You have an error in your SQL syntax; check the ma

问题:

I am getting an Error in MySQL:

You have an error in your SQL syntax; check the manual that corresponds 
to your MySQL server version for the right syntax to use near '''')' at line 2'.

HTML Code:

<form action="read_message.php" method="post">
  <table class="form_table">
    <tr>
      <td style="font-weight:bold;">Subject:</td>
      <td><input style=" width:300px" name="form_subject"/></td>
      <td></td>
    </tr>
    <tr>
      <td style="font-weight:bold;">Message:</td>
      <td id="myWordCount">&nbsp;(300 words left)</td>
      <td></td>
    </tr>
    <tr>
      <td><input type="hidden" name="sender_id" value="<?php echo $sender_id?>"></td>
      <td><textarea cols="50" rows="4" name="form_message"></textarea></td>
      <td valign="bottom"><input type="submit" name="submit_message" value="send"></td>
    </tr>
  </table>
</form>

Code to insert into a mysql table:

<?php
  include_once"connect_to_mysql.php";
  //submit new message
  if($_POST['submit_message']){

    if($_POST['form_subject']==""){
      $submit_subject="(no subject)";
    }else{
      $submit_subject=$_POST['form_subject'];   
    }
    $submit_message=$_POST['form_message'];
    $sender_id = $_POST['sender_id'];
    if($shortMessagesLeft<1){
      $form_error_message='You have left with '.$shortMessagesLeft.' Short Message. Please purchase it from the <a href="membership.php?id='.$id.'">shop</a>.';
    }
    else if($submit_message==""){
      $form_error_message = 'Please fill in the message before sending.';
    }
    else{
      $message_left = $shortMessagesLeft-1;
      $update_short_message = mysql_query("UPDATE message_count SET short_message = '$message_left' WHERE user_id = '$id'");
      $sql = mysql_query("INSERT INTO private_messages (to_id, from_id, time_sent, subject, message) 
        VALUES('$sender_id', '$id', now(),'$submit_subject','$submit_message')") or die (mysql_error());
    }
  }

?>

What does the error mean and what am I doing wrong?

回答1:

There is a single quote in $submitsubject or $submit_message

Why is this a problem?

The single quote char terminates the string in MySQL and everything past that is treated as a sql command. You REALLY don't want to write your sql like that. At best, your application will break intermittently (as you're observing) and at worst, you have just introduced a huge security vulnerability.

Imagine if someone submitted '); DROP TABLE private_messages; in submit message.

Your SQL Command would be:

INSERT INTO private_messages (to_id, from_id, time_sent, subject, message) 
        VALUES('sender_id', 'id', now(),'subjet','');

DROP TABLE private_messages;

Instead you need to properly sanitize your values.

AT A MINIMUM you must run each value through mysql_real_escape_string() but you should really be using prepared statements.

If you were using mysql_real_escape_string() your code would look like this:

if($_POST['submit_message']){

if($_POST['form_subject']==""){
    $submit_subject="(no subject)";
}else{
    $submit_subject=mysql_real_escape_string($_POST['form_subject']); 
}
$submit_message=mysql_real_escape_string($_POST['form_message']);
$sender_id = mysql_real_escape_string($_POST['sender_id']);

Here is a great article on prepared statements and PDO.

回答2:

That's called SQL INJECTION. The ' tries to open/close a string in your mysql query. You should always escape any string that gets into your queries.

for example,

instead of this:

"VALUES ('$sender_id') "

do this:

"VALUES ('". mysql_real_escape_string($sender_id)  ."') "

(or equivalent, of course)

However, it's better to automate this, using PDO, named parameters, prepared statements or many other ways. Research about this and SQL Injection (here you have some techniques).

Hope it helps. Cheers

回答3:

Please make sure you have downloaded the sqldump fully, this problem is very common when we try to import half/incomplete downloaded sqldump. Please check size of your sqldump file.

回答4:

I was getting the same error when I used this code to update the record:

@mysqli_query($dbc,$query or die()))

After removing or die, it started working properly.

回答5:

I had this problem before, and the reason is very simple: Check your variables, if there were strings, so put it in quotes '$your_string_variable_here' ,, if it were numerical keep it without any quotes. for example, if I had these data: $name ( It will be string ) $phone_number ( It will be numerical ) So, it will be like that:

$query = "INSERT INTO users (name, phone) VALUES ('$name', $phone)"; Just like that and it will be fixed ^_^