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问题:
I want to create an object that contains 2 links to Users. For example:
class GameClaim(models.Model):
target = models.ForeignKey(User)
claimer = models.ForeignKey(User)
isAccepted = models.BooleanField()
but I am getting the following errors when running the server:
Accessor for field 'target' clashes with related field 'User.gameclaim_set'. Add a related_name argument to the definition for 'target'.
Accessor for field 'claimer' clashes with related field 'User.gameclaim_set'. Add a related_name argument to the definition for 'claimer'.
Can you please explain why I am getting the errors and how to fix them?
回答1:
You have two foreign keys to User. Django automatically creates a reverse relation from User back to GameClaim, which is usually gameclaim_set
. However, because you have two FKs, you would have two gameclaim_set
attributes, which is obviously impossible. So you need to tell Django what name to use for the reverse relation.
Use the related_name
attribute in the FK definition. e.g.
class GameClaim(models.Model):
target = models.ForeignKey(User, related_name='gameclaim_targets')
claimer = models.ForeignKey(User, related_name='gameclaim_users')
isAccepted = models.BooleanField()
回答2:
The User
model is trying to create two fields with the same name, one for the GameClaims
that have that User
as the target
, and another for the GameClaims
that have that User
as the claimer
. Here's the docs on related_name
, which is Django's way of letting you set the names of the attributes so the autogenerated ones don't conflict.
回答3:
The OP isn't using a abstract base class... but if you are, you will find that hard coding the related_name in the FK (e.g. ..., related_name="myname") will result in a number of these conflict errors - one for each inherited class from the base class. The link provided below contains the workaround, which is simple, but definitely not obvious.
From the django docs...
If you are using the related_name
attribute on a ForeignKey or
ManyToManyField, you must always
specify a unique reverse name for the
field. This would normally cause a
problem in abstract base classes,
since the fields on this class are
included into each of the child
classes, with exactly the same values
for the attributes (including
related_name) each time.
More info here.
回答4:
Sometimes you have to use extra formatting in related_name
- actually, any time when inheritance is used.
class Value(models.Model):
value = models.DecimalField(decimal_places=2, max_digits=5)
animal = models.ForeignKey(
Animal, related_name="%(app_label)s_%(class)s_related")
class Meta:
abstract = True
class Height(Value):
pass
class Weigth(Value):
pass
class Length(Value):
pass
No clash here, but related_name is defined once and Django will take care for creating unique relation names.
then in children of Value class, you'll have access to:
herdboard_height_related
herdboard_lenght_related
herdboard_weight_related
回答5:
I seem to come across this occasionally when I add a submodule as an application to a django project, for example given the following structure:
myapp/
myapp/module/
myapp/module/models.py
If I add the following to INSTALLED_APPS:
'myapp',
'myapp.module',
Django seems to process the myapp.mymodule models.py file twice and throws the above error. This can be resolved by not including the main module in the INSTALLED_APPS list:
'myapp.module',
Including the myapp
instead of myapp.module
causes all the database tables to be created with incorrect names, so this seems to be the correct way to do it.
I came across this post while looking for a solution to this problem so figured I'd put this here :)
回答6:
Just adding to Jordan's answer (thanks for the tip Jordan) it can also happen if you import the level above the apps and then import the apps e.g.
myproject/
apps/
foo_app/
bar_app/
So if you are importing apps, foo_app and bar_app then you could get this issue. I had apps, foo_app and bar_app all listed in settings.INSTALLED_APPS
And you want to avoid importing apps anyway, because then you have the same app installed in 2 different namespaces
apps.foo_app
and
foo_app