Private constructor and make_shared

2019-04-11 15:03发布

问题:

I have a singleton class with a private constructor. In the static factory method I do the following:

shared_ptr<MyClass> MyClass::GetInstance()
{
    static once_flag onceFlag;

    call_once(onceFlag, []() {
        if (_instance == nullptr)
            _instance.reset(new MyClass());
    });

    return _instance;
}

If I use

_instance = make_shared<MyClass>();

the code does not compile. My question is: why new can invoke a private constructor but make_shared not?

回答1:

  1. As mentioned, std::make_shared or its component parts don't have access to private members.

  2. the call_once and once_flag are un-necessary. They are implicit in c++11 static initialisation,

  3. You normally would not want to expose the shared pointer.

 

class MyClass
{
    MyClass() {}

public:
    static MyClass& GetInstance()
    {
        static auto instance = MyClass();
        return instance;
    }
};

However, there is one case I can imagine where you would want to expose a shared pointer to the impl - this is in the case where the class can choose to 'break off' or 'reset' the impl to a new one. In this case I would consider code like this:

class MyClass2
{
    MyClass2() {};

    static auto& InternalGetInstance()
    {
        static std::shared_ptr<MyClass2> instance { new MyClass2 };
        return instance;
    }

public:

    static std::shared_ptr<MyClass2> GetInstance()
    {
        return std::atomic_load(std::addressof(InternalGetInstance()));
    }

    static void reset() {
        std::atomic_store(std::addressof(InternalGetInstance()),
                        std::shared_ptr<MyClass2>(new MyClass2));

    }  
};

However, in the end, it is my view that 'staticness' of a class should be an implementation detail, and unimportant to the user of the class:

#include <memory>
#include <utility>

class MyClass
{
    // internal mechanics

    struct Impl {

        auto doSomething() {
            // actual implementation here.
        }
    };

    // getImpl now becomes the customisation point if you wish to change the
    // bahviour of the class later
    static Impl& getImpl() {
        static auto impl = Impl();
        return impl;
    }


    // use value semantics - it makes for more readable and loosely-coupled code
public:
    MyClass() {}

    // public methods defer to internal implementation

    auto doSomething() {
        return getImpl().doSomething();
    }
};


int main() {

    // note: just create objects
    auto mc = MyClass();
    mc.doSomething();

    // now we can pass the singleton as an object. Other functions don't even
    // need to know it's a singlton:

    extern void somethingElse(MyClass mc);
    somethingElse(mc);
}

void somethingElse(MyClass mc)
{

}


回答2:

Please take VTT's comment seriously.


To your question:

My question is: why new can invoke a private constructor but make_shared not?

The new is actually used within a lambda in a member-function; Well, A lambda defines a local-class, and C++ standards permits a local-class within a member-function to access everything the member-function can access. And its trivial to remember that member functions can access privates..

std::make_shared has no access to the privates of MyClass. It's outside the scope of MyClass


Example:

class X{
    X(){};
public:
    static X* create(){ // This member-function can access private functions and ctors/dtor
        auto lm = [](){ // This lambda inherits the same access of enclosing member-function
               return new X();
        };
        return lm();
    }
};

int main(){
    auto x = X::create();    //valid;
    auto y = new X();        //invalid;
}


回答3:

You should use Meyers singleton instead. You should ensure that your compiler supports C++11 magic static before.