I replaced a 3D array with a 3D std::vector in my code function and it's entering a infinite loop .Could you give me a hint,I really need to use a vector instead an array.Thanks:)
My initial code was:
//arr is a 3D array of a sudoku table,the 3 rd dimension is for keeping values 0 to 13
//for a cell, and when I assign values I start from index 1 to 12
bool sol(int arr[12][12][13]) {
int row,col;
if(!find_empty(arr,row,col)) return true;
for(int i=1;i< 12;i++) { //for digits 1 to 12
if(is_working(arr,row,col,arr[row][col][i]) ) { //if i can put the value in a cell
arr[row][col][0] = arr[row][col][i]; //replace the first element for a cell with that value
//here I want to use vector because I want to use an ac3 algorithm
//and remove those values that not satisfy constraints and shrink domain size having less values to verify with backtrack
if(sol(arr)) return true;
arr[row][col][0] = 0;
}
}
return false;//if not backtrack
}
I replace arr with:
std::vector<std::vector<std::vector<int> > > vec;
vec.resize(12);
for(int i=0;i<12;i++)
{
vec[i].resize(12);
for(int j=0;j<12;j++)
{
vec[i][j].resize(13);
for(int k=0;k<13;k++)
vec[i][j][k]=table[i][j][k];
}
}
bool sol(std::vector<std::vector<std::vector<int> > >& vec) {
int row,col;
if(!find_empty(vec,row,col)) return true;
for(int i=1;i< vec[row][col].size();i++) {//for remainig values in domain
if(is_working(vec,row,col,vec[row][col][i]) ) {//same as above but having less values to verify for
vec[row][col][0] = vec[row][col][i];
if(sol(vec)) return true;
vec[row][col][0] = 0;
}
}
return false;
}
and now it's entering a infinite loop!The initial code has no errors,it's a simple backtracking.The problem appears after I replace arr with vec.Could you give me some advice on how to replace 3D arr with an 3D vector