Convert a std::vector of a boost::variant type

2019-04-09 17:02发布

问题:

How might I implement the function below to convert from vector of Value to a Container? I wish to assert if not all the members of values are of the same type, i.e. if the vector contains a mix of strings and ints. This is because the function's return value is either a std::vector<int> or a std::vector<std::string>.

typedef boost::variant<int, std::string> Value;
typedef boost::variant<std::vector<int>, std::vector<std::string> > Container;

Container valuesToContainer(const std::vector<Value>& values) 
{
    return Container();
}

回答1:

  struct converter_visitor : public boost::static_visitor<Container>
  {

         const std::vector<Value> & _cont;
         converter_visitor(const std::vector<Value> &r) : _cont(r) {}

         template<class T>
         Container operator()(const T &) const {
                  std::vector<T> ans;
                  ans.reserve(_cont.size());
                  for (int i=0;i < _cont.size();++i)
                         ans.push_back( boost::get<T>(_cont[i]));
                  return ans;
         }
   };

   Container valuesToContainer(const std::vector<Value> & values) {
         //assuming !values.empty()
         return boost::apply_visitor( converter_visitor(values),values.front());
   }

This will throw a bad_get if not all the elements of values are of the same type.



回答2:

This could come in handy, maybe:

template <typename... T> using VariantVector = std::vector<boost::variant<T...>>;
template <typename... T> using VectorPack    = std::tuple<std::vector<T>...>;

template <typename... T>
    VectorPack<T...> splitVectors(VariantVector<T...> const &values);

The difference with the function requested by the OP is that instead of 'erroring' when not all element types agree, it will return a tuple of vectors ("VectorPack"), and you can simply select which is the one you want.

Demo program:

#include <boost/variant.hpp>
#include <boost/variant/static_visitor.hpp>
#include <tuple>
#include <vector>

using std::get;

template <typename... T> using VariantVector = std::vector<boost::variant<T...>>;
template <typename... T> using VectorPack    = std::tuple<std::vector<T>...>;

namespace detail
{
    template <typename T>
    struct VectorSplitterMixin {
        void operator()(T const& v) { _bucket.push_back(v); }
        std::vector<T> _bucket;
    };

    template <typename... T>
        struct VectorSplitter : boost::static_visitor<>, VectorSplitterMixin<T>...
    {
        typedef VectorPack<T...> product_t;
        product_t product() {
            return product_t { std::move(static_cast<VectorSplitterMixin<T>*>(this)->_bucket)... };
        }
    };
}

template <typename T> struct X;

template <typename... T>
    VectorPack<T...> splitVectors(VariantVector<T...> const &values)
{
    auto splitter = detail::VectorSplitter<T...>();
    for (auto& val : values)
        boost::apply_visitor(splitter, val);
    return splitter.product();
}

int main()
{
    typedef boost::variant<int, std::string> Value;
    typedef boost::variant<std::vector<int>, std::vector<std::string> > Container;

    const std::vector<Value> vec { 42, "hello world", 1, -99, "more" };

    auto vectorPack = splitVectors<int, std::string>(vec);

    for (auto i : get<0>(vectorPack))
        std::cout << "int:" << i << ", ";
    std::cout << "\n";

    for (auto& s : get<1>(vectorPack))
        std::cout << "string:" << s << ", ";
    std::cout << "\n";
}

Printing:

int:42, int:1, int:-99, 
string:hello world, string:more, 


标签: c++ boost c++98