How to sum array of numbers in Ruby?

问题:

I have an array of integers.

For example:

array = [123,321,12389]

Is there any nice way to get the sum of them?

I know, that

sum = 0
array.each { |a| sum+=a }

would work.

回答1:

Try this:

array.inject(0){|sum,x| sum + x }

See Ruby\'s Enumerable Documentation

(note: the 0 base case is needed so that 0 will be returned on an empty array instead of nil)

回答2:

Or try the Ruby 1.9 way:

array.inject(0, :+)

Note: the 0 base case is needed otherwise nil will be returned on empty arrays:

> [].inject(:+)
nil
> [].inject(0, :+)
0

回答3:

array.reduce(0, :+)

While equivalent to array.inject(0, :+), the term reduce is entering a more common vernacular with the rise of MapReduce programming models.

inject, reduce, fold, accumulate, and compress are all synonymous as a class of folding functions. I find consistency across your code base most important, but since various communities tend to prefer one word over another, it’s nonetheless useful to know the alternatives.

To emphasize the map-reduce verbiage, here’s a version that is a little bit more forgiving on what ends up in that array.

array.map(&:to_i).reduce(0, :+)

Some additional relevant reading:

• http://ruby-doc.org/core-1.9.3/Enumerable.html#method-i-inject
• http://en.wikipedia.org/wiki/MapReduce
• http://en.wikipedia.org/wiki/Fold_(higher-order_function)

回答4:

Alternatively (just for comparison), if you have Rails installed (actually just ActiveSupport):

require \'activesupport\'
array.sum

回答5:

It is dangerous to mokeypatch base classes and now that Ruby 2.4.0 has sum on Enumerables it is not needed and dangerous. If you like danger and using an older version of Ruby, you could add #sum to the Array class:

class Array
  def sum
    inject(0) { |sum, x| sum + x }
  end
end

Then do fun stuff like:

[1, 2, 3, 4].sum

回答6:

New for Ruby 2.4.0

You can use the aptly named method Enumerable#sum. It has a lot of advantages over inject(:+) but there are some important notes to read at the end as well.

Examples

Ranges

(1..100).sum
#=> 5050

Arrays

[1, 2, 4, 9, 2, 3].sum
#=> 21

[1.9, 6.3, 20.3, 49.2].sum
#=> 77.7

Important note

This method is not equivalent to #inject(:+). For example

%w(a b c).inject(:+)
#=> \"abc\"
%w(a b c).sum
#=> TypeError: String can\'t be coerced into Integer

Also,

(1..1000000000).sum
#=> 500000000500000000 (execution time: less than 1s)
(1..1000000000).inject(:+)
#=> 500000000500000000 (execution time: upwards of a minute)

See this answer for more information on why sum is like this.

回答7:

Just for the sake of diversity, you can also do this if your array is not an array of numbers, but rather an array of objects that have properties that are numbers (e.g. amount):

array.inject(0){|sum,x| sum + x.amount}

回答8:

ruby 1.8.7 way is the following:

array.inject(0, &:+) 

回答9:

Ruby 2.4+ / Rails - array.sum i.e. [1, 2, 3].sum # => 6

Ruby pre 2.4 - array.inject(:+) or array.reduce(:+)

*Note: The #sum method is a new addition to 2.4 for enumerable so you will now be able to use array.sum in pure ruby, not just Rails.

回答10:

You can simply use:

    example = [1,2,3]
    example.inject(:+)

回答11:

This is Enough [1,2,3].inject(\'+\')

回答12:

Also allows for [1,2].sum{|x| x * 2 } == 6:

# http://madeofcode.com/posts/74-ruby-core-extension-array-sum
class Array
  def sum(method = nil, &block)
    if block_given?
      raise ArgumentError, \"You cannot pass a block and a method!\" if method
      inject(0) { |sum, i| sum + yield(i) }
    elsif method
      inject(0) { |sum, i| sum + i.send(method) }
    else
      inject(0) { |sum, i| sum + i }
    end
  end
end

回答13:

Ruby 2.4.0 is released, and it has an Enumerable#sum method. So you can do

array.sum

Examples from the docs:

{ 1 => 10, 2 => 20 }.sum {|k, v| k * v }  #=> 50
(1..10).sum                               #=> 55
(1..10).sum {|v| v * 2 }                  #=> 110

回答14:

for array with nil values we can do compact and then inject the sum ex-

a = [1,2,3,4,5,12,23.45,nil,23,nil]
puts a.compact.inject(:+)

回答15:

array.reduce(:+)

Works for Ranges too... hence,

(1..10).reduce(:+) returns 55

回答16:

Method 1:

    [1] pry(main)> [1,2,3,4].sum
    => 10
    [2] pry(main)> [].sum
    => 0
    [3] pry(main)> [1,2,3,5,nil].sum
    TypeError: nil can\'t be coerced into Integer

Method 2:

   [24] pry(main)> [].inject(:+)
   => nil
   [25] pry(main)> [].inject(0, :+)
   => 0
   [4] pry(main)> [1,2,3,4,5].inject(0, :+)
   => 15
   [5] pry(main)> [1,2,3,4,nil].inject(0, :+)
   TypeError: nil can\'t be coerced into Integer
   from (pry):5:in `+\'

Method 3:

   [6] pry(main)> [1,2,3].reduce(:+)
   => 6
   [9] pry(main)> [].reduce(:+)
   => nil
   [7] pry(main)> [1,2,nil].reduce(:+)
   TypeError: nil can\'t be coerced into Integer
   from (pry):7:in `+\'

Method 4: When Array contains an nil and empty values, by default if you use any above functions reduce, sum, inject everything will through the

TypeError: nil can\'t be coerced into Integer

You can overcome this by,

   [16] pry(main)> sum = 0 
   => 0
   [17] pry(main)> [1,2,3,4,nil, \'\'].each{|a| sum+= a.to_i }
   => [1, 2, 3, 4, nil, \"\"]
   [18] pry(main)> sum
   => 10

Method 6: eval

Evaluates the Ruby expression(s) in string.

  [26] pry(main)> a = [1,3,4,5]
  => [1, 3, 4, 5]
  [27] pry(main)> eval a.join \'+\'
  => 13
  [30] pry(main)> a = [1,3,4,5, nil]
  => [1, 3, 4, 5, nil]
  [31] pry(main)> eval a.join \'+\'
  SyntaxError: (eval):1: syntax error, unexpected end-of-input
  1+3+4+5+

回答17:

If you feel golfy, you can do

eval([123,321,12389]*?+)

This will create a string \"123+321+12389\" and then use function eval to do the sum. This is only for golfing purpose, you should not use it in proper code.

回答18:

You could also use recursion

def sum(array)
  array.length == 1 ? array.pop() : array.pop() + sum(array)
end

if you don\'t want to be destructive, make a clone.

回答19:

Or you can try this method:

def sum arr
  0 if arr.empty
  arr.inject :+
end

回答20:

This is the shortest way. Try it.

array.inject :+

回答21:

You can also do it in easy way

def sum(numbers)
  return 0 if numbers.length < 1
  result = 0
  numbers.each { |num| result += num }
  result
end

回答22:

You can use .map and .sum like:

array.map { |e| e }.sum