List files recursively in Linux CLI with path rela

问题:

This is similar to this question, but I want to include the path relative to the current directory in unix. If I do the following:

ls -LR | grep .txt

It doesn't include the full paths. For example, I have the following directory structure:

test1/file.txt
test2/file1.txt
test2/file2.txt

The code above will return:

file.txt
file1.txt
file2.txt

How can I get it to include the paths relative to the current directory using standard Unix commands?

回答1:

Use find:

find . -name \*.txt -print

On systems that use GNU find, like most GNU/Linux distributions, you can leave out the -print.

回答2:

Use tree, with -f (full path) and -i (no indentation lines):

tree -if --noreport .
tree -if --noreport directory/

You can then use grep to filter out the ones you want.

---

If the command is not found, you can install it:

Type following command to install tree command on RHEL/CentOS and Fedora linux:

# yum install tree -y

If you are using Debian/Ubuntu, Mint Linux type following command in your terminal:

$ sudo apt-get install tree -y

回答3:

Try find. You can look it up exactly in the man page, but it's sorta like this:

find [start directory] -name [what to find]

so for your example

find . -name "*.txt"

should give you what you want.

回答4:

You could use find instead:

find . -name '*.txt'

回答5:

That does the trick:

ls -R1 $PWD | while read l; do case $l in *:) d=${l%:};; "") d=;; *) echo "$d/$l";; esac; done | grep -i ".txt"

But it does that by "sinning" with the parsing of ls, though, which is considered bad form by the GNU and Ghostscript communities.

回答6:

DIR=your_path
find $DIR | sed 's:""$DIR""::'

'sed' will erase 'your_path' from all 'find' results. And you recieve relative to 'DIR' path.

回答7:

To get the actual full path file names of the desired files using the find command, use it with the pwd command:

find $(pwd) -name \*.txt -print

回答8:

Here is a Perl script:

sub format_lines($)
{
    my $refonlines = shift;
    my @lines = @{$refonlines};
    my $tmppath = "-";

    foreach (@lines)
    {
        next if ($_ =~ /^\s+/);
        if ($_ =~ /(^\w+(\/\w*)*):/)
        {
            $tmppath = $1 if defined $1;    
            next;
        }
        print "$tmppath/$_";
    }
}

sub main()
{
        my @lines = ();

    while (<>) 
    {
        push (@lines, $_);
    }
    format_lines(\@lines);
}

main();

usage:

ls -LR | perl format_ls-LR.pl

回答9:

You could create a shell function, e.g. in your .zshrc or .bashrc:

filepath() {
    echo $PWD/$1
}

filepath2() {
    for i in $@; do
        echo $PWD/$i
    done
}

The first one would work on single files only, obviously.

回答10:

Find the file called "filename" on your filesystem starting the search from the root directory "/". The "filename"

find / -name "filename" 

回答11:

If you want to preserve the details come with ls like file size etc in your output then this should work.

sed "s|<OLDPATH>|<NEWPATH>|g" input_file > output_file

回答12:

You can implement this functionality like this
Firstly, using the ls command pointed to the targeted directory. Later using find command filter the result from it. From your case, it sounds like - always the filename starts with a word file***.txt

ls /some/path/here | find . -name 'file*.txt'   (* represents some wild card search)