jsonify a SQLAlchemy result set in Flask

问题:

I\'m trying to jsonify a SQLAlchemy result set in Flask/Python.

The Flask mailing list suggested the following method http://librelist.com/browser//flask/2011/2/16/jsonify-sqlalchemy-pagination-collection-result/#04a0754b63387f87e59dda564bde426e :

return jsonify(json_list = qryresult)

However I\'m getting the following error back:

TypeError: <flaskext.sqlalchemy.BaseQuery object at 0x102c2df90> 
is not JSON serializable

What am I overlooking here?

I have found this question: How to serialize SqlAlchemy result to JSON? which seems very similar however I didn\'t know whether Flask had some magic to make it easier as the mailing list post suggested.

Edit: for clarification, this is what my model looks like

class Rating(db.Model):

    __tablename__ = \'rating\'

    id = db.Column(db.Integer, primary_key=True)
    fullurl = db.Column(db.String())
    url = db.Column(db.String())
    comments = db.Column(db.Text)
    overall = db.Column(db.Integer)
    shipping = db.Column(db.Integer)
    cost = db.Column(db.Integer)
    honesty = db.Column(db.Integer)
    communication = db.Column(db.Integer)
    name = db.Column(db.String())
    ipaddr = db.Column(db.String())
    date = db.Column(db.String())

    def __init__(self, fullurl, url, comments, overall, shipping, cost, honesty, communication, name, ipaddr, date):
        self.fullurl = fullurl
        self.url = url
        self.comments = comments
        self.overall = overall
        self.shipping = shipping
        self.cost = cost
        self.honesty = honesty
        self.communication = communication
        self.name = name
        self.ipaddr = ipaddr
        self.date = date

回答1:

It seems that you actually haven\'t executed your query. Try following:

return jsonify(json_list = qryresult.all())

[Edit]: Problem with jsonify is, that usually the objects cannot be jsonified automatically. Even Python\'s datetime fails ;)

What I have usually done, is to add an extra property (like serialize) to classes that need to be serialized:

def dump_datetime(value):
    \"\"\"Deserialize datetime object into string form for JSON processing.\"\"\"
    if value is None:
        return None
    return [value.strftime(\"%Y-%m-%d\"), value.strftime(\"%H:%M:%S\")]

class Foo(db.Model):
    # ... SQLAlchemy defs here..
    def __init__(self, ...):
       # self.foo = ...
       pass

    @property
    def serialize(self):
       \"\"\"Return object data in easily serializeable format\"\"\"
       return {
           \'id\'         : self.id,
           \'modified_at\': dump_datetime(self.modified_at),
           # This is an example how to deal with Many2Many relations
           \'many2many\'  : self.serialize_many2many
       }
    @property
    def serialize_many2many(self):
       \"\"\"
       Return object\'s relations in easily serializeable format.
       NB! Calls many2many\'s serialize property.
       \"\"\"
       return [ item.serialize for item in self.many2many]

And now for views I can just do:

return jsonify(json_list=[i.serialize for i in qryresult.all()])

Hope this helps ;)

回答2:

I had the same need, to serialize into json. Take a look at this question. It shows how to discover columns programmatically. So, from that I created the code below. It works for me, and I\'ll be using it in my web app. Happy coding!

def to_json(inst, cls):
    \"\"\"
    Jsonify the sql alchemy query result.
    \"\"\"
    convert = dict()
    # add your coversions for things like datetime\'s 
    # and what-not that aren\'t serializable.
    d = dict()
    for c in cls.__table__.columns:
        v = getattr(inst, c.name)
        if c.type in convert.keys() and v is not None:
            try:
                d[c.name] = convert[c.type](v)
            except:
                d[c.name] = \"Error:  Failed to covert using \", str(convert[c.type])
        elif v is None:
            d[c.name] = str()
        else:
            d[c.name] = v
    return json.dumps(d)

class Person(base):
    __tablename__ = \'person\'
    id = Column(Integer, Sequence(\'person_id_seq\'), primary_key=True)
    first_name = Column(Text)
    last_name = Column(Text)
    email = Column(Text)

    @property
    def json(self):
        return to_json(self, self.__class__)

回答3:

Here\'s what\'s usually sufficient for me:

I create a serialization mixin which I use with my models. The serialization function basically fetches whatever attributes the SQLAlchemy inspector exposes and puts it in a dict.

from sqlalchemy.inspection import inspect

class Serializer(object):

    def serialize(self):
        return {c: getattr(self, c) for c in inspect(self).attrs.keys()}

    @staticmethod
    def serialize_list(l):
        return [m.serialize() for m in l]

All that\'s needed now is to extend the SQLAlchemy model with the Serializer mixin class.

If there are fields you do not wish to expose, or that need special formatting, simply override the serialize() function in the model subclass.

class User(db.Model, Serializer):
    id = db.Column(db.Integer, primary_key=True)
    username = db.Column(db.String)
    password = db.Column(db.String)

    # ...

    def serialize(self):
        d = Serializer.serialize(self)
        del d[\'password\']
        return d

In your controllers, all you have to do is to call the serialize() function (or serialize_list(l) if the query results in a list) on the results:

def get_user(id):
    user = User.query.get(id)
    return json.dumps(user.serialize())

def get_users():
    users = User.query.all()
    return json.dumps(User.serialize_list(users))

回答4:

Here\'s my approach:

MODEL:

class AutoSerialize(object):
    \'Mixin for retrieving public fields of model in json-compatible format\'
    __public__ = None

    def get_public(self, exclude=(), extra=()):
        \"Returns model\'s PUBLIC data for jsonify\"
        data = {}
        keys = self._sa_instance_state.attrs.items()
        public = self.__public__ + extra if self.__public__ else extra
        for k, field in  keys:
            if public and k not in public: continue
            if k in exclude: continue
            value = self._serialize(field.value)
            if value:
                data[k] = value
        return data

    @classmethod
    def _serialize(cls, value, follow_fk=False):
        if type(value) in (datetime, date):
            ret = value.isoformat()
        elif hasattr(value, \'__iter__\'):
            ret = []
            for v in value:
                ret.append(cls._serialize(v))
        elif AutoSerialize in value.__class__.__bases__:
            ret = value.get_public()
        else:
            ret = value

        return ret

class User(db.Model, AutoSerialize):
    __tablename__ = \'users\'
    __public__ = (\'id\', \'name\', \'email\')
    id = db.Column(db.Integer, primary_key=True)
    name = db.Column(db.Unicode(50))
    email = db.Column(db.String(120), unique=True)
    passhash = db.Column(db.String(100))
    ...

VIEW:

from flask import jsonfy

@mod.route(\'/<int:id>/\', methods=[\'GET\'])
def get_user_by_id(id):
    u = User.query.get(id)
    return jsonify(u.get_public())

I\'m not sure about this:

self._sa_instance_state.attrs.items()

but it works. I had not enough time to make it more elegant, maybe someone will suggest a better way to get SA fields

回答5:

For a flat query (no joins) you can do this

@app.route(\'/results/\')
def results():
    data = Table.query.all()
    result = [d.__dict__ for d in data]
    return jsonify(result=result)

and if you only want to return certain columns from the database you can do this

@app.route(\'/results/\')
def results():
    cols = [\'id\', \'url\', \'shipping\']
    data = Table.query.all()
    result = [{col: getattr(d, col) for col in cols} for d in data]
    return jsonify(result=result)

回答6:

Ok, I\'ve been working on this for a few hours, and I\'ve developed what I believe to be the most pythonic solution yet. The following code snippets are python3 but shouldn\'t be too horribly painful to backport if you need.

The first thing we\'re gonna do is start with a mixin that makes your db models act kinda like dicts:

from sqlalchemy.inspection import inspect

class ModelMixin:
    \"\"\"Provide dict-like interface to db.Model subclasses.\"\"\"

    def __getitem__(self, key):
        \"\"\"Expose object attributes like dict values.\"\"\"
        return getattr(self, key)

    def keys(self):
        \"\"\"Identify what db columns we have.\"\"\"
        return inspect(self).attrs.keys()

Now we\'re going to define our model, inheriting the mixin:

class MyModel(db.Model, ModelMixin):
    id = db.Column(db.Integer, primary_key=True)
    foo = db.Column(...)
    bar = db.Column(...)
    # etc ...

That\'s all it takes to be able to pass an instance of MyModel() to dict() and get a real live dict instance out of it, which gets us quite a long way towards making jsonify() understand it. Next, we need to extend JSONEncoder to get us the rest of the way:

from flask.json import JSONEncoder
from contextlib import suppress

class MyJSONEncoder(JSONEncoder):
    def default(self, obj):
        # Optional: convert datetime objects to ISO format
        with suppress(AttributeError):
            return obj.isoformat()
        return dict(obj)

app.json_encoder = MyJSONEncoder

Bonus points: if your model contains computed fields (that is, you want your JSON output to contain fields that aren\'t actually stored in the database), that\'s easy too. Just define your computed fields as @propertys, and extend the keys() method like so:

class MyModel(db.Model, ModelMixin):
    id = db.Column(db.Integer, primary_key=True)
    foo = db.Column(...)
    bar = db.Column(...)

    @property
    def computed_field(self):
        return \'this value did not come from the db\'

    def keys(self):
        return super().keys() + [\'computed_field\']

Now it\'s trivial to jsonify:

@app.route(\'/whatever\', methods=[\'GET\'])
def whatever():
    return jsonify(dict(results=MyModel.query.all()))

回答7:

If you are using flask-restful you can use marshal:

from flask.ext.restful import Resource, fields, marshal

topic_fields = {
    \'title\':   fields.String,
    \'content\': fields.String,
    \'uri\':     fields.Url(\'topic\'),
    \'creator\': fields.String,
    \'created\': fields.DateTime(dt_format=\'rfc822\')
}

class TopicListApi(Resource):
    def get(self):
        return {\'topics\': [marshal(topic, topic_fields) for topic in DbTopic.query.all()]}

You need to explicitly list what you are returning and what type it is, which I prefer anyway for an api. Serialization is easily taken care of (no need for jsonify), dates are also not a problem. Note that the content for the uri field is automatically generated based on the topic endpoint and the id.

回答8:

I\'ve been looking at this problem for the better part of a day, and here\'s what I\'ve come up with (credit to https://stackoverflow.com/a/5249214/196358 for pointing me in this direction).

(Note: I\'m using flask-sqlalchemy, so my model declaration format is a bit different from straight sqlalchemy).

In my models.py file:

import json

class Serializer(object):
  __public__ = None
  \"Must be implemented by implementors\"

  def to_serializable_dict(self):
    dict = {}
    for public_key in self.__public__:
      value = getattr(self, public_key)
      if value:
        dict[public_key] = value
    return dict

class SWEncoder(json.JSONEncoder):
  def default(self, obj):
    if isinstance(obj, Serializer):
      return obj.to_serializable_dict()
    if isinstance(obj, (datetime)):
      return obj.isoformat()
    return json.JSONEncoder.default(self, obj)


def SWJsonify(*args, **kwargs):
  return current_app.response_class(json.dumps(dict(*args, **kwargs), cls=SWEncoder, indent=None if request.is_xhr else 2), mimetype=\'application/json\')
  # stolen from https://github.com/mitsuhiko/flask/blob/master/flask/helpers.py

and all my model objects look like this:

class User(db.Model, Serializer):
  __public__ = [\'id\',\'username\']
  ... field definitions ...

In my views I call SWJsonify wherever I would have called Jsonify, like so:

@app.route(\'/posts\')
def posts():
  posts = Post.query.limit(PER_PAGE).all()
  return SWJsonify({\'posts\':posts })

Seems to work pretty well. Even on relationships. I haven\'t gotten far with it, so YMMV, but so far it feels pretty \"right\" to me.

Suggestions welcome.

回答9:

Here is a way to add an as_dict() method on every class, as well as any other method you want to have on every single class. Not sure if this is the desired way or not, but it works...

class Base(object):
    def as_dict(self):
        return dict((c.name,
                     getattr(self, c.name))
                     for c in self.__table__.columns)


Base = declarative_base(cls=Base)

回答10:

I was looking for something like the rails approach used in ActiveRecord to_json and implemented something similar using this Mixin after being unsatisfied with other suggestions. It handles nested models, and including or excluding attributes of the top level or nested models.

class Serializer(object):

    def serialize(self, include={}, exclude=[], only=[]):
        serialized = {}
        for key in inspect(self).attrs.keys():
            to_be_serialized = True
            value = getattr(self, key)
            if key in exclude or (only and key not in only):
                to_be_serialized = False
            elif isinstance(value, BaseQuery):
                to_be_serialized = False
                if key in include:
                    to_be_serialized = True
                    nested_params = include.get(key, {})
                    value = [i.serialize(**nested_params) for i in value]

            if to_be_serialized:
                serialized[key] = value

        return serialized

Then, to get the BaseQuery serializable I extended BaseQuery

class SerializableBaseQuery(BaseQuery):

    def serialize(self, include={}, exclude=[], only=[]):
        return [m.serialize(include, exclude, only) for m in self]

For the following models

class ContactInfo(db.Model, Serializer):
    id = db.Column(db.Integer, primary_key=True)
    user_id = db.Column(db.Integer, db.ForeignKey(\'user.id\'))
    full_name = db.Column(db.String())
    source = db.Column(db.String())
    source_id = db.Column(db.String())

    email_addresses = db.relationship(\'EmailAddress\', backref=\'contact_info\', lazy=\'dynamic\')
    phone_numbers = db.relationship(\'PhoneNumber\', backref=\'contact_info\', lazy=\'dynamic\')


class EmailAddress(db.Model, Serializer):
    id = db.Column(db.Integer, primary_key=True)
    email_address = db.Column(db.String())
    type = db.Column(db.String())
    contact_info_id = db.Column(db.Integer, db.ForeignKey(\'contact_info.id\'))


class PhoneNumber(db.Model, Serializer):
    id = db.Column(db.Integer, primary_key=True)
    phone_number = db.Column(db.String())
    type = db.Column(db.String())
    contact_info_id = db.Column(db.Integer, db.ForeignKey(\'contact_info.id\'))

    phone_numbers = db.relationship(\'Invite\', backref=\'phone_number\', lazy=\'dynamic\')

You could do something like

@app.route(\"/contact/search\", methods=[\'GET\'])
def contact_search():
    contact_name = request.args.get(\"name\")
    matching_contacts = ContactInfo.query.filter(ContactInfo.full_name.like(\"%{}%\".format(contact_name)))

    serialized_contact_info = matching_contacts.serialize(
        include={
            \"phone_numbers\" : {
                \"exclude\" : [\"contact_info\", \"contact_info_id\"]
            },
            \"email_addresses\" : {
                \"exclude\" : [\"contact_info\", \"contact_info_id\"]
            }
        }
    )

    return jsonify(serialized_contact_info)

回答11:

Flask-Restful 0.3.6 the Request Parsing recommend marshmallow

marshmallow is an ORM/ODM/framework-agnostic library for converting complex datatypes, such as objects, to and from native Python datatypes.

A simple marshmallow example is showing below.

from marshmallow import Schema, fields

class UserSchema(Schema):
    name = fields.Str()
    email = fields.Email()
    created_at = fields.DateTime()

from marshmallow import pprint

user = User(name=\"Monty\", email=\"[e-mail]\")
schema = UserSchema()
result = schema.dump(user)
pprint(result)
# {\"name\": \"Monty\",
#  \"email\": \"[e-mail]\",
#  \"created_at\": \"2014-08-17T14:54:16.049594+00:00\"}

The core features contain

Declaring Schemas
Serializing Objects (“Dumping”)
Deserializing Objects (“Loading”)
Handling Collections of Objects
Validation
Specifying Attribute Names
Specifying Serialization/Deserialization Keys
Refactoring: Implicit Field Creation
Ordering Output
“Read-only” and “Write-only” Fields
Specify Default Serialization/Deserialization Values
Nesting Schemas
Custom Fields

回答12:

I was working with a sql query defaultdict of lists of RowProxy objects named jobDict It took me a while to figure out what Type the objects were.

This was a really simple quick way to resolve to some clean jsonEncoding just by typecasting the row to a list and by initially defining the dict with a value of list.

    jobDict = defaultdict(list)
    def set_default(obj):
        # trickyness needed here via import to know type
        if isinstance(obj, RowProxy):
            return list(obj)
        raise TypeError


    jsonEncoded = json.dumps(jobDict, default=set_default)

回答13:

I just want to add my method to do this.

just define a custome json encoder to serilize your db models.

class ParentEncoder(json.JSONEncoder):
    def default(self, obj):
        # convert object to a dict
        d = {}
        if isinstance(obj, Parent):
            return {\"id\": obj.id, \"name\": obj.name, \'children\': list(obj.child)}
        if isinstance(obj, Child):
            return {\"id\": obj.id, \"name\": obj.name}

        d.update(obj.__dict__)
        return d

then in your view function

parents = Parent.query.all()
dat = json.dumps({\"data\": parents}, cls=ParentEncoder)
resp = Response(response=dat, status=200, mimetype=\"application/json\")
return (resp)

it works well though the parent have relationships

回答14:

Here\'s my answer if you\'re using the declarative base (with help from some of the answers already posted):

# in your models definition where you define and extend declarative_base()
from sqlalchemy.ext.declarative import declarative_base
...
Base = declarative_base()
Base.query = db_session.query_property()
...

# define a new class (call \"Model\" or whatever) with an as_dict() method defined
class Model():
    def as_dict(self):
        return { c.name: getattr(self, c.name) for c in self.__table__.columns }

# and extend both the Base and Model class in your model definition, e.g.
class Rating(Base, Model):
    ____tablename__ = \'rating\'
    id = db.Column(db.Integer, primary_key=True)
    fullurl = db.Column(db.String())
    url = db.Column(db.String())
    comments = db.Column(db.Text)
    ...

# then after you query and have a resultset (rs) of ratings
rs = Rating.query.all()

# you can jsonify it with
s = json.dumps([r.as_dict() for r in rs], default=alchemyencoder)
print (s)

# or if you have a single row
r = Rating.query.first()

# you can jsonify it with
s = json.dumps(r.as_dict(), default=alchemyencoder)

# you will need this alchemyencoder where your are calling json.dumps to handle datetime and decimal format
# credit to Joonas @ http://codeandlife.com/2014/12/07/sqlalchemy-results-to-json-the-easy-way/
def alchemyencoder(obj):
    \"\"\"JSON encoder function for SQLAlchemy special classes.\"\"\"
    if isinstance(obj, datetime.date):
        return obj.isoformat()
    elif isinstance(obj, decimal.Decimal):
        return float(obj)

回答15:

It\'s been a lot of times and there are lots of valid answers, but the following code block seems to work:

my_object = SqlAlchemyModel()
my_serializable_obj = my_object.__dict__
del my_serializable_obj[\"_sa_instance_state\"]
print(jsonify(my_serializable_object))

I\'m aware that this is not a perfect solution, nor as elegant as the others, however for those who want o quick fix, they might try this.