_()
if __name__ == '__main__':
main()
hope this helps, regards