AutoMapper Dictionary Flattening

问题:

I've got a Dictionary<User, bool>

User is as follows:

 public class User {
   public string Username { get; set; }
   public string Avatar { get; set;
}

The second type, bool, indicates whether this user is a friend of the logged in User. I want to flatten this Dictionary into a List<UserDto> UserDto is defined as:

public class UserDto {
   public string Username { get; set; }
   public string Avatar { get; set; }
   public bool IsFriend { get; set; }
}

IsFriend represents the value of the dictionary.

How can I do this?

回答1:

You should be able to do this with just one mapping¹:

You need to map a KeyValuePair<User, bool> to UserDto. This is necessary for AutoMapper to be able to map the contents of the dictionary to the contents of the List<T> we're ultimately creating (more of an explanation can be found in this answer).

Mapper.CreateMap<KeyValuePair<User, bool>, UserDto>()
    .ForMember(dest => dest.Username, opt => opt.MapFrom(src => src.Key.UserName))
    .ForMember(dest => dest.Avatar, opt => opt.MapFrom(src => src.Key.Avatar))
    .ForMember(dest => dest.IsFriend, opt => opt.MapFrom(src => src.Value));

Then, use the mapping in your .Map call:

Mapper.Map<Dictionary<User, bool>, List<UserDto>>(...);

You don't need to map the collections themselves, as AutoMapper can handle mapping the Dictionary to a List as long as you've mapped the contents of the collections to each other (in our case, KeyValuePair<User, bool> to UserDto).

---

Edit: Here's another solution that doesn't require mapping every User property to UserDto:

Mapper.CreateMap<User, UserDto>();
Mapper.CreateMap<KeyValuePair<User, bool>, UserDto>()
    .ConstructUsing(src => Mapper.Map<User, UserDto>(src.Key))
    .ForMember(dest => dest.IsFriend, opt => opt.MapFrom(src => src.Value));

¹_{Using AutoMapper 2.0}

回答2:

I know I am late to the game, yet this seems to be a more generic solution for mapping a dictionary to a .Net type(simple) using automapper

public static IMappingExpression<Dictionary<string, string>, TDestination> ConvertFromDictionary<TDestination>(
        this IMappingExpression<Dictionary<string, string>, TDestination> exp)
{
    foreach (PropertyInfo pi in typeof(TDestination).GetProperties(BindingFlags.Instance | BindingFlags.Public | BindingFlags.NonPublic))
    {
        exp.ForMember(propertyName, cfg => cfg.MapFrom(r => r[propertyName]));
    }
    return exp;
}

Use it like this

Mapper.CreateMap<Dictionary<string, string>, TDestination>().ConvertFromDictionary();

where TDestination can a .NET simple type. For complex types, you could supply a Func/Action delegate and map using that function.(Inside the above for-each)

Eg.

if (customPropNameMapFunc != null && !string.IsNullOrEmpty(customPropNameMapFunc(propertyName)))
{
   exp.ForMember(propertyName, cfg => cfg.MapFrom(r => r[customPropNameMapFunc(propertyName)]));
}

回答3:

For something simple like this, a quick LINQ query will do. Assuming dict is your Dictionary<User,bool>:

var conv = from kvp in dict
            select new UserDto
                    {
                        Avatar = kvp.Key.Avatar,
                        IsFriend = kvp.Value,
                        Username = kvp.Key.Username
                    };