Generating random numbers with Swift

问题:

I need to generate a random number.

It appears the arc4random function no longer exists as well as the arc4random_uniform function.

The options I have are arc4random_stir(), arc4random_buf(UnsafeMutablePointer<Void>, Int), and arc4random_addrandom(UnsafeMutablePointer<UInt8>, Int32).

I can't find any docs on the functions and no comments in the header files give hints.

回答1:

===== Swift 4.2 / Xcode 10 =====

let randomIntFrom0To10 = Int.random(in: 1..<10)
let randomFloat = Float.random(in: 0..<1)

// if you want to get a random element in an array
let greetings = ["hey", "hi", "hello", "hola"]
greetings.randomElement()

Under the hood Swift uses arc4random_buf to get job done.

===== Swift 4.1 / Xcode 9 =====

arc4random() returns a random number in the range of 0 to 4 294 967 295

drand48() returns a random number in the range of 0.0 to 1.0

arc4random_uniform(N) returns a random number in the range of 0 to N - 1

Examples:

arc4random() // => UInt32 = 2739058784
arc4random() // => UInt32 = 2672503239
arc4random() // => UInt32 = 3990537167
arc4random() // => UInt32 = 2516511476
arc4random() // => UInt32 = 3959558840

drand48() // => Double = 0.88642843322303122
drand48() // => Double = 0.015582849408328769
drand48() // => Double = 0.58409022031727176
drand48() // => Double = 0.15936862653180484
drand48() // => Double = 0.38371587480719427

arc4random_uniform(3) // => UInt32 = 0
arc4random_uniform(3) // => UInt32 = 1
arc4random_uniform(3) // => UInt32 = 0
arc4random_uniform(3) // => UInt32 = 1
arc4random_uniform(3) // => UInt32 = 2

arc4random_uniform() is recommended over constructions like arc4random() % upper_bound as it avoids "modulo bias" when the upper bound is not a power of two.

回答2:

You could try as well:

let diceRoll = Int(arc4random_uniform(UInt32(6)))

I had to add "UInt32" to make it work.

回答3:

Just call this function and provide minimum and maximum range of number and you will get a random number.

eg.like randomNumber(MIN: 0, MAX: 10) and You will get number between 0 to 9.

func randomNumber(MIN: Int, MAX: Int)-> Int{
    return Int(arc4random_uniform(UInt32(MAX-MIN)) + UInt32(MIN));
}

Note:- You will always get output an Integer number.

回答4:

After some investigation I wrote this:

import Foundation

struct Math {
   private static var seeded = false

   static func randomFractional() -> CGFloat {

      if !Math.seeded {
         let time = Int(NSDate().timeIntervalSinceReferenceDate)
         srand48(time)
         Math.seeded = true
      }

      return CGFloat(drand48())
   }
}

Now you can just do Math.randomFraction() to get random numbers [0..1[ without having to remember seeding first. Hope this helps someone :o)

回答5:

Another option is to use the xorshift128plus algorithm:

func xorshift128plus(seed0 : UInt64, _ seed1 : UInt64) -> () -> UInt64 {
    var state0 : UInt64 = seed0
    var state1 : UInt64 = seed1
    if state0 == 0 && state1 == 0 {
        state0 = 1 // both state variables cannot be 0
    }

    func rand() -> UInt64 {
        var s1 : UInt64 = state0
        let s0 : UInt64 = state1
        state0 = s0
        s1 ^= s1 << 23
        s1 ^= s1 >> 17
        s1 ^= s0
        s1 ^= s0 >> 26
        state1 = s1
        return UInt64.addWithOverflow(state0, state1).0
    }

    return rand
}

This algorithm has a period of 2^128 - 1 and passes all the tests of the BigCrush test suite. Note that while this is a high-quality pseudo-random number generator with a long period, it is not a cryptographically secure random number generator.

You could seed it from the current time or any other random source of entropy. For example, if you had a function called urand64() that read a UInt64 from /dev/urandom, you could use it like this:

let rand = xorshift128plus(urand64(), urand64())
for _ in 1...10 {
    print(rand())
}

回答6:

Update with swift 4.2 :

let randomInt = Int.random(in: 1..<5)
let randomFloat = Float.random(in: 1..<10)
let randomDouble = Double.random(in: 1...100)
let randomCGFloat = CGFloat.random(in: 1...1000)

回答7:

let MAX : UInt32 = 9
let MIN : UInt32 = 1 
func randomNumber()
{
   var random_number = Int(arc4random_uniform(MAX) + MIN)
   print ("random = ", random_number);    
}

回答8:

In Swift 3 :

It will generate random number between 0 to limit

let limit : UInt32 = 6
print("Random Number : \(arc4random_uniform(limit))")

回答9:

My implementation as an Int extension. Will generate random numbers in range from..<to

public extension Int {
    static func random(from: Int, to: Int) -> Int {
        guard to > from else {
            assertionFailure("Can not generate negative random numbers")
            return 0
        }
        return Int(arc4random_uniform(UInt32(to - from)) + UInt32(from))
    }
}

回答10:

you can use this in specific rate:

let die = [1, 2, 3, 4, 5, 6]
 let firstRoll = die[Int(arc4random_uniform(UInt32(die.count)))]
 let secondRoll = die[Int(arc4random_uniform(UInt32(die.count)))]

回答11:

Lets Code with Swift for the random number or random string :)

let quotes: NSArray = ["R", "A", "N", "D", "O", "M"]

      let randomNumber = arc4random_uniform(UInt32(quotes.count))
      let quoteString = quotes[Int(randomNumber)]
      print(quoteString)

it will give you output randomly.

回答12:

Don't forget that some numbers will repeat! so you need to do something like....

my totalQuestions was 47.

func getRandomNumbers(totalQuestions:Int) -> NSMutableArray
{

    var arrayOfRandomQuestions: [Int] = []

    print("arraySizeRequired = 40")
    print("totalQuestions = \(totalQuestions)")

    //This will output a 40 random numbers between 0 and totalQuestions (47)
    while arrayOfRandomQuestions.count < 40
    {

        let limit: UInt32 = UInt32(totalQuestions)

        let theRandomNumber = (Int(arc4random_uniform(limit)))

            if arrayOfRandomQuestions.contains(theRandomNumber)
            {
                print("ping")

            }
            else
            {
            //item not found
                arrayOfRandomQuestions.append(theRandomNumber)
            }

    }

    print("Random Number set = \(arrayOfRandomQuestions)")
    print("arrayOutputCount = \(arrayOfRandomQuestions.count)")


    return arrayOfRandomQuestions as! NSMutableArray

}

回答13:

This is how I get a random number between 2 int's!

func randomNumber(MIN: Int, MAX: Int)-> Int{
    var list : [Int] = []
    for i in MIN...MAX {
        list.append(i)
    }
    return list[Int(arc4random_uniform(UInt32(list.count)))]
}

usage:

print("My Random Number is: \(randomNumber(MIN:-10,MAX:10))")

回答14:

Another option is to use GKMersenneTwisterRandomSource from GameKit. The docs say:

A deterministic pseudo-random source that generates random numbers based on a mersenne twister algorithm. This is a deterministic random source suitable for creating reliable gameplay mechanics. It is slightly slower than an Arc4 source, but more random, in that it has a longer period until repeating sequences. While deterministic, this is not a cryptographic random source. It is however suitable for obfuscation of gameplay data.

import GameKit

let minValue = 0
let maxValue = 100

var randomDistribution: GKRandomDistribution?
let randomSource = GKMersenneTwisterRandomSource()
randomDistribution = GKRandomDistribution(randomSource: randomSource, lowestValue: minValue, highestValue: maxValue)
let number = randomDistribution?.nextInt() ?? 0
print(number)

Example taken from Apple's sample code: https://github.com/carekit-apple/CareKit/blob/master/CareKitPrototypingTool/OCKPrototyper/CareKitPatient/RandomNumberGeneratorHelper.swift

回答15:

look, i had the same problem but i insert the function as a global variable

as

var RNumber = Int(arc4random_uniform(9)+1)

func GetCase(){

your code
}

obviously this is not efficent, so then i just copy and paste the code into the function so it could be reusable, then xcode suggest me to set the var as constant so my code were

func GetCase() {

let RNumber = Int(arc4random_uniform(9)+1)

   if categoria == 1 {
    }
}

well thats a part of my code so xcode tell me something of inmutable and initialization but, it build the app anyway and that advice simply dissapear

hope it helps