How to get min or max element in a vector of objec

问题:

(This is a related question, but there are difference with my case that makes me doubt my understanding of it).

I have this class:

class MyOwnClass
{ 
public:
    int score; Specialcustomtype val1; double index;
private:

};

and a vector of MyOwnClass

vector<MyOwnClass> MySuperVector(20);

Having some code that set values to the fields of MyOwnClass, I want to find which MyOwnClass in the vector has the field score with the highest value.

In an answer from the related questions :

#include <algorithm> // For std::minmax_element
#include <tuple> // For std::tie
#include <vector> // For std::vector
#include <iterator> // For global begin() and end()

struct Size {
    int width, height;
};

std::vector<Size> sizes = { {4, 1}, {2, 3}, {1, 2} };

decltype(sizes)::iterator minEl, maxEl;
std::tie(minEl, maxEl) = std::minmax_element(begin(sizes), end(sizes),
    [] (Size const& s1, Size const& s2)
    {
        return s1.width < s2.width;
    });

But in my case, the fields of MyOwnClass are of different types and my attempts at using "max_elements" have failed.

Of course I could loop among the n elements of the vector and use a comparison to find which object has the highest score, and it works but I am sure that the built-in functions of c++ are more efficient thant my version.

回答1:

Try the following

std::vector<MyOwnClass> MySuperVector(20);

//..filling the vector

auto max = std::max_element( MySuperVector.begin(), MySuperVector.end(),
                             []( const MyOwnClass &a, const MyOwnClass &b )
                             {
                                 return a.score < b.score;
                             } ); 

If you need to find the minimum and maximum element simultaneously then you can use standard algorithm std::minmax_element. It returns a pair of iterators the first of which points to the first minimum element and the second points to the last maximum element. Otherwise you need to call std::max_element and std::min_element separatly. if you need to get the first minimum and the first maximum or the last minimum and the last maximum

The other approach is to define internal functional objects for each field that can be used for finding maximum or minimum. For example

class MyOwnClass
{ 
public:
    int score; Specialcustomtype val1; double index;

    struct ByScore
    {
        bool operator ()( const MyOwnClass &a, const MyOwnClass &b ) const
        { 
            return a.score < b.score;
        }
    };

    struct ByIndex
    {
        bool operator ()( const MyOwnClass &a, const MyOwnClass &b ) const
        { 
            return a.index < b.index;
        }
    };
private:

};

//...

auto max_score = std::max_element( MySuperVector.begin(), MySuperVector.end(),
                                   MyOwnClass::ByScore() ); 

auto max_index = std::max_element( MySuperVector.begin(), MySuperVector.end(),
                                   MyOwnClass::ByIndex() ); 

回答2:

That your elements are of different types it doesn't matter, you can always compare the field you're interested in:

std::vector<MyOwnClass> MySuperVector(20);

// A pred function to adjust according to your score
bool comparator(const MyOwnClass& s1, const MyOwnClass& s2) {
    return s1.score < s2.score;
}

int main() {
    MySuperVector[0].score = 23; // This will be returned
    MySuperVector[1].score = 2;
    MySuperVector[5].score = -22;

    auto element = std::max_element(MySuperVector.begin(), 
                                    MySuperVector.end(), comparator);

    std::cout << element->score; // 23
}

Example

Notice that you don't even need the minmax_element function since you're just asking for the greatest element (max_element is a better fit).

If the runtime efficiency to find your greatest value matters, you might want to take a look at priority_queues (heap adaptors).

回答3:

class test
{
private:
int num;
public:
test()
{
    num = 0;

}
test(int n)
{
    num = n;
}
void get(test ob1,test ob2)
{
    if (ob1.num > ob2.num)
    {
        cout << "Max Object nu is:" << ob1.num << endl;
    }
    else
    {
        cout << "Max Object number is:" << ob2.num << endl;
    }
}

};
void main()
{
test a(6);
test b(4);
test c;
c.get(a,b);
system("pause");
}